
底円の半径が3で高さが2の円柱があるとします。2つの底円に重なるABCD
ようにA, B
正方形を描くにはどうしたらよいでしょうか。私は試してみました。C, D
\documentclass[border=2mm,12pt,tikz]{standalone}
\usepackage{tikz-3dplot}
\usetikzlibrary{3d,calc,backgrounds,patterns}
\begin{document}
\pgfmathsetmacro{\myr}{3}
\pgfmathsetmacro{\h}{2}
\def\angB{0}
\def\phi{120}
\def\angA{{\angB + \phi}}
\def\angC{\phi - 180}
\tdplotsetmaincoords{65}{100}
\begin{tikzpicture}[tdplot_main_coords,scale=1,line cap=butt,line join=round]
\begin{scope}[canvas is xy plane at z=0]
\draw[dashed] (\tdplotmainphi:\myr) arc(\tdplotmainphi:\tdplotmainphi+180:\myr);
\coordinate (O) at (0,0);
\coordinate (A) at (\angA:\myr);
\coordinate (B) at (\angB:\myr);
\draw[thick] (\tdplotmainphi:\myr) coordinate(BR) arc(\tdplotmainphi:\tdplotmainphi-180:\myr)
coordinate(BL);
\end{scope}
\begin{scope}[canvas is xy plane at z=\h]
\coordinate (O') at (0,0);
\coordinate (C) at (\angC:\myr);
\coordinate (D) at ($ (A) + (C) -(B) $);
\draw[thick] (O') circle[radius=\myr];
\draw [thick](BR) -- (\tdplotmainphi:\myr) (BL) -- (\tdplotmainphi-180:\myr);
\end{scope}
\fill (A) circle[radius=1pt] node[above] {$A$};
\fill (B) circle[radius=1pt] node[above] {$B$};
\fill (C) circle[radius=1pt] node[above] {$C$};
\fill (D) circle[radius=1pt] node[above] {$D$};
\draw[dashed] (C) -- (B) -- (A) -- (D) ;
\draw[] (C) -- (D);
\end{tikzpicture}
\end{document}
\def\angB{0}
このコードは、に変更すると true になりません\def\angB{30}
。一般的な方法を取得するにはどうすればよいでしょうか?
答え1
正方形上の3点、 、 を考えてみましょうB
。C
一般D
性を失うことなく、これらの点の座標が次の通りであると仮定できます。
C = (r \cos \phi,r \sin\phi,h)
D = (r \cos (180-\phi),r \sin(180-\phi),h)
B = (r \cos \phi,-r \sin\phi,0)
正方形を形成する条件は、
CD = BC
どこ
CD = 2r \cos \phi
BC = \sqrt{(2r \sin\phi)^2+h^2}
これにより
\phi = \acos(h^2/(4r^2))/2
これは hpechristiansens の数値結果を裏付けます。
CD = 2 r \cos \left(\frac{1}{2} \acos\left(\frac{h^2}{4 r^2}\right)\right)
ムウェ
\documentclass[border=2mm,12pt,tikz]{standalone}
\usepackage{tikz-3dplot}
\usetikzlibrary{3d,calc,backgrounds,patterns}
\begin{document}
\pgfmathsetmacro{\myr}{3}
\pgfmathsetmacro{\h}{2}
\pgfmathsetmacro{\angA}{acos(\h*\h/(4*\myr*\myr))/2}
\tdplotsetmaincoords{65}{100}
\begin{tikzpicture}[tdplot_main_coords,scale=1,line cap=butt,line join=round]
\begin{scope}[canvas is xy plane at z=0]
\draw[dashed] (\tdplotmainphi:\myr) arc(\tdplotmainphi:\tdplotmainphi+180:\myr);
\coordinate (O) at (0,0);
\coordinate (A) at (\angA:\myr);
\coordinate (B) at (180-\angA:\myr);
\draw[thick] (\tdplotmainphi:\myr) coordinate(BR) arc(\tdplotmainphi:\tdplotmainphi-180:\myr)
coordinate(BL);
\end{scope}
\begin{scope}[canvas is xy plane at z=\h]
\coordinate (O') at (0,0);
\coordinate (C) at (-180+\angA:\myr);
\coordinate (D) at (-\angA:\myr);
\draw[thick] (O') circle[radius=\myr];
\draw [thick](BR) -- (\tdplotmainphi:\myr) (BL) -- (\tdplotmainphi-180:\myr);
\end{scope}
\fill (A) circle[radius=1pt] node[above] {$A$};
\fill (B) circle[radius=1pt] node[above] {$B$};
\fill (C) circle[radius=1pt] node[above] {$C$};
\fill (D) circle[radius=1pt] node[above] {$D$};
\draw[dashed] (C) -- (B) -- (A);
\draw[thick] (A) -- (D) -- (C);
\end{tikzpicture}
\end{document}
答え2
このコードでは、点はB
円上のどこにでも移動できます。 で変更する\def\angB{-20}
と、正方形 のオプションが利用できるようになりますABCD
。
\documentclass[border=2mm,12pt,tikz]{standalone}
\usepackage{tikz-3dplot}
\usetikzlibrary{3d,calc,backgrounds,patterns}
\usepackage{fouriernc}
\begin{document}
\pgfmathsetmacro{\myr}{3}
\pgfmathsetmacro{\h}{2}
\pgfmathsetmacro{\d}{sqrt(\h*\h+4*\myr*\myr)/sqrt(2)}
\def\angB{-20}
\def\angA{{\angB + acos((2*\myr*\myr-\d*\d)/(2*\myr*\myr)}}
\tdplotsetmaincoords{65}{100}
\begin{tikzpicture}[tdplot_main_coords,scale=1,line cap=butt,line join=round]
\begin{scope}[canvas is xy plane at z=0]
\draw[dashed] (\tdplotmainphi:\myr) arc(\tdplotmainphi:\tdplotmainphi+180:\myr);
\coordinate (O) at (0,0);
\coordinate (A) at (\angA:\myr);
\coordinate (B) at (\angB:\myr);
\coordinate (A') at ($ 2*(O) - (A) $);
\coordinate (B') at ($ 2*(O) - (B) $);
\draw[thick] (\tdplotmainphi:\myr) coordinate(BR) arc(\tdplotmainphi:\tdplotmainphi-180:\myr)
coordinate(BL);
\end{scope}
\begin{scope}[canvas is xy plane at z=\h]
\coordinate (O') at (0,0);
\coordinate (C) at ($ (O') - (O) +(A')$);
\coordinate (D) at ($ (O') - (O) +(B')$);
\draw[thick] (O') circle[radius=\myr];
\draw [thick](BR) -- (\tdplotmainphi:\myr) (BL) -- (\tdplotmainphi-180:\myr);
\end{scope}
\foreach \v/\position in { B/below,O/below,A/below,B'/above,A'/above,C/above,D/above} {\draw[draw =black, fill=black] (\v) circle (1pt) node [\position=0.2mm] {$\v$};
}
\draw[thick] (C) -- (D) ;
\draw[dashed] (A) -- (A') (B) -- (B') (A) -- (B) -- (A') -- (B') -- cycle (B') -- (D) (A') -- (C) (A) -- (D) (B) -- (C);
\end{tikzpicture}
\end{document}
いくつかの計算を使用してメープル点の座標はA, B, C, D
選択できる
そして、コード
\documentclass[border=2mm,12pt,tikz]{standalone}
\usepackage{tikz-3dplot}
\begin{document}
\pgfmathsetmacro{\myr}{3}
\pgfmathsetmacro{\h}{2}
\tdplotsetmaincoords{65}{100}
\begin{tikzpicture}[tdplot_main_coords,scale=1,line cap=butt,line join=round]
\begin{scope}[canvas is xy plane at z=0]
\draw[dashed] (\tdplotmainphi:\myr) arc(\tdplotmainphi:\tdplotmainphi+180:\myr);
\coordinate (O) at (0,0);
\coordinate (A) at ({1/4*sqrt(8*\myr*\myr-2*\h*\h)}, {sqrt(1/2*\myr*\myr+(1/8)*\h*\h)});
\coordinate (B) at ({1/4*sqrt(8*\myr*\myr-2*\h*\h)}, -{sqrt(1/2*\myr*\myr+(1/8)*\h*\h)});
\draw[thick] (\tdplotmainphi:\myr) coordinate(BR) arc(\tdplotmainphi:\tdplotmainphi-180:\myr)
coordinate(BL);
\end{scope}
\begin{scope}[canvas is xy plane at z=\h]
\coordinate (O') at (0,0);
\coordinate (C) at ({-1/4*sqrt(8*\myr*\myr-2*\h*\h)}, -{sqrt(1/2*\myr*\myr+(1/8)*\h*\h)});
\coordinate (D) at ({-1/4*sqrt(8*\myr*\myr-2*\h*\h)}, {sqrt(1/2*\myr*\myr+(1/8)*\h*\h)});
\draw[thick] (O') circle[radius=\myr];
\draw [thick](BR) -- (\tdplotmainphi:\myr) (BL) -- (\tdplotmainphi-180:\myr);
\end{scope}
\foreach \v/\position in { B/below,O/below,A/below,C/above,D/above} {\draw[draw =black, fill=black] (\v) circle (1pt) node [\position=0.2mm] {$\v$};
}
\draw[thick] (C) -- (D) ;
\draw[dashed] (C) -- (B) -- (A) -- (D) ;
\end{tikzpicture}
\end{document}