\documentclass[aspectratio=1610]{beamer}
\usepackage{amsmath}
\begin{document}
\def\function(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
\pgfmathparse{3+\function(1)}
\let\z\pgfmathresult
z result is \z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
\def\myfp(#1,#2){\pgfmathparse{#1} \let\#2\pgfmathresult}
\myfp(3+ \function(1),\z)
% /This yields the right answer BUT z Result is \z ..... Yields error
%3. Why does the following mess up%
\let\z7\pgfmathresult
z7 result is {\z7}
%4. PLEASE point me to relevant documentation!
\end{document}
Antwort1
Ich bin mir nicht sicher, ob ich die Frage verstehe. Wenn Sie jedoch ein Makro aufrufen möchten, \z7funktioniert dies nicht, da Makronamen keine Zahlen enthalten dürfen. Und ich musste einen Backslash entfernen, um zu gelangen
\documentclass[aspectratio=1610]{beamer}
\usepackage{amsmath}
\begin{document}
\def\function(#1){ 96* (#1)-16 *(#1)^2 }
%1. I am trying to condense the following two lines
\pgfmathparse{3+\function(1)}
\let\z\pgfmathresult
z result is \z %
%2. I would like store the result of the previous line in a 'variable'
%The following doesn't work
\def\myfp(#1,#2){\pgfmathparse{#1} \let#2\pgfmathresult} % <removed \ before #2
\myfp(3+ \function(1),\z)
% /This yields the right answer BUT z Result is \z ..... Yields error
%3. Why does the following mess up%
%\pgfmathparse{\z*7}
\let\zseven\pgfmathresult
z7 result is {\zseven}
%4. PLEASE point me to relevant documentation!
\end{document}
