Wie zeichne ich mit Tikz das folgende schematische Diagramm?

Question

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{shapes,arrows}
\begin{document}
\tikzstyle{block} = [draw, fill=white, rectangle, 
    minimum height=3em, minimum width=6em]
\tikzstyle{sum} = [draw, fill=white, rectangle, node distance=1cm]
\tikzstyle{input} = [coordinate]
\tikzstyle{output} = [coordinate]

\begin{tikzpicture}[auto, node distance=2cm,>=latex']
\node [input, name=input] {};
\node [sum, right of=input] (sum) {S};
\node [block, right of=S] (E) {E};
\node [block, right of=E] (I) {I};
\node [block, above of=I] (J) {J};
\node [block, below of=J] (T) {T};

\node [output, below of=S] (output) {};
\node [output, below of=E] (output) {};
\node [output, below of=I] (output) {};
\node [output, right of=J] (output) {};
\node [output, right of=T] (output) {};

\draw [draw,->] (input) -- node {$A$} (S);
\draw [draw,->] (input) -- node {$\Lambda$} (S);
\draw [->] (S) -- node[name=$m \beta \left( \frac{I+l J}{N}  \right)$] {$m \beta \left( \frac{I+l J}{N}  \right)$} (E);
\draw [->] (S) -- node[name=$(1-m) \beta \left( \frac{I+l J}{N}  \right)$] {$m \beta \left( \frac{I+l J}{N}  \right)$} (I);
\draw [->] (E) -- node[name=k] {$k$} (I);
\draw [->] (I) -- node[name=n] {$k$} (J);
\draw [->] (I) -- node[name=$r_1$] {$r_1$} (T);
\draw [->] (J) -- node[name=$r_2$] {$r_2$} (T);
\draw [->] (T) -- node[name=$q\delta$] {$q\delta$} (E);
\draw [->] (T) -- node[name=$(1-q)\delta$] {$q\delta$} (S);

\draw [->] (s) -- node [name=$\mu$] {$\mu$}(output);
\draw [->] (E) -- node [name=$\mu$] {$\mu$}(output);
\draw [->] (I) -- node [name=$\mu+d_1$] {$\mu$}(output);
\draw [->] (J) -- node [name=$\mu+d_2$] {$\mu$}(output);
\draw [->] (T) -- node [name=$\mu$] {$\mu$}(output);

\end{tikzpicture}
\end{document}

Answer 1

Nach einigem Unkrautjäten komme ich zu

\documentclass[tikz,border=3.14mm]{standalone}
\usetikzlibrary{positioning}
\begin{document}

\begin{tikzpicture}[auto, node distance=2cm,>=latex,block/.style={draw, fill=white, rectangle, 
    minimum height=3em, minimum width=6em}]
 \node[block] (S) {S};
 \node[block, right=of S] (E) {E};
 \node[block, right=of E] (I) {I};
 \node[block, above right=of I] (J) {J};
 \node[block, below right=of I] (T) {T};
 %
 \draw[->] (S) -- ++ (0,2) -| node[pos=0.25,above]{$(1-m) \beta \left( \frac{I+l J}{N}  \right)$} (I); 
 \draw[->] (S) -- node[pos=0.5,below]{$m \beta \left( \frac{I+l J}{N}\right)$}(E);
 \draw[->] (E) -- node[pos=0.5,above]{$k$} (I);
 \draw[->] (E.90) -- ++ (0,0.5) node[right] {$\mu$};
 \draw[->] (I.20) -- node[pos=0.5,above,sloped] {$n$} (J.180);
 \draw[->] (I.-20) -- node[pos=0.5,below,sloped] {$r_1$} (T.180);
 \draw[->] (J) -- node[pos=0.5,right] {$r_2$} (T);
 \draw[->] (T.-135) -- ++ (0,-1) -| node[pos=0.25] {$q\delta$} (E);
 \draw[->] (T.-45) -- ++ (0,-2) -| node[pos=0.25] {$(1-q)\delta$} (S.-45);
 \draw[->] (S.-135) -- ++ (0,-1) node[below]{$\mu$};
 \draw[<-] (S.160) -- ++ (-1,0) node[left] {$\Lambda$};
 \draw[<-] (S.200) -- ++ (-1,0) node[left] {$A$};
 \draw[->] (T.0) -- ++ (1,0) node[right]{$\mu$};
 \draw[->] (J.0) -- ++ (1,0) node[right]{$\mu+d_2$};
\end{tikzpicture}
\end{document}

Notiz:

1. \tikzstyleist veraltet.
2. Dies gilt auch für die Pfeilbibliothek.
3. Und die Positionierungssyntax, die Sie verwendet haben.
4. Sie können Knoten nicht einNamedas ist eine Formel.
5. Es ist nicht besonders sinnvoll, verschiedenen Knoten dieselben Namen zu geben.
6. Dieser Code kann noch weiter optimiert werden. Es handelt sich um einen Kompromiss zwischen Eleganz und großer Deutlichkeit und damit besserer Verständlichkeit.