Ansatz 1

Question

ich benutzeMathematicaund der Befehl TeXFormzum Konvertieren der Gleichung. Das Array ist zu lang. Ich versuche, einen Weg zu finden, aber ich kann diese Gleichung nicht ausrichten. Wie kann ich das machen?

\documentclass[12pt,a4paper]{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{fourier}
\usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]{geometry}
\begin{document}
\[\left(
\begin{array}{ccc}
 \{-7,-2,2\} & \{-5,8,0\} &\{-3,-6,4\} \\
 \{-7,-2,2\} & \{-3,-6,4\} &\{7,-4,6\} \\
 \{-7,-2,2\} & \{-3,6,10\} &\{4,8,9\} \\
 \{-7,-2,4\} & \{-5,8,6\} & \{-3,-6,2\} \\
 \{-7,-2,4\} & \{-3,-6,2\} &\{7,-4,0\} \\
 \{-7,3,-1\} & \{-3,-5,7\} &\{4,-4,9\} \\
 \{-7,3,7\} & \{-3,-5,-1\} &\{-2,8,9\} \\
 \{-7,6,2\} & \{-5,-4,0\} &\{-3,10,4\} \\
 \{-7,6,2\} & \{-3,-2,10\} &\{4,-4,9\} \\
 \{-7,6,4\} & \{-3,10,2\} &\{7,8,0\} \\
 \{-6,-2,-1\} & \{2,6,-5\} &\{7,8,0\} \\
 \{-6,-2,7\} & \{-5,-4,0\} &\{2,6,11\} \\
 \{-6,6,-1\} & \{2,-2,-5\} &\{7,-4,0\} \\
 \{-6,6,7\} & \{-5,8,0\} &\{2,-2,11\} \\
 \{-5,-4,0\} & \{5,-6,2\} &\{9,-2,4\} \\
 \{-5,-4,6\} & \{-3,1,11\} &\{5,9,7\} \\
 \{-5,-4,6\} & \{5,-6,4\} & \{9,-2,2\} \\
 \{-5,-1,9\} & \{-3,-6,4\} &\{5,-2,-4\} \\
 \{-5,5,-3\} & \{0,10,-1\} &\{8,6,7\} \\
 \{-5,5,9\} & \{0,10,7\} &\{8,6,-1\} \\
 \{-5,8,0\} & \{-3,9,7\} &\{5,1,11\} \\
 \{-5,8,0\} & \{5,10,2\} & \{9,6,4\} \\
 \{-3,-2,-4\} & \{5,-6,4\} &\{7,-1,9\} \\
 \{-3,1,-5\} & \{5,9,-1\} &\{7,8,6\} \\
 \{-3,9,-1\} & \{5,1,-5\} &\{7,-4,0\} \\
 \{-2,-4,-3\} & \{0,6,-5\} &\{2,10,-1\} \\
 \{-2,-4,-3\} & \{5,-5,-1\} &\{9,3,7\} \\
 \{-2,-4,9\} & \{0,6,11\} &\{2,10,7\} \\
 \{-2,8,-3\} & \{0,10,7\} &\{2,6,11\} \\
 \{-2,8,9\} & \{0,10,-1\} &\{2,6,-5\} \\
 \{0,-6,-1\} & \{2,-2,-5\} & \{4,8,-3\} \\
 \{0,-6,7\} & \{2,-2,11\} &\{4,8,9\} \\
 \{0,-2,-5\} & \{2,-6,-1\} &\{4,-4,9\} \\
 \{0,-2,11\} & \{2,-6,7\} &\{4,-4,-3\} \\
 \{0,6,-5\} & \{2,10,-1\} & \{4,8,9\} \\
 \{0,6,11\} & \{2,10,7\} & \{4,8,-3\} \\
 \{0,10,-1\} & \{2,6,-5\} & \{4,-4,-3\} \\
 \{0,10,7\} & \{2,6,11\} & \{4,-4,9\} \\
 \{4,-4,-3\} & \{5,6,10\} & \{9,-2,2\} \\
 \{4,8,-3\} & \{5,-5,7\} &\{9,3,-1\} \\
 \{4,8,-3\} & \{5,-2,10\} & \{9,6,2\} \\
 \{5,-6,2\} & \{7,8,6\} &\{9,-2,4\} \\
 \{5,-6,4\} & \{7,8,0\} &\{9,-2,2\} \\
\{5,10,4\} & \{7,-4,0\} &\{9,6,2\} \\
 \{0,10,7\} & \{2,6,11\} & \{4,-4,9\} \\
 \{4,-4,-3\} & \{5,6,10\} & \{9,-2,2\} \\
 \{4,8,-3\} & \{5,-5,7\} & \{9,3,-1\} \\
 \{4,8,-3\} & \{5,-2,10\} &\{9,6,2\} \\
 \{5,-6,2\} & \{7,8,6\} & \{9,-2,4\} \\
 \{5,-6,4\} & \{7,8,0\} &\{9,-2,2\} \\
 \{5,10,4\} & \{7,-4,0\} &\{9,6,2\}
\end{array}
\right)\]
\end{document}

Answer 1

\documentclass[12pt,a4paper]{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{fourier}
\usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]{geometry}
\begin{document}
\small\[
\left(\begin{array}{*{3}{r@{,}r@{,}r}}
 \{-7&-2&2\} & \{-5&8&0\} &\{-3&-6&4\} \\
 \{-7&-2&2\} & \{-3&-6&4\} &\{7&-4&6\} \\
 \{-7&-2&2\} & \{-3&6&10\} &\{4&8&9\} \\
 \{-7&-2&4\} & \{-5&8&6\} & \{-3&-6&2\} \\
 \{-7&-2&4\} & \{-3&-6&2\} &\{7&-4&0\} \\
 \{-7&3&-1\} & \{-3&-5&7\} &\{4&-4&9\} \\
 \{-7&3&7\} & \{-3&-5&-1\} &\{-2&8&9\} \\
 \{-7&6&2\} & \{-5&-4&0\} &\{-3&10&4\} \\
 \{-7&6&2\} & \{-3&-2&10\} &\{4&-4&9\} \\
 \{-7&6&4\} & \{-3&10&2\} &\{7&8&0\} \\
 \{-6&-2&-1\} & \{2&6&-5\} &\{7&8&0\} \\
 \{-6&-2&7\} & \{-5&-4&0\} &\{2&6&11\} \\
 \{-6&6&-1\} & \{2&-2&-5\} &\{7&-4&0\} \\
 \{-6&6&7\} & \{-5&8&0\} &\{2&-2&11\} \\
 \{-5&-4&0\} & \{5&-6&2\} &\{9&-2&4\} \\
 \{-5&-4&6\} & \{-3&1&11\} &\{5&9&7\} \\
 \{-5&-4&6\} & \{5&-6&4\} & \{9&-2&2\} \\
 \{-5&-1&9\} & \{-3&-6&4\} &\{5&-2&-4\} \\
 \{-5&5&-3\} & \{0&10&-1\} &\{8&6&7\} \\
 \{-5&5&9\} & \{0&10&7\} &\{8&6&-1\} \\
 \{-5&8&0\} & \{-3&9&7\} &\{5&1&11\} \\
 \{-5&8&0\} & \{5&10&2\} & \{9&6&4\} \\
 \{-3&-2&-4\} & \{5&-6&4\} &\{7&-1&9\} \\
 \{-3&1&-5\} & \{5&9&-1\} &\{7&8&6\} \\
 \{-3&9&-1\} & \{5&1&-5\} &\{7&-4&0\} \\
 \{-2&-4&-3\} & \{0&6&-5\} &\{2&10&-1\} \\
 \{-2&-4&-3\} & \{5&-5&-1\} &\{9&3&7\} \\
 \{-2&-4&9\} & \{0&6&11\} &\{2&10&7\} \\
 \{-2&8&-3\} & \{0&10&7\} &\{2&6&11\} \\
 \{-2&8&9\} & \{0&10&-1\} &\{2&6&-5\} \\
 \{0&-6&-1\} & \{2&-2&-5\} & \{4&8&-3\} \\
 \{0&-6&7\} & \{2&-2&11\} &\{4&8&9\} \\
 \{0&-2&-5\} & \{2&-6&-1\} &\{4&-4&9\} \\
 \{0&-2&11\} & \{2&-6&7\} &\{4&-4&-3\} \\
 \{0&6&-5\} & \{2&10&-1\} & \{4&8&9\} \\
 \{0&6&11\} & \{2&10&7\} & \{4&8&-3\} \\
 \{0&10&-1\} & \{2&6&-5\} & \{4&-4&-3\} \\
 \{0&10&7\} & \{2&6&11\} & \{4&-4&9\} \\
 \{4&-4&-3\} & \{5&6&10\} & \{9&-2&2\} \\
 \{4&8&-3\} & \{5&-5&7\} &\{9&3&-1\} \\
 \{4&8&-3\} & \{5&-2&10\} & \{9&6&2\} \\
 \{5&-6&2\} & \{7&8&6\} &\{9&-2&4\} \\
 \{5&-6&4\} & \{7&8&0\} &\{9&-2&2\} \\
\{5&10&4\} & \{7&-4&0\} &\{9&6&2\} \\
 \{0&10&7\} & \{2&6&11\} & \{4&-4&9\} \\
 \{4&-4&-3\} & \{5&6&10\} & \{9&-2&2\} \\
 \{4&8&-3\} & \{5&-5&7\} & \{9&3&-1\} \\
 \{4&8&-3\} & \{5&-2&10\} &\{9&6&2\} \\
 \{5&-6&2\} & \{7&8&6\} & \{9&-2&4\} \\
 \{5&-6&4\} & \{7&8&0\} &\{9&-2&2\} \\
 \{5&10&4\} & \{7&-4&0\} &\{9&6&2\}
\end{array}\right)\]
\end{document}

Answer 2

Hier sind zwei Ansätze, je nach Ihren Anforderungen. Jeder erfordert eine manuelle Bearbeitung der Ausgabe. Ergebnisse und vollständiger Code werden unten angezeigt.

Ansatz 1

Da der gesamte Ausdruck in Klammern steht, gibt es hierfür keine Standardmethode. Ich schlage vor, Sie beschreiben die Matrix wie folgt:

X = ( X_1 )
    ( X_2 )

wobei X_1 und X_2 kleinere Untermatrizen sind, die in den verfügbaren Platz passen. Fügen Sie nun X_1 =vor dem \left(\begin{array}und dem ein

\end{array}\right)\]
and 
\[ X_2 = \left(
\begin{array}{ccc}

an einer für den Seitenumbruch geeigneten Stelle.

(Eine Alternative wäre, die Definitionen von X_1 und X_2 in schwebende Umgebungen wie zu setzen tableund auf diese zu verweisen table. Dann müssten Sie nur sicherstellen, dass jedes X_i kleiner als eine Seite ist.)

Ansatz 2

Wenn die Klammern nicht wichtig sind, können Sie entweder das longtablePaket oder verwenden mdframed. In keinem Fall müssen Sie den Seitenumbruch manuell auswählen. Hier ist ein mdframedAnsatz. Ersetzen Sie \[\left(\array{ccc}' and\end{array}\right)]` durch

\begin{mdframed}[hidealllines=true]
\allowdisplaybreaks 
\begin{align*}

Und

\end{align*}
\end{mdframed}

und ersetzen Sie jedes &durch &&.

Ergebnis von Ansatz 1

Ergebnis von Ansatz 2

Code für Ansatz 1

\documentclass[12pt,a4paper]{article}

\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{fourier}
\usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]{geometry}

\usepackage{lipsum}% for dummy text

\begin{document}

\lipsum[1-2]

\begin{equation*}
  X =
  \begin{pmatrix}
    X_1 \\ X_2
  \end{pmatrix}
  ,
\end{equation*}
where
\[
X_1 = 
\left(
\begin{array}{ccc}
 \{-7,-2,2\} & \{-5,8,0\} &\{-3,-6,4\} \\
 \{-7,-2,2\} & \{-3,-6,4\} &\{7,-4,6\} \\
 \{-7,-2,2\} & \{-3,6,10\} &\{4,8,9\} \\
 \{-7,-2,4\} & \{-5,8,6\} & \{-3,-6,2\} \\
 \{-7,-2,4\} & \{-3,-6,2\} &\{7,-4,0\} \\
 \{-7,3,-1\} & \{-3,-5,7\} &\{4,-4,9\} \\
 \{-7,3,7\} & \{-3,-5,-1\} &\{-2,8,9\} \\
 \{-7,6,2\} & \{-5,-4,0\} &\{-3,10,4\} \\
 \{-7,6,2\} & \{-3,-2,10\} &\{4,-4,9\} \\
 \{-7,6,4\} & \{-3,10,2\} &\{7,8,0\} \\
 \{-6,-2,-1\} & \{2,6,-5\} &\{7,8,0\} \\
 \{-6,-2,7\} & \{-5,-4,0\} &\{2,6,11\} \\
 \{-6,6,-1\} & \{2,-2,-5\} &\{7,-4,0\} \\
 \{-6,6,7\} & \{-5,8,0\} &\{2,-2,11\} \\
 \{-5,-4,0\} & \{5,-6,2\} &\{9,-2,4\} \\
 \{-5,-4,6\} & \{-3,1,11\} &\{5,9,7\} \\
 \{-5,-4,6\} & \{5,-6,4\} & \{9,-2,2\} \\
 \{-5,-1,9\} & \{-3,-6,4\} &\{5,-2,-4\} \\
 \{-5,5,-3\} & \{0,10,-1\} &\{8,6,7\} \\
 \{-5,5,9\} & \{0,10,7\} &\{8,6,-1\} \\
 \{-5,8,0\} & \{-3,9,7\} &\{5,1,11\} \\
 \{-5,8,0\} & \{5,10,2\} & \{9,6,4\} \\
 \{-3,-2,-4\} & \{5,-6,4\} &\{7,-1,9\} \\
 \{-3,1,-5\} & \{5,9,-1\} &\{7,8,6\} \\
 \{-3,9,-1\} & \{5,1,-5\} &\{7,-4,0\} \\
 \{-2,-4,-3\} & \{0,6,-5\} &\{2,10,-1\}\\
\{-2,-4,-3\} & \{5,-5,-1\} &\{9,3,7\} \\
 \{-2,-4,9\} & \{0,6,11\} &\{2,10,7\} \\
 \{-2,8,-3\} & \{0,10,7\} &\{2,6,11\} \\
 \{-2,8,9\} & \{0,10,-1\} &\{2,6,-5\} \\
 \{0,-6,-1\} & \{2,-2,-5\} & \{4,8,-3\} \\
\end{array}\right)\]
and 
\[ X_2 = \left(
\begin{array}{ccc}
 \{0,-6,7\} & \{2,-2,11\} &\{4,8,9\} \\
 \{0,-2,-5\} & \{2,-6,-1\} &\{4,-4,9\} \\
 \{0,-2,11\} & \{2,-6,7\} &\{4,-4,-3\} \\
 \{0,6,-5\} & \{2,10,-1\} & \{4,8,9\} \\
 \{0,6,11\} & \{2,10,7\} & \{4,8,-3\} \\
 \{0,10,-1\} & \{2,6,-5\} & \{4,-4,-3\} \\
 \{0,10,7\} & \{2,6,11\} & \{4,-4,9\} \\
 \{4,-4,-3\} & \{5,6,10\} & \{9,-2,2\} \\
 \{4,8,-3\} & \{5,-5,7\} &\{9,3,-1\} \\
 \{4,8,-3\} & \{5,-2,10\} & \{9,6,2\} \\
 \{5,-6,2\} & \{7,8,6\} &\{9,-2,4\} \\
 \{5,-6,4\} & \{7,8,0\} &\{9,-2,2\} \\
\{5,10,4\} & \{7,-4,0\} &\{9,6,2\} \\
 \{0,10,7\} & \{2,6,11\} & \{4,-4,9\} \\
 \{4,-4,-3\} & \{5,6,10\} & \{9,-2,2\} \\
 \{4,8,-3\} & \{5,-5,7\} & \{9,3,-1\} \\
 \{4,8,-3\} & \{5,-2,10\} &\{9,6,2\} \\
 \{5,-6,2\} & \{7,8,6\} & \{9,-2,4\} \\
 \{5,-6,4\} & \{7,8,0\} &\{9,-2,2\} \\
 \{5,10,4\} & \{7,-4,0\} &\{9,6,2\}
\end{array}
\right)\]
\end{document}

Code für Ansatz 2

\documentclass[12pt,a4paper]{article}

\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{fourier}
\usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]{geometry}

\usepackage[tikz]{mdframed}

\usepackage{lipsum}% for dummy text

\begin{document}

\lipsum[1-2]

\begin{mdframed}[hidealllines=true]
\allowdisplaybreaks 
\begin{align*}
  \{-7,-2,2\} && \{-5,8,0\} &&\{-3,-6,4\} \\
  \{-7,-2,2\} && \{-3,-6,4\} &&\{7,-4,6\} \\
  \{-7,-2,2\} && \{-3,6,10\} &&\{4,8,9\} \\
  \{-7,-2,4\} && \{-5,8,6\} && \{-3,-6,2\} \\
  \{-7,-2,4\} && \{-3,-6,2\} &&\{7,-4,0\} \\
  \{-7,3,-1\} && \{-3,-5,7\} &&\{4,-4,9\} \\
  \{-7,3,7\} && \{-3,-5,-1\} &&\{-2,8,9\} \\
  \{-7,6,2\} && \{-5,-4,0\} &&\{-3,10,4\} \\
  \{-7,6,2\} && \{-3,-2,10\} &&\{4,-4,9\} \\
  \{-7,6,4\} && \{-3,10,2\} &&\{7,8,0\} \\
  \{-6,-2,-1\} && \{2,6,-5\} &&\{7,8,0\} \\
  \{-6,-2,7\} && \{-5,-4,0\} &&\{2,6,11\} \\
  \{-6,6,-1\} && \{2,-2,-5\} &&\{7,-4,0\} \\
  \{-6,6,7\} && \{-5,8,0\} &&\{2,-2,11\} \\
  \{-5,-4,0\} && \{5,-6,2\} &&\{9,-2,4\} \\
  \{-5,-4,6\} && \{-3,1,11\} &&\{5,9,7\} \\
  \{-5,-4,6\} && \{5,-6,4\} && \{9,-2,2\} \\
  \{-5,-1,9\} && \{-3,-6,4\} &&\{5,-2,-4\} \\
  \{-5,5,-3\} && \{0,10,-1\} &&\{8,6,7\} \\
  \{-5,5,9\} && \{0,10,7\} &&\{8,6,-1\} \\
  \{-5,8,0\} && \{-3,9,7\} &&\{5,1,11\} \\
  \{-5,8,0\} && \{5,10,2\} && \{9,6,4\} \\
  \{-3,-2,-4\} && \{5,-6,4\} &&\{7,-1,9\} \\
  \{-3,1,-5\} && \{5,9,-1\} &&\{7,8,6\} \\
  \{-3,9,-1\} && \{5,1,-5\} &&\{7,-4,0\} \\
  \{-2,-4,-3\} && \{0,6,-5\} &&\{2,10,-1\}\\
  \{-2,-4,-3\} && \{5,-5,-1\} &&\{9,3,7\} \\
  \{-2,-4,9\} && \{0,6,11\} &&\{2,10,7\} \\
  \{-2,8,-3\} && \{0,10,7\} &&\{2,6,11\} \\
  \{-2,8,9\} && \{0,10,-1\} &&\{2,6,-5\} \\
  \{0,-6,-1\} && \{2,-2,-5\} && \{4,8,-3\} \\
  \{0,-6,7\} && \{2,-2,11\} &&\{4,8,9\} \\
  \{0,-2,-5\} && \{2,-6,-1\} &&\{4,-4,9\} \\
  \{0,-2,11\} && \{2,-6,7\} &&\{4,-4,-3\} \\
  \{0,6,-5\} && \{2,10,-1\} && \{4,8,9\} \\
  \{0,6,11\} && \{2,10,7\} && \{4,8,-3\} \\
  \{0,10,-1\} && \{2,6,-5\} && \{4,-4,-3\} \\
  \{0,10,7\} && \{2,6,11\} && \{4,-4,9\} \\
  \{4,-4,-3\} && \{5,6,10\} && \{9,-2,2\} \\
  \{4,8,-3\} && \{5,-5,7\} &&\{9,3,-1\} \\
  \{4,8,-3\} && \{5,-2,10\} && \{9,6,2\} \\
  \{5,-6,2\} && \{7,8,6\} &&\{9,-2,4\} \\
  \{5,-6,4\} && \{7,8,0\} &&\{9,-2,2\} \\
  \{5,10,4\} && \{7,-4,0\} &&\{9,6,2\} \\
  \{0,10,7\} && \{2,6,11\} && \{4,-4,9\} \\
  \{4,-4,-3\} && \{5,6,10\} && \{9,-2,2\} \\
  \{4,8,-3\} && \{5,-5,7\} && \{9,3,-1\} \\
  \{4,8,-3\} && \{5,-2,10\} &&\{9,6,2\} \\
  \{5,-6,2\} && \{7,8,6\} && \{9,-2,4\} \\
  \{5,-6,4\} && \{7,8,0\} &&\{9,-2,2\} \\
  \{5,10,4\} && \{7,-4,0\} &&\{9,6,2\}\\
\end{align*}
\end{mdframed}

\end{document}

Answer 3

Sie könnten eine longtableUmgebung mit neun Spalten verwenden. Jede Spalte wird automatisch im Mathematikmodus verarbeitet und geschweifte Klammern und Kommas werden automatisch eingefügt. Da ein longtableArray über mehrere Seiten umbrechen kann, müssen Sie sich keine Gedanken darüber machen, ob Sie Seitenumbrüche zulassen (oder nicht zulassen...), nur damit das Array auf eine Seite passt.

Die ersten sechs Zeilen des resultierenden Arrays sehen folgendermaßen aus:

\documentclass[12pt,a4paper]{article}
\usepackage[margin=2cm]{geometry}
\usepackage{fourier,longtable,array}
\begin{document}
\begin{longtable}{| *{3}{>{$\{}r<{$} @{,\,} >{$}r<{$} @{,\,} >{$}r<{\}$} } |}
\endfirsthead  % blank header on first page
\multicolumn{9}{l}{(\emph{array continued from previous page})}
\endhead
\multicolumn{9}{r}{(\emph{array continued on next page})}
\endfoot
\endlastfoot  % blank footer on final page
 -7 & -2 & 2 & -5 & 8 & 0 &-3 & -6 & 4 \\
 -7 & -2 & 2 & -3 & -6 & 4 &7 & -4 & 6 \\
 -7 & -2 & 2 & -3 & 6 & 10 &4 & 8 & 9 \\
 -7 & -2 & 4 & -5 & 8 & 6 & -3 & -6 & 2 \\
 -7 & -2 & 4 & -3 & -6 & 2 &7 & -4 & 0 \\
 -7 & 3 & -1 & -3 & -5 & 7 &4 & -4 & 9 \\
 -7 & 3 & 7 & -3 & -5 & -1 &-2 & 8 & 9 \\
 -7 & 6 & 2 & -5 & -4 & 0 &-3 & 10 & 4 \\
 -7 & 6 & 2 & -3 & -2 & 10 &4 & -4 & 9 \\
 -7 & 6 & 4 & -3 & 10 & 2 &7 & 8 & 0 \\
 -6 & -2 & -1 & 2 & 6 & -5 &7 & 8 & 0 \\
 -6 & -2 & 7 & -5 & -4 & 0 &2 & 6 & 11 \\
 -6 & 6 & -1 & 2 & -2 & -5 &7 & -4 & 0 \\
 -6 & 6 & 7 & -5 & 8 & 0 &2 & -2 & 11 \\
 -5 & -4 & 0 & 5 & -6 & 2 &9 & -2 & 4 \\
 -5 & -4 & 6 & -3 & 1 & 11 &5 & 9 & 7 \\
 -5 & -4 & 6 & 5 & -6 & 4 & 9 & -2 & 2 \\
 -5 & -1 & 9 & -3 & -6 & 4 &5 & -2 & -4 \\
 -5 & 5 & -3 & 0 & 10 & -1 &8 & 6 & 7 \\
 -5 & 5 & 9 & 0 & 10 & 7 &8 & 6 & -1 \\
 -5 & 8 & 0 & -3 & 9 & 7 &5 & 1 & 11 \\
 -5 & 8 & 0 & 5 & 10 & 2 & 9 & 6 & 4 \\
 -3 & -2 & -4 & 5 & -6 & 4 &7 & -1 & 9 \\
 -3 & 1 & -5 & 5 & 9 & -1 &7 & 8 & 6 \\
 -3 & 9 & -1 & 5 & 1 & -5 &7 & -4 & 0 \\
 -2 & -4 & -3 & 0 & 6 & -5 &2 & 10 & -1 \\
 -2 & -4 & -3 & 5 & -5 & -1 &9 & 3 & 7 \\
 -2 & -4 & 9 & 0 & 6 & 11 &2 & 10 & 7 \\
 -2 & 8 & -3 & 0 & 10 & 7 &2 & 6 & 11 \\
 -2 & 8 & 9 & 0 & 10 & -1 &2 & 6 & -5 \\
 0 & -6 & -1 & 2 & -2 & -5 & 4 & 8 & -3 \\
 0 & -6 & 7 & 2 & -2 & 11 &4 & 8 & 9 \\
 0 & -2 & -5 & 2 & -6 & -1 &4 & -4 & 9 \\
 0 & -2 & 11 & 2 & -6 & 7 &4 & -4 & -3 \\
 0 & 6 & -5 & 2 & 10 & -1 & 4 & 8 & 9 \\
 0 & 6 & 11 & 2 & 10 & 7 & 4 & 8 & -3 \\
 0 & 10 & -1 & 2 & 6 & -5 & 4 & -4 & -3 \\
 0 & 10 & 7 & 2 & 6 & 11 & 4 & -4 & 9 \\
 4 & -4 & -3 & 5 & 6 & 10 & 9 & -2 & 2 \\
 4 & 8 & -3 & 5 & -5 & 7 &9 & 3 & -1 \\
 4 & 8 & -3 & 5 & -2 & 10 & 9 & 6 & 2 \\
 5 & -6 & 2 & 7 & 8 & 6 &9 & -2 & 4 \\
 5 & -6 & 4 & 7 & 8 & 0 &9 & -2 & 2 \\
 5 & 10 & 4 & 7 & -4 & 0 &9 & 6 & 2 \\
 0 & 10 & 7 & 2 & 6 & 11 & 4 & -4 & 9 \\
 4 & -4 & -3 & 5 & 6 & 10 & 9 & -2 & 2 \\
 4 & 8 & -3 & 5 & -5 & 7 & 9 & 3 & -1 \\
 4 & 8 & -3 & 5 & -2 & 10 &9 & 6 & 2 \\
 5 & -6 & 2 & 7 & 8 & 6 & 9 & -2 & 4 \\
 5 & -6 & 4 & 7 & 8 & 0 &9 & -2 & 2 \\
 5 & 10 & 4 & 7 & -4 & 0 &9 & 6 & 2 \\
\end{longtable}
\end{document} 

---

Nachtrag: Wenn Sie den Code des Array-Körpers so beibehalten möchten, wie er von Mathematica bereitgestellt wird, können Sie dennoch eine longtableUmgebung anstelle einer arrayUmgebung verwenden, um das Material zu setzen. Ersetzen Sie einfach die aktuelle Anweisung

\[ \left( \begin{array}{ccc}

mit

\begin{longtable}{| *{3}{>{$}c<{$}} | }

Wenn irgendwo im Array ein Seitenumbruch auftritt, können Sie den folgenden Code bereitstellen, um den Blick des Lesers zu lenken:

\endfirsthead  % blank header on first page
\multicolumn{3}{@{}l}{(\emph{array continued from previous page})}
\endhead
\multicolumn{3}{r@{}}{(\emph{array continued on next page})}
\endfoot
\endlastfoot  % blank footer on final page

Der Inhalt der zweiten Seite würde folgendermaßen aussehen:

\documentclass{article}
\usepackage{array,longtable,fourier}
\begin{document}
\begin{longtable}{| *{3}{>{$}c<{$}} | }
\endfirsthead  % blank header on first page
\multicolumn{3}{@{}l}{(\emph{array continued from previous page})}
\endhead
\multicolumn{3}{r@{}}{(\emph{array continued on next page})}
\endfoot
\endlastfoot  % blank footer on final page
 \{-7,-2,2\} & \{-5,8,0\} &\{-3,-6,4\} \\
 \{-7,-2,2\} & \{-3,-6,4\} &\{7,-4,6\} \\
 \{-7,-2,2\} & \{-3,6,10\} &\{4,8,9\} \\
 \{-7,-2,4\} & \{-5,8,6\} & \{-3,-6,2\} \\
 \{-7,-2,4\} & \{-3,-6,2\} &\{7,-4,0\} \\
 \{-7,3,-1\} & \{-3,-5,7\} &\{4,-4,9\} \\
 \{-7,3,7\} & \{-3,-5,-1\} &\{-2,8,9\} \\
 \{-7,6,2\} & \{-5,-4,0\} &\{-3,10,4\} \\
 \{-7,6,2\} & \{-3,-2,10\} &\{4,-4,9\} \\
 \{-7,6,4\} & \{-3,10,2\} &\{7,8,0\} \\
 \{-6,-2,-1\} & \{2,6,-5\} &\{7,8,0\} \\
 \{-6,-2,7\} & \{-5,-4,0\} &\{2,6,11\} \\
 \{-6,6,-1\} & \{2,-2,-5\} &\{7,-4,0\} \\
 \{-6,6,7\} & \{-5,8,0\} &\{2,-2,11\} \\
 \{-5,-4,0\} & \{5,-6,2\} &\{9,-2,4\} \\
 \{-5,-4,6\} & \{-3,1,11\} &\{5,9,7\} \\
 \{-5,-4,6\} & \{5,-6,4\} & \{9,-2,2\} \\
 \{-5,-1,9\} & \{-3,-6,4\} &\{5,-2,-4\} \\
 \{-5,5,-3\} & \{0,10,-1\} &\{8,6,7\} \\
 \{-5,5,9\} & \{0,10,7\} &\{8,6,-1\} \\
 \{-5,8,0\} & \{-3,9,7\} &\{5,1,11\} \\
 \{-5,8,0\} & \{5,10,2\} & \{9,6,4\} \\
 \{-3,-2,-4\} & \{5,-6,4\} &\{7,-1,9\} \\
 \{-3,1,-5\} & \{5,9,-1\} &\{7,8,6\} \\
 \{-3,9,-1\} & \{5,1,-5\} &\{7,-4,0\} \\
 \{-2,-4,-3\} & \{0,6,-5\} &\{2,10,-1\} \\
 \{-2,-4,-3\} & \{5,-5,-1\} &\{9,3,7\} \\
 \{-2,-4,9\} & \{0,6,11\} &\{2,10,7\} \\
 \{-2,8,-3\} & \{0,10,7\} &\{2,6,11\} \\
 \{-2,8,9\} & \{0,10,-1\} &\{2,6,-5\} \\
 \{0,-6,-1\} & \{2,-2,-5\} & \{4,8,-3\} \\
 \{0,-6,7\} & \{2,-2,11\} &\{4,8,9\} \\
 \{0,-2,-5\} & \{2,-6,-1\} &\{4,-4,9\} \\
 \{0,-2,11\} & \{2,-6,7\} &\{4,-4,-3\} \\
 \{0,6,-5\} & \{2,10,-1\} & \{4,8,9\} \\
 \{0,6,11\} & \{2,10,7\} & \{4,8,-3\} \\
 \{0,10,-1\} & \{2,6,-5\} & \{4,-4,-3\} \\
 \{0,10,7\} & \{2,6,11\} & \{4,-4,9\} \\
 \{4,-4,-3\} & \{5,6,10\} & \{9,-2,2\} \\
 \{4,8,-3\} & \{5,-5,7\} &\{9,3,-1\} \\
 \{4,8,-3\} & \{5,-2,10\} & \{9,6,2\} \\
 \{5,-6,2\} & \{7,8,6\} &\{9,-2,4\} \\
 \{5,-6,4\} & \{7,8,0\} &\{9,-2,2\} \\
\{5,10,4\} & \{7,-4,0\} &\{9,6,2\} \\
 \{0,10,7\} & \{2,6,11\} & \{4,-4,9\} \\
 \{4,-4,-3\} & \{5,6,10\} & \{9,-2,2\} \\
 \{4,8,-3\} & \{5,-5,7\} & \{9,3,-1\} \\
 \{4,8,-3\} & \{5,-2,10\} &\{9,6,2\} \\
 \{5,-6,2\} & \{7,8,6\} & \{9,-2,4\} \\
 \{5,-6,4\} & \{7,8,0\} &\{9,-2,2\} \\
 \{5,10,4\} & \{7,-4,0\} &\{9,6,2\}
\end{longtable}
\end{document}