
Tengo una estufa y una mesa.
Quiero verificar si hay elementos duplicados en un rango y luego quiero filtrar estos elementos de la tabla... a continuación se muestra lo que hice pero no funcionó.
He escrito un código para hacer una lista/matriz/rango de elementos duplicados en la selección.
Luego paso este duplicado de lista/matriz/rango al Criterio1 de autoFilter. Pero no funciona. no filtra nada.
' making of an array/ range of duplicates from selection
Dim Ary As Variant, cell As Range, i As Integer
i = 0
ReDim Ary(0)
For Each cell In Selection
If WorksheetFunction.CountIf(Selection, cell) >= 2 Then
Ary(i) = cell.Value
i = i + 1
ReDim Preserve Ary(i)
End If
Next
'If I put msgbox Ary(0) here then it shows me a value but overall the code is not working for autofilter && is it possible to use above code as separate function
'apply filter with duplicate values
ActiveSheet.ListObjects("Table1").Range.AutoFilter Field:=3, Criteria1:= _
Ary, Operator:=xlFilterValues
End Sub
Respuesta1
Cosas que Microsoft no te cuenta Parte 94...
Los valores de los criterios de filtro utilizados en el Autofilter
método deben especificarse como cadenas de texto, incluso si la columna que está filtrando comprende números.
Cambie su declaración de asignación utilizada para construir la Ary
matriz a
Ary(i) = CStr(cell.Value)
para garantizar que la matriz comprenda cadenas de texto.
Aún mejor, declara adicionalmente Ary
como una matriz de cadenas
Dim Ary() As String
y no como una variante, por lo que la intención Ary
queda clara desde el principio.
Hay una pista en eldocumentación para el método Autofiltroque los números deben pasarse a los argumentos de criterios como cadenas de texto (consulte el tercer ejemplo enumerado en la documentación), pero no se enfatiza este requisito.
Respuesta2
Devolver duplicados únicos en una matriz
- La forma más eficiente (más rápida) de obtener los valores duplicados únicos en una matriz generalmente se logra mediante el uso de un diccionario: primero se escriben todos los valores y su recuento y luego se recorre las claves en el diccionario y se elimina cada clave cuyo El artículo tiene un valor de 1.
- Para 'obtener' una matriz o cualquier otro resultado, debe usar una función que llamará desde su procedimiento,
por ejemploDim Ary As Variant: Ary = ArrMultiRangeDuplicates(Range("A1:A10,D5:d13")
. - Para 'convertir una matriz en texto' puedes usar este sencillo truco que utilicé en tu subejemplo:
Ary = Split(Join(Ary, vbLf & "?"), vbLf & "?")
- Antes de aplicar un filtro, debe verificar y eliminar cualquier filtro existente previamente.
Option Explicit
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Purpose: If the 'Selection' is a range and if its cells contain
' duplicates, it will use these duplicates to filter
' the active sheet's Excel table 'Table1' in its 3rd column.
' Calls: ArrMultiRangeDuplicates
' DictMultiRangeCount
' GetRange
' DictAddCount
' DictRemoveSingleCount
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Sub FilterByDuplicatesExample()
Const ProcName As String = "FilterByDuplicatesExample"
On Error GoTo ClearError
If Not TypeOf Selection Is Range Then Exit Sub ' not a range
' Using the ArrMultiRangeDuplicates function and its accompanying procedures,
' write the Selection's duplicates to an array.
Dim Ary As Variant: Ary = ArrMultiRangeDuplicates(Selection)
If IsEmpty(Ary) Then Exit Sub
' Using the Split and Join functions, 'convert the array to text'.
Ary = Split(Join(Ary, vbLf & "?"), vbLf & "?")
'Debug.Print Join(Ary, ",")
' Apply the filter.
With ActiveSheet.ListObjects("Table1")
If .ShowAutoFilter Then ' remove possible previous filter
If .AutoFilter.FilterMode Then .AutoFilter.ShowAllData
End If
.Range.AutoFilter Field:=3, Criteria1:=Ary, Operator:=xlFilterValues
End With
ProcExit:
Exit Sub
ClearError:
Debug.Print "'" & ProcName & "' Run-time error '" _
& Err.Number & "':" & vbLf & " " & Err.Description
Resume ProcExit
End Sub
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Purpose: Tests the ArrMultiRangeDuplicates function.
' In the active sheet, enter some values in a range
' starting from cell `A1`. Make sure there are duplicates.
' In the Immediate window (Ctrl+G) see the results.
' Calls: ArrMultiRangeDuplicates
' DictMultiRangeCount
' GetRange
' DictAddCount
' DictRemoveSingleCount
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Sub ArrMultiRangeDuplicatesTEST()
Dim rg As Range: Set rg = Range("A1").CurrentRegion
Dim Arr As Variant: Arr = ArrMultiRangeDuplicates(rg)
If Not IsEmpty(Arr) Then
Debug.Print Join(Arr, ",")
End If
End Sub
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Purpose: From a (multi-) range ('mrg'), returns its cell's duplicates
' in an array.
' Remarks: Error values and blanks are excluded.
' Calls: DictMultiRangeCount
' GetRange
' DictAddCount
' DictRemoveSingleCount
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Function ArrMultiRangeDuplicates( _
ByVal mrg As Range) _
As Variant
Const ProcName As String = "ArrMultiRangeDuplicates"
On Error GoTo ClearError
' Return the unique values and their count, in a dictionary
Dim dict As Object: Set dict = DictMultiRangeCount(mrg)
If dict Is Nothing Then Exit Function
' Remove the values that occur only once from the dictionary.
DictRemoveSingleCount dict
If dict.Count = 0 Then Exit Function
' Return the dictionary keys.
ArrMultiRangeDuplicates = dict.Keys
ProcExit:
Exit Function
ClearError:
Debug.Print "'" & ProcName & "' Run-time error '" _
& Err.Number & "':" & vbLf & " " & Err.Description
Resume ProcExit
End Function
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Purpose: From a (multi-) range ('mrg'), returns its cell's unique values
' and their count, in a dictionary.
' Remarks: Error values and blanks are excluded.
' Calls: GetRange,DictAddCount.
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Function DictMultiRangeCount( _
ByVal mrg As Range) _
As Object
Const ProcName As String = "ArrMultiRangeDuplicates"
On Error GoTo ClearError
Dim dict As Object: Set dict = CreateObject("Scripting.Dictionary")
dict.CompareMode = vbTextCompare
Dim arg As Range
Dim aData As Variant
Dim aKey As Variant
Dim acCount As Long
Dim ar As Long
Dim ac As Long
For Each arg In mrg.Areas
aData = GetRange(arg)
acCount = UBound(aData, 2)
For ar = 1 To UBound(aData) ' rows
For ac = 1 To acCount ' columns
aKey = aData(ar, ac)
DictAddCount dict, aKey ' write to the dictionary
Next ac
Next ar
Next arg
If dict.Count = 0 Then Exit Function
Set DictMultiRangeCount = dict
ProcExit:
Exit Function
ClearError:
Debug.Print "'" & ProcName & "' Run-time error '" _
& Err.Number & "':" & vbLf & " " & Err.Description
Resume ProcExit
End Function
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Purpose: Returns the values of a range ('rg') in a 2D one-based array.
' Remarks: If ˙rg` refers to a multi-range, only its first area
' is considered.
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Function GetRange( _
ByVal rg As Range) _
As Variant
Const ProcName As String = "GetRange"
On Error GoTo ClearError
If rg.Rows.Count + rg.Columns.Count = 2 Then ' one cell
Dim Data As Variant: ReDim Data(1 To 1, 1 To 1): Data(1, 1) = rg.Value
GetRange = Data
Else ' multiple cells
GetRange = rg.Value
End If
ProcExit:
Exit Function
ClearError:
Debug.Print "'" & ProcName & "' Run-time error '" _
& Err.Number & "':" & vbLf & " " & Err.Description
Resume ProcExit
End Function
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Purpose: Adds a value ('Key') to a key of an existing ('ByRef')
' dictionary ('dict') writing the number 1 to its associated item.
' If the key already exists, it increases its item's value by 1.
' Remarks: Error values and blanks are excluded.
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Sub DictAddCount( _
ByRef dict As Object, _
ByVal Key As Variant)
Const ProcName As String = "DictAddCount"
On Error GoTo ClearError
If Not IsError(Key) Then ' exclude error values
If Len(Key) > 0 Then ' exclude blanks
dict(Key) = dict(Key) + 1 ' count
End If
End If
ProcExit:
Exit Sub
ClearError:
Debug.Print "'" & ProcName & "' Run-time error '" _
& Err.Number & "':" & vbLf & " " & Err.Description
Resume ProcExit
End Sub
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Purpose: In an existing ('ByRef') dictionary ('dict'), removes each key
' whose item's value is equal to a whole number ('KeyCount').
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Sub DictRemoveSingleCount( _
ByRef dict As Object, _
Optional ByVal KeyCount As Long = 1)
Const ProcName As String = "DictRemoveSingleCount"
On Error GoTo ClearError
Dim Key As Variant
For Each Key In dict.Keys
If IsNumeric(dict(Key)) Then
If dict(Key) = KeyCount Then dict.Remove Key
End If
Next Key
ProcExit:
Exit Sub
ClearError:
Debug.Print "'" & ProcName & "' Run-time error '" _
& Err.Number & "':" & vbLf & " " & Err.Description
Resume ProcExit
End Sub