
Esta es mi primera figura tratando de tenerla en elproyectorcon \foreach
.
Para algunos puede que sean cinco minutos de trabajo... pero a mí me ha consumido toda la mañana...
Entonces mi pregunta:¿Cómo puedo tener separaciones frame
para cada imagen que produce el \foreach
operador? El \newframe
interior \foreach
no funciona.
Mi metaera hacer que tuviera movimiento (en sentido antihorario)... pero no enredar dos preguntas juntas
\documentclass{beamer}%{book}
\usepackage[utf8x]{inputenc}
\usepackage{default}
\usepackage{tikz}
\usetikzlibrary{calc}
\usetheme{Warsaw}
\usecolortheme{whale}
\begin{document}
%
\begin{frame}{rotating - test}
%
\begin{center}
\begin{tikzpicture}[scale=2]
\draw[thin,gray,step=0.25] (-1,-1) grid (1,1);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\draw[->] (-1.5,0) -- (1.5,0) node[below]{$\phi_0$};
\draw[->] (0,-1.5) -- (0,1.5) node[left]{$x$};
\draw[thick] (0,0) circle [radius=1];
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\coordinate (C1) at (1,0);
\coordinate (C2) at (0.86,0.5);
\coordinate (C3) at (0.7,0.7);
\coordinate (C4) at (0.5,0.86);
\coordinate (C5) at (0,1);
\coordinate (C6) at (-0.5,0.86);
\coordinate (C7)at(-0.7,0.7);
\coordinate (C8)at(-0.86,0.5);
\coordinate (C9) at (-1,0);
\coordinate (C10) at (-0.86,-0.5);
\coordinate (C11)at(-0.7,-0.7);
\coordinate (C12) at (-0.5,-0.86);
\coordinate (C13) at (0,-1);
\coordinate (C14) at (0.5,-0.86);
\coordinate (C15) at (0.7,-0.7);
\coordinate (C16) at (0.86,-0.5);
%
\foreach \Ctest in {(C1),(C2),(C3),(C4),(C5),(C6),
(C7),(C8),(C9),(C10),(C11),(C12),(C13),(C14),(C15),(C16)}{%
\draw [dashed] let \p1 = \Ctest
in
(\x1,\y1) -- (0,\y1)
(\x1,\y1) -- (0,0);
\draw [red,thick,->] let \p1 = \Ctest
in
(0,0) -- (0,\y1) node[left] {$x$};
\draw [red,thick] let \p1 = \Ctest,
\n1={atan2(\x1,\y1)}
in
(1,0) arc (0:\n1:1)
(0,0)--(0.251,0) arc (0:\n1:0.25)--cycle;
\draw[fill=red] \Ctest circle [radius=0.06];
% \newframe %<<================================================
};
\end{tikzpicture}
%
\end{center}
%
\end{frame}
\end{document}
1 Actualización:Después de respuesta de @Claudio Fiandrino y @Gonzalo Medina tengo esta figura. El problema ahora es que quiero que la "órbita" del cuerpo rojo tenga un arco creciente continuo, pero el ángulo de más de 180 grados no está definido.
Respuesta1
TikZ
y beamer
están bien integrados; en particular, los comandos de TikZ reconocen la superposición, por lo que puede decir, por ejemplo \draw<+-> ...
; en este caso particular, count=<macro>
se puede utilizar la sintaxis (comoCaludio Fiandrinosugerido en su comentario) para mantener cada posición en el bucle y luego usar <macro>
para la especificación de superposición:
El código original se puede simplificar mucho si en lugar de asignar coordenadas se \Ctest
trabaja con ángulos:
\documentclass{beamer}%{book}
\usepackage[utf8x]{inputenc}
\usepackage{tikz}
\usetikzlibrary{calc}
\usetheme{Warsaw}
\usecolortheme{whale}
\begin{document}
\begin{frame}{rotating - test}
\begin{center}
\begin{tikzpicture}[scale=2]
\draw[thin,gray,step=0.25] (-1,-1) grid (1,1);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\draw[->] (-1.5,0) -- (1.5,0) node[below]{$\phi_0$};
\draw[->] (0,-1.5) -- (0,1.5) node[left]{$x$};
\draw[thick] (0,0) circle [radius=1];
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\foreach \Ctest[count=\i] in {0,30,45,60,90,120,135,150,180,210,225,240,270,300,315,330,360}{%
\draw<\i> [dashed]
(0,0) -- (\Ctest:1) -- (0,{sin(\Ctest)})
node[left,red] {$x$};
\draw<\i> [red,thick]
(0,0)--(0.251,0) arc (0:\Ctest:0.25) -- cycle;
\draw<\i> [->,red,thick]
(0,0) -- (0,{sin(\Ctest)});
\draw<\i>[fill=red] ({cos(\Ctest)},{sin(\Ctest)}) circle [radius=0.06];
}
\end{tikzpicture}
\end{center}
\end{frame}
\end{document}
Y con el código original:
\documentclass{beamer}%{book}
\usepackage[utf8x]{inputenc}
%\usepackage{default}
\usepackage{tikz}
\usetikzlibrary{calc}
\usetheme{Warsaw}
\usecolortheme{whale}
\begin{document}
%
\begin{frame}{rotating - test}
%
\begin{center}
\begin{tikzpicture}[scale=2]
\draw[thin,gray,step=0.25] (-1,-1) grid (1,1);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\draw[->] (-1.5,0) -- (1.5,0) node[below]{$\phi_0$};
\draw[->] (0,-1.5) -- (0,1.5) node[left]{$x$};
\draw[thick] (0,0) circle [radius=1];
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\coordinate (C1) at (1,0);
\coordinate (C2) at (0.86,0.5);
\coordinate (C3) at (0.7,0.7);
\coordinate (C4) at (0.5,0.86);
\coordinate (C5) at (0,1);
\coordinate (C6) at (-0.5,0.86);
\coordinate (C7)at(-0.7,0.7);
\coordinate (C8)at(-0.86,0.5);
\coordinate (C9) at (-1,0);
\coordinate (C10) at (-0.86,-0.5);
\coordinate (C11)at(-0.7,-0.7);
\coordinate (C12) at (-0.5,-0.86);
\coordinate (C13) at (0,-1);
\coordinate (C14) at (0.5,-0.86);
\coordinate (C15) at (0.7,-0.7);
\coordinate (C16) at (0.86,-0.5);
%
\foreach \Ctest[count=\i] in {(C1),(C2),(C3),(C4),(C5),(C6),
(C7),(C8),(C9),(C10),(C11),(C12),(C13),(C14),(C15),(C16)}{%
\draw<\i> [dashed] let \p1 = \Ctest
in
(\x1,\y1) -- (0,\y1)
(\x1,\y1) -- (0,0);
\draw<\i> [red,thick,->] let \p1 = \Ctest
in
(0,0) -- (0,\y1) node[left] {$x$};
\ifnum\i<9\relax
{\draw<\i> [red,thick] let \p1 = \Ctest,
\n1={atan2(\x1,\y1)}
in
(0,0)--(0.251,0) arc (0:\n1:0.25)--cycle;
}
\else
{
\draw<\i> [red,thick]
(0.25,0mm) arc (0:180:0.25);
\draw<\i> [red,thick] let \p1 = \Ctest,
\n1={atan2(-\x1,\y1)}
in
(0,0)--(-0.251,0) arc (0:-\n1:-0.25)--cycle;
}
\fi
\draw<\i>[fill=red] \Ctest circle [radius=0.06];
};
\end{tikzpicture}
%
\end{center}
%
\end{frame}
\end{document}