Respuesta1
Como punto de partida puede servir el siguiente código, que proporciona parte de su deseo:
\documentclass[tikz, border=3mm]{standalone}
\usetikzlibrary{arrows.meta,chains,matrix,decorations.pathreplacing}
\begin{document}
\begin{tikzpicture}[
node distance=0pt,
start chain = A going right,
arrow/.style = {draw=#1,-{Stealth[]},
shorten >=1mm, shorten <=1mm}, % styles of arrows
arrow/.default = black,
X/.style = {rectangle, draw,% styles of nodes in string (chain)
minimum width=2ex, minimum height=3ex,
outer sep=0pt, on chain},
B/.style = {decorate,
decoration={brace, amplitude=5pt,
pre=moveto,pre length=1pt,post=moveto,post length=1pt,
raise=1mm,
#1}, % for mirroring of brace, if necessary
thick},
B/.default = mirror, % by default braces are mirrored
]
\foreach \i in {1,0,0,0,1,1,
2,0,3,4,1,2}% <-- content of nodes
\node[X] {\i};
\matrix (ML) [matrix of nodes,
nodes=draw, dashed, row sep=1mm,
row 1 column 1/.style={draw=red},
left=11mm of A-1]
{
1\ 0\\
0\ 0\\
1\ 1\\
};
\draw (ML.north -| ML-1-1.north west) -|
(ML.south west) --
(ML.south -| ML-3-1.south west)
%
(ML.north -| ML-1-1.north east) -|
(ML.south east) --
(ML.south -| ML-3-1.south east)
;
\matrix (MR) [matrix of nodes,
nodes=draw, dashed, row sep=1mm,
row 1 column 1/.style={draw=red},
right=11mm of A-12]
{ 1\ 0\\
0\ 0\\
1\ 1\\
};
\draw (MR.north -| MR-1-1.north west) -|
(MR.south west) --
(MR.south -| MR-3-1.south west)
%
(MR.north -| MR-1-1.north east) -|
(MR.south east) --
(MR.south -| MR-3-1.south east)
;
\draw[B=,red] (A-1.north west) -- coordinate[above=3mm] (a) (A-2.north east);
\draw[arrow] (ML-1-1.north) to [out=60, in=120] (a);
\draw[B] (A-3.south west) -- coordinate[below=3mm] (b) (A-4.south east);
\draw[arrow] (ML-2-1.south) to [out=315, in=210] (b);
\draw[B] (A-5.south west) -- coordinate[below=3mm] (c) (A-6.south east);
\draw[arrow] (ML-3-1.south) to [out=315, in=240] (c);
\end{tikzpicture}
\end{document}
Su sorteo:
Creo que faltar parte de las imágenes deseadas (la parte principal está determinada por el código anterior) es una adición relativamente sencilla. Si en esto tendrás problemas, solo pregunta dónde te quedaste estancado.