Etiqueta en una flecha doblada

Question

Tengo algunos problemas con el siguiente código:

\documentclass[crop,border=0]{standalone}
\usepackage{amsmath}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture} [>=latex]
    \draw[->, out=225, in=200] (-0.5,1.2) to (12-0.5,-1.6) node [pos=0.8, below] {\scriptsize $\begin{pmatrix}1 & 0 & 0 & 0 \end{pmatrix}$};
\end{tikzpicture}
\end{document}

No importa lo que elija, possiempre obtengo que el vector de fila se posicione como se muestra en la siguiente figura (ubicación fija y no debajo de la flecha). Mi intención es colocar el vector hacia el final de la flecha y debajo de ella.

¿Cualquier sugerencia? ¡Gracias!

Answer 1

La sintaxis correcta es colocar el nodo inmediatamente después to:

\documentclass[crop,border=0]{standalone}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{bbox}
\begin{document}
\begin{tikzpicture} [>=latex,bezier bounding box]
    \draw[->, out=225, in=200] (-0.5,1.2) to node [pos=0.8, below] {\scriptsize
    $\begin{pmatrix}1 & 0 & 0 & 0 \end{pmatrix}$} (12-0.5,-1.6) ;
\end{tikzpicture}
\end{document}

Elbbox biblioteca, que se utilizó para obtener el cuadro delimitador correcto, se puede encontraraquí.

APÉNDICE: Si se usa arrows.metay bending, la biblioteca (experimental) bboxdebe modificarse ligeramente (porque la flexión introduce curvas de Bézier muy cortas). Guarde lo siguiente como tikzlibrarybbox.code.tex:

\tikzset{%
  bezier bounding box/.is choice,%
  bezier bounding box/.default=true,%
  bezier bounding box/true/.code=\tikzset{switch on bezier bounding box},%
  bezier bounding box/false/.code=\tikzset{switch off bezier bounding box}}%
\tikzset{switch off bezier bounding box/.code={%
\def\pgf@lt@curveto##1##2##3##4##5##6{%
  \pgf@protocolsizes{##1}{##2}%
  \pgf@protocolsizes{##3}{##4}%
  \pgf@protocolsizes{##5}{##6}%
  \pgfsyssoftpath@curveto{\the##1}{\the##2}{\the##3}{\the##4}{\the##5}{\the##6}%
}%
\let\pgf@nlt@curveto\pgf@lt@curveto}}
%
% it might just be me but according to what I believe to find 
% \pgfmathsetlengthmacro appears to generate spaces
%
\tikzset{switch on bezier bounding box/.code={%
\def\pgf@lt@curveto##1##2##3##4##5##6{%
  % extrema in x
  \pgfmathsetmacro{\pgf@temp@b}{abs(\pgf@path@lastx-##5-3*##1+3*##3)}%
  % ^^^ this is used for the denominator below, cannot become too small
  \pgfmathsetmacro{\pgf@temp@c}{max(1+\pgf@path@lastx,max(##1,max(##3,##5)))}%
  % ^^^ in order to avoid dimension too large errors from squaring lengths in pt
  \ifdim\pgf@temp@c pt>1pt
   \pgfmathparse{((##1/\pgf@temp@c)*(##1/\pgf@temp@c)-1*((##1/\pgf@temp@c)*(##3/\pgf@temp@c))+(##3/\pgf@temp@c)*(##3/\pgf@temp@c)-1*((##1/\pgf@temp@c)*(##5/\pgf@temp@c))+(-(##3/\pgf@temp@c)+(##5/\pgf@temp@c))*(\pgf@path@lastx/\pgf@temp@c))}%
   \pgfutil@tempdima=\pgfmathresult pt\relax% 
   % ^^^ discriminant
   \ifdim\pgf@temp@b pt<0.01pt\relax%
    % approximately linear  
    \pgfmathparse{abs(2*(##1)-2*(##3)+(##5))}%
    \pgfutil@tempdimb=\pgfmathresult pt\relax%
    \ifdim\pgfutil@tempdimb<0.1pt\relax%
     % if the denominator is very small, it is *likely* large but could be 0/0
    \else
     \pgfmathsetmacro{\pgf@temp@a}{(2*(##1)-3*(##3)+(##5))/(2*(##1)-2*(##3)+(##5))}%
     \pgfmathparse{\pgf@path@lastx*pow(1-\pgf@temp@a,3)+3*##1*pow(1-\pgf@temp@a,2)*\pgf@temp@a+3*##3*(1-\pgf@temp@a)*\pgf@temp@a*\pgf@temp@a+##5*pow(\pgf@temp@a,3)}%
     \pgfutil@tempdimb=\pgfmathresult pt\relax%
     \pgf@protocolsizes{\pgfutil@tempdimb}{##6}%
    \fi%
   \else
    \ifdim\pgfutil@tempdima<0pt\relax% negative discriminant -> no turning point
    \else
      \pgfmathsetmacro{\pgf@temp@a}{min(1,max(0,(\pgf@path@lastx-2*##1+##3-\pgf@temp@c*sqrt(\pgfutil@tempdima))/(\pgf@path@lastx-##5-3*##1+3*##3)))}%
      \pgfmathparse{\pgf@path@lastx*pow(1-\pgf@temp@a,3)+3*##1*pow(1-\pgf@temp@a,2)*\pgf@temp@a+3*##3*(1-\pgf@temp@a)*\pgf@temp@a*\pgf@temp@a+##5*pow(\pgf@temp@a,3)}%
      \pgfutil@tempdimb=\pgfmathresult pt\relax%
      \pgf@protocolsizes{\pgfutil@tempdimb}{##6}%
      \pgfmathsetmacro{\pgf@temp@a}{min(1,max(0,(\pgf@path@lastx-2*##1+##3+\pgf@temp@c*sqrt(\pgfutil@tempdima))/(\pgf@path@lastx-##5-3*##1+3*##3)))}%
      \pgfmathparse{\pgf@path@lastx*pow(1-\pgf@temp@a,3)+3*##1*pow(1-\pgf@temp@a,2)*\pgf@temp@a+3*##3*(1-\pgf@temp@a)*\pgf@temp@a*\pgf@temp@a+##5*pow(\pgf@temp@a,3)}%
      \pgfutil@tempdimb=\pgfmathresult pt\relax%
      \pgf@protocolsizes{\pgfutil@tempdimb}{##6}%
    \fi% 
   \fi 
  \fi
  %%%%%%%%%%%%%%%%%%%%%%%%%%%
  % extrema in y (completely analogous to the above)
  \pgfmathsetmacro{\pgf@temp@b}{abs(\pgf@path@lasty-##6-3*##2+3*##4)}%
  \pgfmathsetmacro{\pgf@temp@c}{max(1+\pgf@path@lasty,max(##2,max(##4,##6)))}%
  \ifdim\pgf@temp@c pt>1pt
   \pgfmathparse{((##2/\pgf@temp@c)*(##2/\pgf@temp@c)-1*((##2/\pgf@temp@c)*(##4/\pgf@temp@c))+(##4/\pgf@temp@c)*(##4/\pgf@temp@c)-1*((##2/\pgf@temp@c)*(##6/\pgf@temp@c))+(-(##4/\pgf@temp@c)+(##6/\pgf@temp@c))*(\pgf@path@lasty/\pgf@temp@c))}%
   \pgfutil@tempdima=\pgfmathresult pt\relax% 
   % ^^^ discriminant
   \ifdim\pgf@temp@b pt<0.01pt\relax%
    % approximately linear  
    \pgfmathparse{abs(2*(##2)-2*(##4)+(##6))}%
    \pgfutil@tempdimb=\pgfmathresult pt\relax%
    \ifdim\pgfutil@tempdimb<0.1pt\relax%
     % if the denominator is very small, it is *likely* large but could be 0/0
    \else
     \pgfmathsetmacro{\pgf@temp@a}{(2*(##2)-3*(##4)+(##6))/(2*(##2)-2*(##4)+(##6))}%
     \pgfmathparse{\pgf@path@lasty*pow(1-\pgf@temp@a,3)+3*##2*pow(1-\pgf@temp@a,2)*\pgf@temp@a+3*##4*(1-\pgf@temp@a)*\pgf@temp@a*\pgf@temp@a+##6*pow(\pgf@temp@a,3)}%
     \pgfutil@tempdimb=\pgfmathresult pt\relax%
     \pgf@protocolsizes{##5}{\pgfutil@tempdimb}%
    \fi%
   \else
    \ifdim\pgfutil@tempdima<0pt\relax% negative discriminant -> no turning point
    \else
      \pgfmathsetmacro{\pgf@temp@a}{min(1,max(0,(\pgf@path@lasty-2*##2+##4-\pgf@temp@c*sqrt(\pgfutil@tempdima))/(\pgf@path@lasty-##6-3*##2+3*##4)))}%
      \pgfmathparse{\pgf@path@lasty*pow(1-\pgf@temp@a,3)+3*##2*pow(1-\pgf@temp@a,2)*\pgf@temp@a+3*##4*(1-\pgf@temp@a)*\pgf@temp@a*\pgf@temp@a+##6*pow(\pgf@temp@a,3)}%
      \pgfutil@tempdimb=\pgfmathresult pt\relax%
      \pgf@protocolsizes{##5}{\pgfutil@tempdimb}%
      \pgfmathsetmacro{\pgf@temp@a}{min(1,max(0,(\pgf@path@lasty-2*##2+##4+\pgf@temp@c*sqrt(\pgfutil@tempdima))/(\pgf@path@lasty-##6-3*##2+3*##4)))}%
      \pgfmathparse{\pgf@path@lasty*pow(1-\pgf@temp@a,3)+3*##2*pow(1-\pgf@temp@a,2)*\pgf@temp@a+3*##4*(1-\pgf@temp@a)*\pgf@temp@a*\pgf@temp@a+##6*pow(\pgf@temp@a,3)}%
      \pgfutil@tempdimb=\pgfmathresult pt\relax%
      \pgf@protocolsizes{##5}{\pgfutil@tempdimb}%
    \fi% 
   \fi 
  \fi
  \pgf@protocolsizes{\pgf@path@lastx}{\pgf@path@lasty}%
  \pgf@protocolsizes{##5}{##6}%
  \pgfsyssoftpath@curveto{\the##1}{\the##2}{\the##3}{\the##4}{\the##5}{\the##6}%
}
\let\pgf@nlt@curveto\pgf@lt@curveto}}% fix me: 0/0 cases and occasional
% dimension too large errors (they can be fixed with fpu)

Entonces lo siguiente también funciona:

\documentclass[crop,border=0]{standalone}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{bbox,arrows.meta,bending}
\begin{document}
\begin{tikzpicture} [,bezier bounding box]
    \draw[-{Latex[bend]}, out=225, in=200] (-0.5,1.2) to node [pos=0.8, below] {\scriptsize
    $\begin{pmatrix}1 & 0 & 0 & 0 \end{pmatrix}$} (12-0.5,-1.6) ;
\end{tikzpicture}
\end{document}

Answer 2

Pruebe lo siguiente:

\documentclass[crop,border=0]{standalone}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{quotes}

\begin{document}
    \begin{tikzpicture} [>=latex, auto=right
                        ]
\draw[->] (-0.5,1.2) to [out=225, in=200, "$\begin{pmatrix}1 & 0 & 0 & 0 \end{pmatrix}$", pos=0.7] (12-0.5,-1.6);
    \end{tikzpicture}
\end{document}

Apéndice

Puedes considerar agregar \clip (-1.2,1.2) rectangle (11.5,-3);antes de dibujar la curva. Con él, recortará el espacio en blanco en el lado izquierdo de la imagen (causado por la flexión de los anclajes). Para fuentes más pequeñas de etiquetas de borde, puede definir su estilo tal como está en el siguiente MWE:

\documentclass[crop,border=0]{standalone}
\usepackage{amsmath}
\usepackage{tikz}
\usetikzlibrary{quotes}

\begin{document}
    \begin{tikzpicture} [>=latex, 
every edge quotes/.style = {font=\scriptsize, auto=right}
                        ]
\clip (-1.2,1.2) rectangle (11.5,-3);
\draw[->] (-0.5,1.2) to [out=225, in=200, "$\begin{pmatrix}1 & 0 & 0 & 0 \end{pmatrix}$", pos=0.7] (11.5,-1.6);
    \end{tikzpicture}
\end{document}