Omitir dibujar una parte del contorno de un dibujo.

Question

De la respuesta aesta pregunta, utilicé el siguiente código para dibujar un cuadrante de una cruz:

\documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\begin{document}
\begin{frame}[t]
\frametitle{}
\includegraphics[width=6.6cm,keepaspectratio]{./cross_coptic.jpg}
\vskip -6.5cm
\hskip .04cm
\begin{tikzpicture}[scale=.9, transform shape]
\node [red] at (0,0) (o){\bf .}%do not insert empty lines inbetween
([shift={(90.:3.4cm)}]o.center) node [red] (t){\bf .}%topmost
([shift={(180.:3.38cm)}]o.center) node [red] (ol){\bf .}
([shift={(90.:.6cm)}]o.center) node [red] (oua){\bf .}%up 1 level
([shift={(180.:.6cm)}]oua.center) node [red] (oual){\bf .}
([shift={(90.:2.1cm)}]o.center) node [red] (ouaaa){\bf .}%up 3 levels
([shift={(180.:1.6cm)}]ouaaa.center) node [red] (ouaaal){\bf .}
([shift={(90.:2.45cm)}]o.center) node [red] (ouaaaa){\bf .}%up 4 levels
([shift={(180.:.6cm)}]ouaaaa.center) node [red] (ouaaaal){\bf .}
;
\draw[line width=.1cm,red, fill=red!20!white] (oual.center)
 to [out=90,in=-20, looseness=1.] (ouaaal.center)
 to [out=50,in=180, looseness=1.] (ouaaaal.center)
 to [out=90,in=-150, looseness=1.] (t.center)
 to [out=-90,in=90, looseness=1.] (o.center)
 to [out=180,in=0, looseness=1.] ([shift={(-90:.6)}]oual.center)
 -- cycle
;
\end{tikzpicture}
\end{frame}
\end{document}

¿Es posible omitir dibujar el contorno presente dentro de la cruz (conectando los nodos t -- o -- shift={(-90:.6)}]oual -- oual), siguiendo llenando el cuadrante?

Answer 1

\documentclass[tikz, border=1cm]{standalone}
\usetikzlibrary{spath3}
\begin{document}
\begin{tikzpicture}
\path[spath/save=apath] (-1,1) -- (-1,2) to[out=100, in=-20] (-2.6,3.4) to[out=45, in=180] (-1,4.2) to[out=90, in=210] (0,5.6);
\draw[line width=6pt] 
[spath/use={apath}]
[spath/use={apath, move, weld, transform={xscale=-1, rotate=0}, reverse}]
[spath/use={apath, move, weld, transform={scale=-1, rotate=90}}]
[spath/use={apath, move, weld, transform={xscale=-1, rotate=90}, reverse}]
[spath/use={apath, move, weld, transform={scale=-1, rotate=0}}]
[spath/use={apath, move, weld, transform={yscale=-1, rotate=0}, reverse}]
[spath/use={apath, move, weld, transform={scale=-1, rotate=-90}}]
[spath/use={apath, move, weld, transform={xscale=-1, rotate=-90}, reverse}]
-- cycle;
\fill[red!20] (0,0) -- (-1,0) [spath/use={apath, weld}] --cycle;
\draw[red, line width=6pt] [spath/use={apath}];
\end{tikzpicture}
\end{document}

Answer 2

Asegúrate de lo que quieres hacer exactamente, pero puedes eliminar la línea dibujada manteniendo el relleno del fondo reemplazándola \drawpor \fill, como se muestra a continuación:

\documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\begin{document}
\begin{frame}[t]
\frametitle{}
%\includegraphics[width=6.6cm,keepaspectratio]{./cross_coptic.jpg}
%\vskip -6.5cm
%\hskip .04cm
\begin{tikzpicture}[scale=.9, transform shape]
\node at (0,0) (o){}%do not insert empty lines inbetween
([shift={(90.:3.4cm)}]o.center) node (t){}%topmost
([shift={(180.:3.38cm)}]o.center) node (ol){}
([shift={(90.:.6cm)}]o.center) node (oua){}%up 1 level
([shift={(180.:.6cm)}]oua.center) node  (oual){}
([shift={(90.:2.1cm)}]o.center) node (ouaaa){}%up 3 levels
([shift={(180.:1.6cm)}]ouaaa.center) node (ouaaal){}
([shift={(90.:2.45cm)}]o.center) node (ouaaaa){}%up 4 levels
([shift={(180.:.6cm)}]ouaaaa.center) node (ouaaaal){}
;
\fill[red!20!white] (oual.center)
 to [out=90,in=-20, looseness=1.] (ouaaal.center)
 to [out=50,in=180, looseness=1.] (ouaaaal.center)
 to [out=90,in=-150, looseness=1.] (t.center)
 to [out=-90,in=90, looseness=1.] (o.center)
 to [out=180,in=0, looseness=1.] ([shift={(-90:.6)}]oual.center)
 -- cycle
;

\end{tikzpicture}
\end{frame}
\end{document}

Tenga en cuenta que comenté la figura incluida ya que no la tengo cross_coptic.jpg. Puede descomentar las líneas 8 a 10.