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Convierta bloques de Simulink en un modelo TikZ

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Convierta bloques de Simulink en un modelo TikZ

¿Alguien sabe cómo es el código TikZ para crear este modelo con estas ecuaciones?

ingrese la descripción de la imagen aquí

Nota. Independientemente del color de las líneas y flechas de la imagen, todas tienen que ser negras y estar dibujadas de forma continua.

Muchas gracias por todo

Respuesta1

Puedes usar el paquete SchemaBloc

\documentclass[border=5pt]{standalone}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usepackage{schemabloc}


\begin{document}

\begin{tikzpicture}
\sbEntree{r}
\sbComp*{compar}{r}                               
\sbRelier[$r$]{r}{compar}{}
\sbBloc{H1}{$\dfrac{1}{s+1}$}{compar}  
\sbRelier[$\varepsilon$]{compar}{H1}{}
\sbBloc{H2}{$\dfrac{1}{s+2}$}{H1}  
\sbRelier[]{H1}{H2}{}
\sbSortie[5]{Y}{H2}                              
\sbRelier[$y$]{H2}{Y}{}     
\sbRenvoi{H2-Y}{compar}{$y_m$}
\end{tikzpicture}

\end{document}

ingrese la descripción de la imagen aquí

Puedes probar aquí https://fr.overleaf.com/read/mwrzbnqmmtmy

Respuesta2

Con TikZ puro:

\documentclass[tikz, margin=3.14159mm]{standalone}
\usetikzlibrary{arrows.meta,
                chains,
                positioning,
                quotes}
\usepackage{amsmath}

\begin{document}
    \begin{tikzpicture}[auto,
node distance = 11mm and 9mm,
  start chain = A going right,
   arr/.style = {draw=#1, semithick, -Triangle},
 arr/.default = black,
   box/.style = {draw, minimum height=11mm, minimum width=22mm},
   dot/.style = {circle, fill, inner sep=2pt, outer sep=0pt, anchor=center},
   sum/.style = {circle, draw, minimum size=9mm}
                        ]
    \begin{scope}[nodes={on chain=A}]
\coordinate (in);
\node [sum] {};                     % A-2
\node [box] {$\dfrac{1}{s + 1}$};
\node [box] {$\dfrac{1}{s + 2}$};
\node [dot] {};                     % A-5
\coordinate (out);
    \end{scope}
\draw[arr=red]  (in) to ["$r$"] (A-2.west) node[right] {$+$}; 
\draw[arr]  (A-2)   edge["$e$"] (A-3)
            (A-3)   edge["$u$"] (A-4);
\draw[-]    (A-4) -- (A-5);
\draw[arr=red,dashed]   (A-5) node[above] {$y$} -- (out);
%
\coordinate[below=of A-5]   (aux);
\draw[arr] (A-5) -- (aux) -| (A-2.south) 
    node[below left] {$y_m$}
    node[above] {$-$};
    \end{tikzpicture}
\end{document}

ingrese la descripción de la imagen aquí

Respuesta3

Eso era lo que estaba buscando:

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{shapes,arrows}
\begin{document}


\tikzstyle{block} = [draw, fill=blue!20, rectangle, 
    minimum height=3em, minimum width=6em]
\tikzstyle{sum} = [draw, fill=blue!20, circle, node distance=1cm]
\tikzstyle{input} = [coordinate]
\tikzstyle{output} = [coordinate]
\tikzstyle{pinstyle} = [pin edge={to-,thin,black}]

\begin{tikzpicture}[auto, node distance=2cm,>=latex']

    \node [input, name=input] {};
    \node [sum, right of=input] (sum) {};
    \node [block, right of=sum] (controller) {$\frac{0.067\cdot \left(s + 6.51 \right)}{s}  $};
    \node [block, right of=controller, node distance=3cm] (system) {$\frac{357.67}{0.250 \cdot s + 1} \cdot \frac{1}{32}$};

    \draw [->] (controller) -- node[name=u] {$u$} (system);
    \node [output, right of=system] (output) {};
    %\node [block, below of=u] (measurements) {Measurements};
    \coordinate [below of=u] (measurements) {};

    \draw [draw,->] (input) -- node {$r$} (sum);
    \draw [->] (sum) -- node {$e$} (controller);
    \draw [->] (system) -- node [name=y] {$y$}(output);
    \draw [-] (y) |- (measurements);
    \draw [->] (measurements) -| node[pos=1.00] {$-$} 
        node [near end] {$y_m$} (sum);

\end{tikzpicture}

\end{document}

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