problema con multicol y panorama general

Question

La imagen es demasiado alta para permanecer en la primera columna, pero el texto restante se extiende por toda la altura de esta columna. La única forma que he encontrado para evitar este problema es colocar un vacío vboxa cierta altura. Esto no es nada satisfactorio. ¿Cuál es el mejor método?

\documentclass{scrartcl}
\usepackage{tikz}
\usepackage{multicol,lipsum}
\setlength{\columnsep}{24pt}
\setlength{\columnseprule}{0.4pt}

\begin{document}
\begin{multicols*}{2}
   
\section{Contruction with inversion} 

Let us consider the circle $\mathcal{T}$ of center $T$ point common to the circles $\mathcal{A}$ and $\mathcal{B}$ and tangent to the line $(EF)$. It intercepts the two circles at 4 points which define two lines $\mathcal{L_A}$ and $\mathcal{L_B}$ perpendicular to the line $(AB)$.
  
Consider the inversion of center $T$ with respect to the circle $\mathcal{T}$. The circles $\mathcal{A}$ and $\mathcal{B}$ have as inverses the lines $\mathcal{L_A}$ and $\mathcal{L_B}$.
     
The orange circle passing through $T$ and tangent to the circle $\mathcal{T}$ and to the line $(EF)$ is therefore tangent to the line $(EF)$. This circle is therefore tangent to the lines $\mathcal{L_A}$ and $\mathcal{L_B}$ since $(EF)$ is tangent to the circles $\mathcal{A}$ and $\mathcal{B}$.

%\vbox to 10cm{} 

 \begin{tikzpicture}
    \draw (0,0)--(7,15) (0,15)--(7,0);
 \end{tikzpicture} 
 
\lipsum[2]
 \end{multicols*}

\end{document}

Answer 1

Esto agrega suficiente texto para llenar la primera columna y luego usa mi solución vinculada.

\documentclass{scrartcl}
\usepackage{tikz}
\usepackage{multicol,lipsum}
\setlength{\columnsep}{24pt}
\setlength{\columnseprule}{0.4pt}

\makeatletter
\newcommand{\split}[2]% #1 = text, #2 = insert
{\par\bgroup
  \setbox0=\vbox{\strut #1\strut}% measure height
  \sbox1{#2}% ditto
  \dimen0=\dimexpr \pagegoal-\pagetotal-\col@number\baselineskip\relax% fudge factor
  \dimen1=\pagegoal% compute height of one column
  \ifnum\col@number>1\relax
    \divide\dimen1 by \col@number
  \fi
  \advance\dimen1 by -\baselineskip% fudge factor
  \loop\ifdim\dimen0>\dimen1% space left in this column
    \advance\dimen0 by -\dimen1
  \repeat
  \dimen1=\dimexpr \ht1+\dp1+\textfloatsep\relax% space needed for insert
  \ifdim\dimen1>\dimen0
    \ifdim\ht0>\dimen0
      \setbox2=\vsplit0 to \dimen0
      \unvbox2
      \noindent\box1
      \vskip\textfloatsep
      \unvbox0
    \else% entire text will fit into column
      \unvbox0
      \vskip\textfloatsep% probably ignored
      \noindent\box1
      \vskip\textfloatsep
    \fi
  \else% insert will fit into column
    \vskip\intextsep
    \noindent\box1
    \vskip\intextsep
    \unvbox0
  \fi
\egroup\par}
\makeatother

\begin{document}
\begin{multicols*}{2}
   
\section{Contruction with inversion} 

Let us consider the circle $\mathcal{T}$ of center $T$ point common to the circles $\mathcal{A}$ and $\mathcal{B}$ and tangent to the line $(EF)$. It intercepts the two circles at 4 points which define two lines $\mathcal{L_A}$ and $\mathcal{L_B}$ perpendicular to the line $(AB)$.
  
Consider the inversion of center $T$ with respect to the circle $\mathcal{T}$. The circles $\mathcal{A}$ and $\mathcal{B}$ have as inverses the lines $\mathcal{L_A}$ and $\mathcal{L_B}$.
     
The orange circle passing through $T$ and tangent to the circle $\mathcal{T}$ and to the line $(EF)$ is therefore tangent to the line $(EF)$. This circle is therefore tangent to the lines $\mathcal{L_A}$ and $\mathcal{L_B}$ since $(EF)$ is tangent to the circles $\mathcal{A}$ and $\mathcal{B}$.\strut

\split{\lipsum[2-3]}{\noindent\begin{tikzpicture}
    \draw (0,0)--(\columnwidth,15) (0,15)--(\columnwidth,0);
 \end{tikzpicture}}

 \end{multicols*}

\end{document}

---

Si ustedcomograndes brechas, puedes usar

\split{\vfill}{\noindent\begin{tikzpicture}
    \draw (0,0)--(\columnwidth,15) (0,15)--(\columnwidth,0);
\end{tikzpicture}}