Soportes multilínea

Question

Parece que no consigo que el paréntesis envuelva el lado derecho de la igualdad. Recibo el siguiente error: Errores:

./review.tex:239: Extra }, or forgotten \right. [\end{split}]
./review.tex:239: Missing \right. inserted. [\end{split}]
./review.tex:239: Missing } inserted. [\end{split}]
./review.tex:239: Missing } inserted. [\end{split}]
./review.tex:239: Extra \right. [\end{split}]
./review.tex:239: Missing { inserted. [\end{split}]
./review.tex:239: Extra }, or forgotten \right. [\end{split}]
./review.tex:239: Missing \right. inserted. [\end{split}]
./review.tex:239: Missing } inserted. [\end{split}]
./review.tex:239: Missing } inserted. [\end{split}]
./review.tex:239: Extra \right. [\end{split}]
./review.tex:239: Missing { inserted. [\end{split}]

De este código:

\begin{equation}
\begin{split}
\left(\hat{c}_{0}^{\dagger} + \hat{c}_{1}^{\dagger})\hat{t}_{0}^{\dagger} \ket{0000}\otimes\ket{00}= \\
(- c_{0}^{\dagger} c_{1}^{\dagger} + c_{0}^{\dagger} t_{1}^{\dagger} - c_{0}^{\dagger} v_{t}^{\dagger} + c_{1}^{\dagger 2}\\
+ c_{1}^{\dagger} t_{0}^{\dagger} + \sqrt{2} c_{1}^{\dagger} v_{c}^{\dagger} + c_{1}^{\dagger} v_{t}^{\dagger} - \\
t_{0}^{\dagger} t_{1}^{\dagger} + t_{0}^{\dagger} v_{t}^{\dagger} - t_{1}^{\dagger 2} - \sqrt{2} t_{1}^{\dagger} v_{c}^{\dagger}\\
+ t_{1}^{\dagger} v_{t}^{\dagger} + \sqrt{2} v_{c}^{\dagger} v_{t}^{\dagger}\right) \ket{0000}\otimes\ket{00}
\end{split}
\end{equation}

Las declaraciones de una sola línea funcionan; lo he probado.

Aquí está el código de trabajo, sin el paréntesis que necesito.

\begin{equation}
\begin{split}
\hat{c}_{0}^{\dagger} + \hat{c}_{1}^{\dagger})\hat{t}_{0}^{\dagger} \ket{0000}\otimes\ket{00}= \\
(- c_{0}^{\dagger} c_{1}^{\dagger} + c_{0}^{\dagger} t_{1}^{\dagger} - c_{0}^{\dagger} v_{t}^{\dagger} + c_{1}^{\dagger 2}\\
+ c_{1}^{\dagger} t_{0}^{\dagger} + \sqrt{2} c_{1}^{\dagger} v_{c}^{\dagger} + c_{1}^{\dagger} v_{t}^{\dagger} - \\
t_{0}^{\dagger} t_{1}^{\dagger} + t_{0}^{\dagger} v_{t}^{\dagger} - t_{1}^{\dagger 2} - \sqrt{2} t_{1}^{\dagger} v_{c}^{\dagger}\\
+ t_{1}^{\dagger} v_{t}^{\dagger} + \sqrt{2} v_{c}^{\dagger} v_{t}^{\dagger}\ket{0000}\otimes\ket{00}
\end{split}
\end{equation}

Answer 1

Tienes desequilibrados \left... \right(deben estar en la misma línea lógica). Una solución ejemplar, aunque fea:

\documentclass{article}
\usepackage{amsmath,braket}

\begin{document}

\begin{equation}
\begin{split}
%\left(
(\hat{c}_{0}^{\dagger} + \hat{c}_{1}^{\dagger})\hat{t}_{0}^{\dagger} \ket{0000}\otimes\ket{00}= \\
\Bigl(- c_{0}^{\dagger} c_{1}^{\dagger} + c_{0}^{\dagger} t_{1}^{\dagger} - c_{0}^{\dagger} v_{t}^{\dagger} + c_{1}^{\dagger 2}\\
+ c_{1}^{\dagger} t_{0}^{\dagger} + \sqrt{2} c_{1}^{\dagger} v_{c}^{\dagger} + c_{1}^{\dagger} v_{t}^{\dagger} - \\
t_{0}^{\dagger} t_{1}^{\dagger} + t_{0}^{\dagger} v_{t}^{\dagger} - t_{1}^{\dagger 2} - \sqrt{2} t_{1}^{\dagger} v_{c}^{\dagger}\\
+ t_{1}^{\dagger} v_{t}^{\dagger} + \sqrt{2} v_{c}^{\dagger} v_{t}^{\dagger}
%\right)
\Bigr)
 \ket{0000}\otimes\ket{00}
\end{split}
\end{equation}


\end{document}

Answer 2

Además de la respuesta de Przemysław, la hice un poco más bonita. No necesitas ese gran paréntesis en absoluto. Si desea utilizar un corchete automatizado como \left(, debe "cerrarlo" \right.en la misma línea.

Aquí está mi MWE. Incluso podrías reducir una fila. Hay suficiente espacio para ampliar un poco la ecuación:

% arara: pdflatex

\documentclass{article}
\usepackage{mathtools}
\usepackage{braket}
\newcommand*{\myStrut}{\vphantom{1}}

\begin{document}
\begin{equation}
    \begin{split}
        (\hat{c}_{0}^{\dagger} + \hat{c}_{1}^{\dagger})\hat{t}_{0}^{\dagger} \ket{0000}\otimes\ket{00} &= (c_{0}^{\dagger} t_{1}^{\dagger} - c_{0}^{\dagger} c_{1}^{\dagger} - c_{0}^{\dagger} v_{t}^{\dagger} + c_{1}^{\dagger\,2} + c_{1}^{\dagger} t_{0}^{\dagger} \\
        &\qquad+ \sqrt{2} c_{1}^{\dagger} v_{c\myStrut}^{\dagger} + c_{1}^{\dagger} v_{t}^{\dagger} - t_{0}^{\dagger} t_{1}^{\dagger} + t_{0}^{\dagger} v_{t}^{\dagger} - t_{1}^{\dagger\,2} \\ 
        &\qquad- \sqrt{2} t_{1}^{\dagger} v_{c\myStrut}^{\dagger} + t_{1}^{\dagger} v_{t}^{\dagger} \\
        &\qquad+ \sqrt{2} v_{c\myStrut}^{\dagger} v_{t}^{\dagger}) \ket{0000}\otimes\ket{00}
    \end{split}
\end{equation}
\end{document}

Answer 3

Puede tener corchetes de varias líneas, siguiendo el ejemplo de Sébastien Gouezel en po. 28-29 de la mathtoolsdocumentación. Además, propongo otra alineación basada en el alignedatmedio ambiente:

\documentclass{article}
\usepackage[showframe]{geometry}
\usepackage{mathtools} %
\usepackage{braket}

\newcommand\MTkillspecial[1]{% helper macro
\bgroup
\catcode`\&=9
\let\\\relax%
\scantokens{#1}%
\egroup
}
\DeclarePairedDelimiter\mlparen\lparen\rparen
\reDeclarePairedDelimiterInnerWrapper\mlparen{star}{
\mathopen{#1\vphantom{\MTkillspecial{#2}}\kern-\nulldelimiterspace\right.}
#2
\mathclose{\left.\kern-\nulldelimiterspace\vphantom{\MTkillspecial{#2}}#3}}

\begin{document}

\begin{equation}
\begin{alignedat}{2}
\bigr(\hat{c}_{0}^{\dagger} + \hat{c}_{1}^{\dagger}\bigr)\hat{t}_{0}^{\dagger} \ket{0000}\otimes\ket{00} & =
{}&\mlparen[\big]{& {- c_{0}}^{\dagger} c_{1}^{\dagger} + c_{0}^{\dagger} t_{1}^{\dagger} - c_{0}^{\dagger} v_{t}^{\dagger} + c_{1}^{\dagger 2} + c_{1}^{\dagger} t_{0}^{\dagger} \\
& &&\! + √{2} c_{1}^{\dagger} v_{c}^{\dagger} + c_{1}^{\dagger} v_{t}^{\dagger} - t_{0}^{\dagger} t_{1}^{\dagger} + t_{0}^{\dagger} v_{t}^{\dagger} - t_{1}^{\dagger 2} \\
& & &\! - √{2} t_{1}^{\dagger} v_{c}^{\dagger}+ t_{1}^{\dagger} v_{t}^{\dagger} + √{2} v_{c}^{\dagger} v_{t}^{\dagger}} \ket{0000}\otimes\ket{00}
\end{alignedat}
\end{equation}

\end{document}