
\begin{align}
\mathcal{L}_{\lambda} = u_{1}(h) - u_{1}(h^{*}) + T \geq 0 \text{(foc$\lambda$)}, \label{eqn:foca1}\\
\mathcal{L}_{T} = -1 + \lambda = 0 \Leftrightarrow \lambda = 1 \text{(focT)} ,\label{eqn:focb1}\\
\mathcal{L}_{h} =- u'_{2}(h) + \lambda u'_{1}(h) = 0 \Leftrightarrow \lambda = \frac{u'_{2}(h)}{u'_{1}(h)} \text{(foch)}.\label{eqn:focc1}\\
\lambda \geq 0 \text{(nn)}, \label{eqn:focd1}\\
\lambda \mathcal{L}_{\lambda} = \lambda [u_{1}(h) - u_{1}(h^{*}) + T] = 0 \text{(cs$\lambda$)} .\label{eqn:foce1}
\end{align}
그것이 타당하다면 반대편에 방정식 번호로 foc$\lambda$, \text{(focT)} 등을 갖고 싶습니까?
답변1
다음 명령을 사용할 수 있습니다 \tag
. 대괄호가 제공됩니다 ()
.
전체 MWE는 다음과 같습니다.
\documentclass{amsart}
\begin{document}
\begin{align}
\mathcal{L}_{\lambda} = u_{1}(h) - u_{1}(h^{*}) + T \geq 0,
\tag{\text{foc$\lambda$}} \label{eqn:foca1}\\
\mathcal{L}_{T} = -1 + \lambda = 0 \Leftrightarrow \lambda = 1,
\tag{\text{focT}}\label{eqn:focb1}\\
\mathcal{L}_{h} =- u'_{2}(h) + \lambda u'_{1}(h) = 0 \Leftrightarrow \lambda = \frac{u'_{2}(h)}{u'_{1}(h)},
\tag{\text{foch}}\label{eqn:focc1}\\
\lambda \geq 0, \tag{\text{nn}}\label{eqn:focd1}\\
\lambda \mathcal{L}_{\lambda} = \lambda [u_{1}(h) - u_{1}(h^{*}) + T] = 0.
\tag{\text{cs$\lambda$}}\label{eqn:foce1}
\end{align}
By \eqref{eqn:foca1}.
\end{document}