![라벨링 및 정렬의 정확성](https://rvso.com/image/305754/%EB%9D%BC%EB%B2%A8%EB%A7%81%20%EB%B0%8F%20%EC%A0%95%EB%A0%AC%EC%9D%98%20%EC%A0%95%ED%99%95%EC%84%B1.png)
(1). 그림은 중앙에 위치해야 합니다. (2). 포인트 Z
, X
및 는 Y
적절하게 라벨이 지정되어야 합니다. (포인트가 있어야 할 위치에서 멀리 떨어져 있습니다.
\documentclass[11pt,a4paper]{article}
\usepackage{blindtext}
\usepackage{tikz}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usepackage{color}
\begin{document}
\normalsize{\textbf{Theorem 1.24.} \textit{The bisectors of the angles of a triangle meet in a point which is equally distant from the sides.}}
\begin{center}
\begin{tikzpicture}
\tkzDefPoint(0,0){A}
\tkzDefPoint(12,0){B}
\tkzLabelPoints[below](A)
\tkzLabelPoints[below](B)
\tkzDrawSegment(A,B)
\tkzDefPoint(3,7){C}
\tkzLabelPoints[above](C)
\tkzDrawSegment(A,C)
\tkzDrawSegment(B,C)
\tkzDefLine[bisector](A,C,B)\tkzGetPoint{Z}
\tkzDrawSegment[add=0pt and -150pt](C,Z)
\tkzLabelPoints[xshift=-10pt](Z)
\tkzDefLine[bisector](C,A,B)\tkzGetPoint{Y}
\tkzDrawSegment[add=0pt and -280pt](A,Y)
\tkzLabelPoints[xshift=-10pt](Y)
\tkzDefLine[bisector](C,B,A)\tkzGetPoint{X}
\tkzDrawSegment[add=0pt and -280pt](B,X)
\tkzLabelPoints[xshift=-10pt](X)
\end{tikzpicture}
\end{center}
\end{document}
답변1
이미 초기 버전이 있었지만 댓글에 따르면 의도는 달랐습니다. 어쨌든 나는 여기에 두 버전을 모두 포함하기로 결정했습니다.
\documentclass[11pt,a4paper]{article}
\usepackage{tkz-euclide}
\usetkzobj{all}
\begin{document}
\begin{center}
\begin{tikzpicture}[scale=0.75]
\tkzDefPoint(0,0){A}
\tkzDefPoint(12,0){B}
\tkzLabelPoints[below](A)
\tkzLabelPoints[below](B)
\tkzDrawSegment(A,B)
\tkzDefPoint(3,7){C}
\tkzLabelPoints[above](C)
\tkzDrawSegment(A,C)
\tkzDrawSegment(B,C)
\tkzDrawBisector[dashed,draw=gray](C,B,A)
\tkzGetPoint{X}
\tkzLabelPoints[left](X)
\tkzDrawBisector(A,C,B)
\tkzGetPoint{Z}
\tkzLabelPoints[below](Z)
\tkzDrawBisector(C,A,B)
\tkzGetPoint{Y}
\tkzLabelPoints[above right](Y)
\tkzInterLL(A,Y)(C,Z)
\tkzGetPoint{P}
\tkzLabelPoints[left](P)
\tkzDrawSegment[add=0pt and -20pt](B,P)
\end{tikzpicture}
\end{center}
\begin{center}
\begin{tikzpicture}[scale=0.75]
\clip
(-1,-3) rectangle (13,8);
\tkzDefPoint(0,0){A}
\tkzDefPoint(12,0){B}
\tkzLabelPoints[below](A)
\tkzLabelPoints[below](B)
\tkzDrawSegment(A,B)
\tkzDefPoint(3,7){C}
\tkzLabelPoints[above](C)
\tkzDrawSegment(A,C)
\tkzDrawSegment(B,C)
\tkzDefLine[bisector](A,C,B)
\tkzGetPoint{Z}
\tkzDrawSegment[add=0pt and -150pt](C,Z)
\tkzDefLine[bisector](B,A,C)
\tkzGetPoint{Y}
\tkzDrawSegment[add=0pt and -320pt](A,Y)
\tkzDefLine[bisector](C,B,A)
\tkzGetPoint{X}
\tkzDrawSegment[add=0pt and -300pt](B,X)
\tkzInterLL(A,Y)(C,Z)
\tkzGetPoint{P}
\tkzLabelPoints[left](P)
\tkzLabelLine[pos=0.65](C,Z){Z}
\tkzLabelLine[pos=0.40](B,X){X}
\tkzLabelLine[pos=0.50](A,Y){Y}
\end{tikzpicture}
\end{center}
\end{document}
결과: