\lstinline의 C++ 연산자('::', '->', ...)에서 줄 바꿈 허용

Question

다음 그림은 내 문제를 보여줍니다.

\lstinline특정 C++ 연산자에서 줄 바꿈을 어떻게 알 수 있나요 ? 예를 들어 FooFactory::instance()->createFoo()다음과 같이 나누어야 합니다.

... text   FooFactory::
instance()->createFoo()

또는

FooFactory::instance()->
createFoo() text text ...

MWE:

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[left=6cm,right=7cm]{geometry}
\usepackage{parskip}
\usepackage{showframe}
\usepackage{listings}

\lstset{
    language=C++,
    basicstyle=\ttfamily,
    breaklines=true,
    breakatwhitespace=true,
    inputencoding=utf8,
    extendedchars=true
}
\lstset{literate=% I dont know what I am doing...
    {::}{::}{1\discretionary{}{}{}} % line-break at ::
    {->}{->}{1\discretionary{}{}{}} % line-break at ->
}

\begin{document}

text text text text text text text text \lstinline{FooFactory::instance()->createFoo()} text text
text text text text 

text text text text text text \lstinline{FooFactory::instance()->createFoo()} text text
text text text text 

\end{document}

Answer 1

이것이 왜 작동하는지 이해하지 못합니다. 보다 정확하게는 대체 텍스트 내부 대신 숫자 뒤에 \discretionary를 넣어야 하는 이유를 모르겠습니다.

\documentclass{article}
%\usepackage[utf8]{inputenc}% all it does for me is produce warnings
\usepackage[left=6cm,right=7cm]{geometry}
\usepackage{parskip}
\usepackage{showframe}
\usepackage{listings}

\lstset{
    language=C++,
    basicstyle=\ttfamily,
    breaklines=true,
    breakatwhitespace=true,
    inputencoding=utf8,
    extendedchars=true
    }
\lstset{literate={::}{}{0\discretionary{::}{}{::}}% line-break at ::
   {->}{}{0\discretionary{->}{}{->}}% line-break at ->
}
\begin{document}

text text text text text text text text  \lstinline{FooFactory::instance()->createFoo()} text text text text text text 

text text text text text text \lstinline{FooFactory::instance()->createFoo()} text text text text text text 

\begin{lstlisting}
    FooFactory::instance()->createFoo();
\end{lstlisting}

\end{document}