수학 함수 정의

Question

\documentclass[aspectratio=1610]{beamer} 
\usepackage{amsmath} 

\begin{document} 
\def\function(#1){ 96* (#1)-16 *(#1)^2 } 

%1. I am trying to condense the following two lines

\pgfmathparse{3+\function(1)}
\let\z\pgfmathresult
z result is \z  %


 %2.  I would like  store the result of the previous line in a 'variable'

 %The following doesn't work 

\def\myfp(#1,#2){\pgfmathparse{#1} \let\#2\pgfmathresult}
\myfp(3+ \function(1),\z)  

% /This yields the right answer BUT  z Result is \z   ..... Yields error 



%3. Why does the following mess up%

\let\z7\pgfmathresult

z7 result is {\z7} 

%4. PLEASE point me to relevant documentation!
\end{document}

Answer 1

질문을 이해했는지 잘 모르겠습니다. 그러나 매크로를 호출하려는 경우에는 \z7매크로 이름에 숫자가 포함될 수 없기 때문에 작동하지 않습니다. 그리고 도착하려면 백슬래시를 제거해야 했습니다.

\documentclass[aspectratio=1610]{beamer} 
\usepackage{amsmath} 

\begin{document} 
\def\function(#1){ 96* (#1)-16 *(#1)^2 } 

%1. I am trying to condense the following two lines

\pgfmathparse{3+\function(1)}
\let\z\pgfmathresult
z result is \z  %


 %2.  I would like  store the result of the previous line in a 'variable'

 %The following doesn't work 

\def\myfp(#1,#2){\pgfmathparse{#1} \let#2\pgfmathresult} % <removed \ before #2
\myfp(3+ \function(1),\z)  

% /This yields the right answer BUT  z Result is \z   ..... Yields error 



%3. Why does the following mess up%

%\pgfmathparse{\z*7}
\let\zseven\pgfmathresult

z7 result is {\zseven} 

%4. PLEASE point me to relevant documentation!
\end{document}