매우 유용한 이 코드를 실행했지만 코드를 실행할 때 모든 노드에 관한 오류가 발생했습니다.(예를 들어 이름이 지정된 모양이 없습니다 A-2-1), 노드에 레이블이 지정된 방식이 다른 코드와 잘 작동하기 때문에 문제가 무엇인지 모르겠습니다. 여기서 문제가 무엇인지 아시나요?
% Author : Alain Matthes
% Source : http://altermundus.com/pages/examples.html
\documentclass[]{article}
\usepackage[utf8]{inputenc}
\usepackage[upright]{fourier}
\usepackage{tikz}
\usetikzlibrary{matrix,arrows,decorations.pathmorphing}
\begin{document}
% l' unite
\newcommand{\myunit}{1 cm}
\tikzset{
node style sp/.style={draw,circle,minimum size=\myunit},
node style ge/.style={circle,minimum size=\myunit},
arrow style mul/.style={draw,sloped,midway,fill=white},
arrow style plus/.style={midway,sloped,fill=white},
}
\begin{tikzpicture}[>=latex]
% les matrices
\matrix(A)[matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (0,0)
{%
a_{11} & a_{12} & \ldots & a_{1p} \\
\node[node style sp] {a_{21}};%
& \node[node style sp] {a_{22}};%
& \ldots%
& \node[node style sp] {a_{2p}}; \\
\vdots & \vdots & \ddots & \vdots \\
a_{n1} & a_{n2} & \ldots & a_{np} \\
};
\node [draw,below=10pt] at (A.south)
{ $A$ : \textcolor{red}{$n$ rows} $p$ columns};
\matrix (B) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter =)] at (6*\myunit,6*\myunit)
{%
b_{11} & \node[node style sp] {b_{12}};%
& \ldots & b_{1q} \\
b_{21} & \node[node style sp] {b_{22}};%
& \ldots & b_{2q} \\
\vdots & \vdots & \ddots & \vdots \\
b_{p1} & \node[node style sp] {b_{p2}};%
& \ldots & b_{pq} \\
};
\node [draw,above=10pt] at (B.north)
{ $B$ : $p$ rows \textcolor{red}{$q$ columns}};
% matrice résultat
\matrix (C) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (6*\myunit,0)
{%
c_{11} & c_{12} & \ldots & c_{1q} \\
c_{21} & \node[node style sp,red] {c_{22}};%
& \ldots & c_{2q} \\
\vdots & \vdots & \ddots & \vdots \\
c_{n1} & c_{n2} & \ldots & c_{nq} \\
};
% les fleches
\draw[blue] (A-2-1.north) -- (C-2-2.north);
\draw[blue] (A-2-1.south) -- (C-2-2.south);
\draw[blue] (B-1-2.west) -- (C-2-2.west);
\draw[blue] (B-1-2.east) -- (C-2-2.east);
\draw[<->,red](A-2-1) to[in=180,out=90]
node[arrow style mul] (x) {$a_{21}\times b_{12}$} (B-1-2);
\draw[<->,red](A-2-2) to[in=180,out=90]
node[arrow style mul] (y) {$a_{22}\times b_{22}$} (B-2-2);
\draw[<->,red](A-2-4) to[in=180,out=90]
node[arrow style mul] (z) {$a_{2p}\times b_{p2}$} (B-4-2);
\draw[red,->] (x) to node[arrow style plus] {$+$} (y)%
to node[arrow style plus] {$+\raisebox{.5ex}{\ldots}+$} (z)%
to (C-2-2.north west);
\node [draw,below=10pt] at (C.south)
{$ C=A\times B$ : \textcolor{red}{$n$ rows} \textcolor{red}{$q$ columns}};
\end{tikzpicture}
\begin{tikzpicture}[>=latex]
% unit
% defintion of matrices
\matrix (A) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (0,0)
{%
a_{11} &\ldots & a_{1k} & \ldots & a_{1p} \\
\vdots & \ddots & \vdots & \vdots & \vdots \\
\node[node style sp] {a_{i1}};& \ldots%
& \node[node style sp] {a_{ik}};%
& \ldots%
& \node[node style sp] {a_{ip}}; \\
\vdots & \vdots& \vdots & \ddots & \vdots \\
a_{n1}& \ldots & a_{nk} & \ldots & a_{np} \\
};
\node [draw,below] at (A.south) { $A$ : \textcolor{red}{$n$ rows} $p$ columns};
\matrix (B) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter =)] at (7*\myunit,7*\myunit)
{%
b_{11} & \ldots& \node[node style sp] {b_{1j}};%
& \ldots & b_{1q} \\
\vdots& \ddots & \vdots & \vdots & \vdots \\
b_{k1} & \ldots& \node[node style sp] {b_{kj}};%
& \ldots & b_{kq} \\
\vdots& \vdots & \vdots & \ddots & \vdots \\
b_{p1} & \ldots& \node[node style sp] {b_{pj}};%
& \ldots & b_{pq} \\
};
\node [draw,above] at (B.north) { $B$ : $p$ rows \textcolor{red}{$q$ columns}};
% matrice resultat
\matrix (C) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (7*\myunit,0)
{%
c_{11} & \ldots& c_{1j} & \ldots & c_{1q} \\
\vdots& \ddots & \vdots & \vdots & \vdots \\
c_{i1}& \ldots & \node[node style sp,red] {c_{ij}};%
& \ldots & c_{iq} \\
\vdots& \vdots & \vdots & \ddots & \vdots \\
c_{n1}& \ldots & c_{nk} & \ldots & c_{nq} \\
};
\node [draw,below] at (C.south)
{$ C=A\times B$ : \textcolor{red}{$n$ rows} \textcolor{red}{$q$ columns}};
% arrows
\draw[blue] (A-3-1.north) -- (C-3-3.north);
\draw[blue] (A-3-1.south) -- (C-3-3.south);
\draw[blue] (B-1-3.west) -- (C-3-3.west);
\draw[blue] (B-1-3.east) -- (C-3-3.east);
\draw[<->,red](A-3-1) to[in=180,out=90]
node[arrow style mul] (x) {$a_{i1}\times b_{1j}$} (B-1-3);
\draw[<->,red](A-3-3) to[in=180,out=90]
node[arrow style mul] (y) {$a_{ik}\times b_{kj}$}(B-3-3);
\draw[<->,red](A-3-5) to[in=180,out=90]
node[arrow style mul] (z) {$a_{ip}\times b_{pj}$}(B-5-3);
\draw[red,->] (x) to node[arrow style plus] {$+\raisebox{.5ex}{\ldots}+$} (y)%
to node[arrow style plus] {$+\raisebox{.5ex}{\ldots}+$} (z);
%
% to (C-3-3.north west);
\draw[->,red,decorate,decoration=zigzag] (z) -- (C-3-3.north west);
\end{tikzpicture}
\end{document}
답변1
대신 다음 \node[node style sp] {a_{21}};을 작성하십시오 |[node style sp]| {a_{21}}.
\documentclass[]{article}
\usepackage[utf8]{inputenc}
\usepackage[upright]{fourier}
\usepackage{tikz}
\usetikzlibrary{arrows,matrix,decorations.pathmorphing}
\begin{document}
% l' unite
\newcommand{\myunit}{1 cm}
\tikzset{
node style sp/.style={draw,circle,minimum size=\myunit},
node style ge/.style={circle,minimum size=\myunit},
arrow style mul/.style={draw,sloped,midway,fill=white},
arrow style plus/.style={midway,sloped,fill=white},
}
\begin{tikzpicture}[>=latex]
% les matrices
\matrix (A) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )]
{%
a_{11} & a_{12} & \ldots & a_{1p} \\
|[node style sp]| {a_{21}}%
& |[node style sp]| {a_{22}}%
& \ldots%
& |[node style sp]| {a_{2p}} \\
\vdots & \vdots & \ddots & \vdots \\
a_{n1} & a_{n2} & \ldots & a_{np} \\
};
\node [draw,below=10pt] at (A.south)
{ $A$ : \textcolor{red}{$n$ rows} $p$ columns};
\matrix (B) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter =)] at (6*\myunit,6*\myunit)
{%
b_{11} & |[node style sp]| {b_{12}}%
& \ldots & b_{1q} \\
b_{21} & |[node style sp]| {b_{22}}%
& \ldots & b_{2q} \\
\vdots & \vdots & \ddots & \vdots \\
b_{p1} & |[node style sp]| {b_{p2}}%
& \ldots & b_{pq} \\
};
\node [draw,above=10pt] at (B.north)
{ $B$ : $p$ rows \textcolor{red}{$q$ columns}};
% matrice resultat
\matrix (C) [matrix of math nodes,%
nodes = {node style ge},%
left delimiter = (,%
right delimiter = )] at (6*\myunit,0)
{%
c_{11} & c_{12} & \ldots & c_{1q} \\
c_{21} & |[node style sp,red]| {c_{22}}%
& \ldots & c_{2q} \\
\vdots & \vdots & \ddots & \vdots \\
c_{n1} & c_{n2} & \ldots & c_{nq} \\
};
% les fleches
\draw[blue] (A-2-1.north) -- (C-2-2.north);
\draw[blue] (A-2-1.south) -- (C-2-2.south);
\draw[blue] (B-1-2.west) -- (C-2-2.west);
\draw[blue] (B-1-2.east) -- (C-2-2.east);
\draw[<->,red](A-2-1) to[in=180,out=90]
node[arrow style mul] (x) {$a_{21}\times b_{12}$} (B-1-2);
\draw[<->,red](A-2-2) to[in=180,out=90]
node[arrow style mul] (y) {$a_{22}\times b_{22}$} (B-2-2);
\draw[<->,red](A-2-4) to[in=180,out=90]
node[arrow style mul] (z) {$a_{2p}\times b_{p2}$} (B-4-2);
\draw[red,->] (x) to node[arrow style plus] {$+$} (y)%
to node[arrow style plus] {$+\raisebox{.5ex}{\ldots}+$} (z)%
to (C-2-2.north west);
\node [draw,below=10pt] at (C.south)
{$ C=A\times B$ : \textcolor{red}{$n$ rows} \textcolor{red}{$q$ columns}};
\end{tikzpicture}
\end{document}
답변2
행렬은 이미 다음과 같은 노드 집합으로 정의됩니다.
\matrix(A)[matrix of math nodes,%
따라서 아래의 두 번째 명령은 잘못된 첫 번째 노드 내에 노드를 중첩합니다.
\node[node style sp] {a_{21}};%
따라서 이 작업을 수행하려는 경우 주 행렬(A)에 대한 A-2-1이 아닌 다른 별칭을 사용하여 두 번째 /중첩 노드를 호출해야 합니다.
두 번째 중첩 노드에 별도의 이름(A-2-1)을 지정했습니다. 마찬가지로 행렬(C)의 경우 (C-2-2)에 있는 두 번째 중첩 노드에도 별도의 이름이 지정됩니다.
이제 이 두 노드 사이에 draw 명령을 사용하면 오류가 없습니다.
\draw[blue] (A-2-1.north) -- (C-2-2.north);
결과는 아래와 같습니다.
아래 링크에 설명된 대로 별칭을 사용할 수도 있습니다 ==