바닥 버팀대 stix 2가 제대로 표시되지 않음

Question

\documentclass[12pt]{article}
\usepackage{amsthm,amsmath,ragged2e,relsize,graphicx,bbm,mathtools}

\DeclareFontEncoding{LS1}{}{}
\DeclareFontEncoding{LS2}{}{\noaccents@}
\DeclareFontSubstitution{LS1}{stix2}{m}{n}
\DeclareFontSubstitution{LS2}{stix2}{m}{n}
\DeclareSymbolFont{xsymbols}{LS1}{stix2scr}{m}{n}
\DeclareSymbolFont{xlargesymbols}{LS2}{stix2ex}{m}{n}
\DeclareMathDelimiter{\lfloor}{\mathopen}{symbols}{"E2}{xlargesymbols}{"08}
\DeclareMathDelimiter{\rfloor}{\mathclose}{symbols}{"E3}{xlargesymbols}{"09}

\begin{document}
Why am i not getting $\lfloor x\rfloor$ properly?
\end{document}

pdflatex를 실행할 때 바닥 기호가 출력되지 않습니다. 여기에 출력을 첨부하고 있습니다.도와주세요.

Answer 1

당신은 얻는다

Missing character: There is no <E2> in font cmsy10!
Missing character: There is no <E3> in font cmsy10!

오타가 있기 때문에: symbols대신 largesymbols. 즉, STIX2의 글리프를 사용한다고 가정합니다. \makeatletter때문에 잊지 마세요 \noaccents@.

\documentclass[12pt]{article}
\usepackage{amsthm,amsmath,ragged2e,relsize,graphicx,bbm,mathtools}

\makeatletter
%\DeclareFontEncoding{LS1}{}{}
\DeclareFontEncoding{LS2}{}{\noaccents@}
\makeatother
%\DeclareFontSubstitution{LS1}{stix2}{m}{n}
\DeclareFontSubstitution{LS2}{stix2}{m}{n}
%\DeclareSymbolFont{xsymbols}{LS1}{stix2scr}{m}{n}
\DeclareSymbolFont{xlargesymbols}{LS2}{stix2ex}{m}{n}
\DeclareMathDelimiter{\lfloor}{\mathopen}{xlargesymbols}{"E2}{xlargesymbols}{"08}
\DeclareMathDelimiter{\rfloor}{\mathclose}{xlargesymbols}{"E3}{xlargesymbols}{"09}

\begin{document}

I am getting $\lfloor x\rfloor$ properly.

\end{document}

also \lbraceand를 사용합니다 \rbrace(그러나 실제로는 다른 글꼴과 일치하지 않습니다).

\documentclass{article}
\usepackage{amsthm,amsmath,ragged2e,relsize,graphicx,bbm,mathtools}

\makeatletter
\DeclareFontEncoding{LS1}{}{}
\DeclareFontEncoding{LS2}{}{\noaccents@}
\makeatother
\DeclareFontSubstitution{LS1}{stix2}{m}{n}
\DeclareFontSubstitution{LS2}{stix2}{m}{n}
\DeclareSymbolFont{stixoperators}{LS1}{stix2}{m}{n}
%\DeclareSymbolFont{stixsymbols}{LS1}{stix2scr}{m}{n}
\DeclareSymbolFont{stixlargesymbols}{LS2}{stix2ex}{m}{n}
\DeclareMathDelimiter{\lfloor}{\mathopen}{stixlargesymbols}{"E2}{stixlargesymbols}{"08}
\DeclareMathDelimiter{\rfloor}{\mathclose}{stixlargesymbols}{"E3}{stixlargesymbols}{"09}
\DeclareMathDelimiter{\lbrace}{\mathopen} {stixoperators}{"5E}{stixlargesymbols}{"0C}
\DeclareMathDelimiter{\rbrace}{\mathclose}{stixoperators}{"60}{stixlargesymbols}{"0D}

\begin{document}

I am getting $\lfloor x\rfloor$ properly.

I am getting $\lbrace x\rbrace$ properly.

I am getting $\{x\}$ properly.

\bigskip

$
\biggl\{\biggl\lfloor \Bigl\{\Bigl\lfloor \bigl\{\bigl\lfloor \{\lfloor
%
\biggl\rfloor\biggl\} \Bigl\rfloor\Bigl\} \bigl\rfloor\bigl\} \rfloor\}
$

\end{document}

\Big예, 에서 로 큰 도약이 있습니다 \bigg. 요소를 조금 줄여야 합니다. 운동으로 남았습니다.

Answer 2

\lfloor선언 하고 다시 할 필요가 없습니다 \rfloor. 이미 존재합니다. Pdflatex는 여기서 문제가 되지 않습니다.

\documentclass[12pt]{article}
\usepackage{amsthm,amsmath,ragged2e,relsize,graphicx,bbm,mathtools}

\DeclareFontEncoding{LS1}{}{}
\DeclareFontEncoding{LS2}{}{\noaccents@}
\DeclareFontSubstitution{LS1}{stix2}{m}{n}
\DeclareFontSubstitution{LS2}{stix2}{m}{n}
\DeclareSymbolFont{xsymbols}{LS1}{stix2scr}{m}{n}
\DeclareSymbolFont{xlargesymbols}{LS2}{stix2ex}{m}{n}
% \DeclareMathDelimiter{\lfloor}{\mathopen}{symbols}{"E2}{xlargesymbols}{"08} <- Not necessary
% \DeclareMathDelimiter{\rfloor}{\mathclose}{symbols}{"E3}{xlargesymbols}{"09} <- Not necessary

\begin{document}
Why am i not getting $\lfloor x\rfloor$ properly?
\end{document}

생산하다

그런데 다음이 필요합니다.

\documentclass{article}

\begin{document}
    You can get $\lfloor x \rfloor$ properly.
\end{document}

획득하다