테이블 형식(LaTeX)의 달러 기호의 Textbf

Question

나는 한동안 LaTeX Overleaf(overleaf.com)를 사용하여 삼각법 테이블을 만들려고 노력해 왔습니다. 표의 첫 번째 줄에서 첫 번째 셀에 알파를 굵게 표시하려고 했지만 달러 기호 안에 넣으면 오류가 많이 발생하고 PDF 변환기가 충돌하게 됩니다. 달러 기호 바깥쪽에 넣으면 \textbf알파가 굵게 표시되지 않습니다. 누구든지 이 문제를 해결하도록 도와주실 수 있나요? 감사합니다! 내 코드는 이 단락 아래에 있습니다.

\begin{tabular}{||c|c|c|c||c|c|c||}
\hline
\hline
$\textbf{\alpha}$ &sin($\alpha$) &cos($\alpha$) &tan($\alpha$) &cosec($\alpha$) &sec($\alpha$) &cot($\alpha$)\\
\hline
\hline
\textbf{0}$^\circ$ & $\textbf{0}$ &$\textbf{1}$ &$\textbf{0}$ &\textbf{undefined} &$\textbf{1}$ &\textbf{undefined}\\
\hline
\hline
$15^\circ$ &$\frac{\sqrt{6}-\sqrt{2}}{4}$ &$\frac{\sqrt{6}+\sqrt{2}}{4}$ &$2-\sqrt{3}$ &$\sqrt{6}+\sqrt{2}$ &$\sqrt{6}-\sqrt{2}$ &$2+\sqrt{3}$\\
\hline
$30^\circ$ &$\frac{1}{2}$ &$\frac{\sqrt{3}}{2}$ &$\frac{\sqrt{3}}{3}$ &$2$ &$\frac{2\sqrt{3}}{3}$ &$\sqrt{3}$\\
\hline
$45^\circ$ &$\frac{\sqrt{2}}{2}$ &$\frac{\sqrt{2}}{2}$ &$1$ &$\sqrt{2}$ &$\sqrt{2}$ &$1$\\
\hline
$60^\circ$ &$\frac{\sqrt{3}}{2}$ &$\frac{1}{2}$ &$\sqrt{3}$ &$\frac{2\sqrt{3}}{3}$ &$2$ &$\frac{\sqrt{3}}{3}$\\
\hline
$75^\circ$ &$\frac{\sqrt{6}+\sqrt{2}}{4}$ &$\frac{\sqrt{6}-\sqrt{2}}{4}$ &$2+\sqrt{3}$ &$\sqrt{6}-\sqrt{2}$ &$\sqrt{6}+\sqrt{2}$ &$2-\sqrt{3}$\\
\hline
\hline
$90^\circ$ &$1$ &$0$ &undefined &$1$ &undefined &$0$\\
\hline
\hline
$105^\circ$ &$\frac{\sqrt{6}+{\sqrt{2}}}{4}$ &$\frac{\sqrt{2}-\sqrt{6}}{4}$ &$-2-\sqrt{3}$ &$\sqrt{6}-\sqrt{2}$ &$-\sqrt{6}-\sqrt{2}$ &$\sqrt{3}-2$\\
\hline
$120^\circ$ &$\frac{\sqrt{3}}{2}$ &$-\frac{1}{2}$ &$-\sqrt{3}$ &$\frac{2\sqrt{3}}{3}$ &$-2$ &$-\frac{\sqrt{3}}{3}$\\
\hline
$135^\circ$ &$\frac{\sqrt{2}}{2}$ &$-\frac{\sqrt{2}}{2}$ &$-1$ &$\sqrt{2}$ &$-\sqrt{2}$ &$-1$\\
\hline
$150^\circ$ &$\frac{1}{2}$ &$-\frac{\sqrt{3}}{2}$ &$-\frac{\sqrt{3}}{3}$ &$2$ &$-\frac{2\sqrt{3}}{3}$ &$-\sqrt{3}$\\
\hline
$165^\circ$ &$\frac{\sqrt{6}-\sqrt{2}}{4}$ &$\frac{-\sqrt{6}-\sqrt{2}}{4}$ &$\sqrt{3}-2$ &$\sqrt{6}+\sqrt{2}$ &$\sqrt{2}-\sqrt{6}$ &$-2-\sqrt{3}$\\
\hline
\hline
$180^\circ$ &$0$ &$-1$ &$0$ &undefined &$-1$ &undefined\\
\hline
\hline
$195^\circ$ &$\frac{\sqrt{2}-\sqrt{6}}{4}$ &$\frac{-\sqrt{6}-\sqrt{2}}{4}$ &$2-\sqrt{3}$ &$-\sqrt{6}-\sqrt{2}$ &$\sqrt{2}-\sqrt{6}$ &$2+\sqrt{3}$\\
\hline
$210^\circ$ &$-\frac{1}{2}$ &$-\frac{\sqrt{3}}{2}$ &$\frac{\sqrt{3}}{3}$ &$-2$ &$-\frac{2\sqrt{3}}{3}$ &$\sqrt{3}$\\
\hline
$225^\circ$ &$-\frac{\sqrt{2}}{2}$ &$-\frac{\sqrt{2}}{2}$ &$1$ &$-\sqrt{2}$ &$-\sqrt{2}$ &$1$\\
\hline
$240^\circ$ &$-\frac{\sqrt{3}}{2}$ &$-\frac{1}{2}$ &$\sqrt{3}$ &$-\frac{2\sqrt{3}}{3}$ &$-2$ &$\frac{\sqrt{3}}{3}$\\
\hline
$255^\circ$ &$\frac{-\sqrt{6}-\sqrt{2}}{4}$ &$\frac{\sqrt{2}-\sqrt{6}}{4}$ &$2+\sqrt{3}$ &$\sqrt{6}-\sqrt{2}$ &$-\sqrt{6}-\sqrt{2}$ &$2-\sqrt{3}$\\
\hline
\hline
$270^\circ$ &$-1$ &$0$ &undefined &$1$ &undefined &$0$\\
\hline
\hline
$285^\circ$ &$\frac{-\sqrt{6}-\sqrt{2}}{4}$ &$\frac{\sqrt{6}-\sqrt{2}}{4}$ &$-2-\sqrt{3}$ &$\sqrt{2}-\sqrt{6}$ &$\sqrt{2}+\sqrt{6}$ &$\sqrt{3}-2$\\
\hline
$300^\circ$ &$-\frac{\sqrt{3}}{2}$ &$\frac{1}{2}$ &$-\sqrt{3}$ &$-\frac{2\sqrt{3}}{3}$ &$2$ &$-\frac{\sqrt{3}}{3}$\\
\hline
$315^\circ$ &$-\frac{\sqrt{2}}{2}$ &$\frac{\sqrt{2}}{2}$ &$-1$ &$-\sqrt{2}$ &$\sqrt{2}$ &$-1$\\
\hline
$330^\circ$ &$-\frac{1}{2}$ &$\frac{\sqrt{3}}{2}$ &$-\frac{\sqrt{3}}{3}$ &$-2$ &$\frac{2\sqrt{3}}{3}$ &$-\sqrt{3}$\\
\hline
$345^\circ$ &$\frac{\sqrt{2}-\sqrt{6}}{4}$ &$\frac{\sqrt{6}+\sqrt{2}}{4}$ &$\sqrt{3}-2$ &$-\sqrt{6}-\sqrt{2}$ &$\sqrt{6}-\sqrt{2}$ &$-2-\sqrt{3}$\\
\hline
\hline
$360^\circ$ &$0$ &$1$ &$0$ &undefined &$1$ &undefined\\
\hline
\hline

\end{tabular}
\end{center}

Answer 1

당신은 다음과 같은 테이블 디자인을 좋아할 것입니다:

디스플레이 수학 환경에 테이블을 넣고 tabularray패키지를 사용하면 테이블 코드가 훨씬 짧아지고 테이블이 훨씬 더 좋아집니다. 물론 textbf{<text>}and 대신에 각각 and를 \textbf{<symbol>}사용해야 합니다 .mathbf{<text>}\boldsymbol{<symbol>}

\documentclass{article}
\usepackage{xcolor}
\usepackage{tabularray}
\UseTblrLibrary{amsmath}
\DeclareMathOperator{\cosec}{cosec}

\begin{document}
    \[
\begin{tblr}{hlines, vlines,
             cells = {c},
             row{2,8,14,20,Z} = {bg=gray!20}
             }
\boldsymbol{\alpha} & \sin(\alpha) & \cos(\alpha) & \tan(\alpha)  &\cosec(\alpha) & \sec(\alpha) & \cot(\alpha) \\
%
\mathbf{0}^\circ & \mathbf{0} &\mathbf{1} &\mathbf{0} &\mathbf{undefined} &\mathbf{1} &\mathbf{undefined}\\

15^\circ &\frac{\sqrt{6}-\sqrt{2}}{4} &\frac{\sqrt{6}+\sqrt{2}}{4} &2-\sqrt{3} &\sqrt{6}+\sqrt{2} &\sqrt{6}-\sqrt{2} &2+\sqrt{3}\\
30^\circ &\frac{1}{2} &\frac{\sqrt{3}}{2} &\frac{\sqrt{3}}{3} &2 &\frac{2\sqrt{3}}{3} &\sqrt{3}\\
45^\circ &\frac{\sqrt{2}}{2} &\frac{\sqrt{2}}{2} &1 &\sqrt{2} &\sqrt{2} &1\\
60^\circ &\frac{\sqrt{3}}{2} &\frac{1}{2} &\sqrt{3} &\frac{2\sqrt{3}}{3} &2 &\frac{\sqrt{3}}{3}\\
75^\circ &\frac{\sqrt{6}+\sqrt{2}}{4} &\frac{\sqrt{6}-\sqrt{2}}{4} &2+\sqrt{3} &\sqrt{6}-\sqrt{2} &\sqrt{6}+\sqrt{2} &2-\sqrt{3}\\
90^\circ &1 &0 &\mathbf{undefined} &1 &\mathbf{undefined} &0\\
105^\circ &\frac{\sqrt{6}+{\sqrt{2}}}{4} &\frac{\sqrt{2}-\sqrt{6}}{4} &-2-\sqrt{3} &\sqrt{6}-\sqrt{2} &-\sqrt{6}-\sqrt{2} &\sqrt{3}-2\\
120^\circ &\frac{\sqrt{3}}{2} &-\frac{1}{2} &-\sqrt{3} &\frac{2\sqrt{3}}{3} &-2 &-\frac{\sqrt{3}}{3}\\
135^\circ &\frac{\sqrt{2}}{2} &-\frac{\sqrt{2}}{2} &-1 &\sqrt{2} &-\sqrt{2} &-1\\
150^\circ &\frac{1}{2} &-\frac{\sqrt{3}}{2} &-\frac{\sqrt{3}}{3} &2 &-\frac{2\sqrt{3}}{3} &-\sqrt{3}\\
165^\circ &\frac{\sqrt{6}-\sqrt{2}}{4} &\frac{-\sqrt{6}-\sqrt{2}}{4} &\sqrt{3}-2 &\sqrt{6}+\sqrt{2} &\sqrt{2}-\sqrt{6} &-2-\sqrt{3}\\
180^\circ &0 &-1 &0 &\mathbf{undefined} &-1 &\mathbf{undefined}\\
195^\circ &\frac{\sqrt{2}-\sqrt{6}}{4} &\frac{-\sqrt{6}-\sqrt{2}}{4} &2-\sqrt{3} &-\sqrt{6}-\sqrt{2} &\sqrt{2}-\sqrt{6} &2+\sqrt{3}\\
210^\circ &-\frac{1}{2} &-\frac{\sqrt{3}}{2} &\frac{\sqrt{3}}{3} &-2 &-\frac{2\sqrt{3}}{3} &\sqrt{3}\\
225^\circ &-\frac{\sqrt{2}}{2} &-\frac{\sqrt{2}}{2} &1 &-\sqrt{2} &-\sqrt{2} &1\\
240^\circ &-\frac{\sqrt{3}}{2} &-\frac{1}{2} &\sqrt{3} &-\frac{2\sqrt{3}}{3} &-2 &\frac{\sqrt{3}}{3}\\
255^\circ &\frac{-\sqrt{6}-\sqrt{2}}{4} &\frac{\sqrt{2}-\sqrt{6}}{4} &2+\sqrt{3} &\sqrt{6}-\sqrt{2} &-\sqrt{6}-\sqrt{2} &2-\sqrt{3}\\
270^\circ &-1 &0 &\mathbf{undefined} &1 &\mathbf{undefined} &0\\
285^\circ &\frac{-\sqrt{6}-\sqrt{2}}{4} &\frac{\sqrt{6}-\sqrt{2}}{4} &-2-\sqrt{3} &\sqrt{2}-\sqrt{6} &\sqrt{2}+\sqrt{6} &\sqrt{3}-2\\
300^\circ &-\frac{\sqrt{3}}{2} &\frac{1}{2} &-\sqrt{3} &-\frac{2\sqrt{3}}{3} &2 &-\frac{\sqrt{3}}{3}\\
315^\circ &-\frac{\sqrt{2}}{2} &\frac{\sqrt{2}}{2} &-1 &-\sqrt{2} &\sqrt{2} &-1\\
330^\circ &-\frac{1}{2} &\frac{\sqrt{3}}{2} &-\frac{\sqrt{3}}{3} &-2 &\frac{2\sqrt{3}}{3} &-\sqrt{3}\\
345^\circ &\frac{\sqrt{2}-\sqrt{6}}{4} &\frac{\sqrt{6}+\sqrt{2}}{4} &\sqrt{3}-2 &-\sqrt{6}-\sqrt{2} &\sqrt{6}-\sqrt{2} &-2-\sqrt{3}\\
360^\circ &0 &1 &0 &\mathbf{undefined} &1 &\mathbf{undefined}\\
\end{tblr}
    \]
\end{document}

Answer 2

Zarko의 댓글을 보고 내 문서에서 시도한 후 $\textbf{\alpha}$with로 대체할 수 있다는 것을 알았습니다. $\boldsymbol\alpha$여기서 작동하는 코드는 다음과 같습니다.

\begin{tabular}{||c|c|c|c||c|c|c||}
\hline
\hline
$\boldsymbol\alpha$ &sin($\alpha$) &cos($\alpha$) &tan($\alpha$) &cosec($\alpha$) &sec($\alpha$) &cot($\alpha$)\\
\hline
\hline
\textbf{0}$^\circ$ & $\textbf{0}$ &$\textbf{1}$ &$\textbf{0}$ &\textbf{undefined} &$\textbf{1}$ &\textbf{undefined}\\
\hline
\hline
$15^\circ$ &$\frac{\sqrt{6}-\sqrt{2}}{4}$ &$\frac{\sqrt{6}+\sqrt{2}}{4}$ &$2-\sqrt{3}$ &$\sqrt{6}+\sqrt{2}$ &$\sqrt{6}-\sqrt{2}$ &$2+\sqrt{3}$\\
\hline
$30^\circ$ &$\frac{1}{2}$ &$\frac{\sqrt{3}}{2}$ &$\frac{\sqrt{3}}{3}$ &$2$ &$\frac{2\sqrt{3}}{3}$ &$\sqrt{3}$\\
\hline
$45^\circ$ &$\frac{\sqrt{2}}{2}$ &$\frac{\sqrt{2}}{2}$ &$1$ &$\sqrt{2}$ &$\sqrt{2}$ &$1$\\
\hline
$60^\circ$ &$\frac{\sqrt{3}}{2}$ &$\frac{1}{2}$ &$\sqrt{3}$ &$\frac{2\sqrt{3}}{3}$ &$2$ &$\frac{\sqrt{3}}{3}$\\
\hline
$75^\circ$ &$\frac{\sqrt{6}+\sqrt{2}}{4}$ &$\frac{\sqrt{6}-\sqrt{2}}{4}$ &$2+\sqrt{3}$ &$\sqrt{6}-\sqrt{2}$ &$\sqrt{6}+\sqrt{2}$ &$2-\sqrt{3}$\\
\hline
\hline
$90^\circ$ &$1$ &$0$ &undefined &$1$ &undefined &$0$\\
\hline
\hline
$105^\circ$ &$\frac{\sqrt{6}+{\sqrt{2}}}{4}$ &$\frac{\sqrt{2}-\sqrt{6}}{4}$ &$-2-\sqrt{3}$ &$\sqrt{6}-\sqrt{2}$ &$-\sqrt{6}-\sqrt{2}$ &$\sqrt{3}-2$\\
\hline
$120^\circ$ &$\frac{\sqrt{3}}{2}$ &$-\frac{1}{2}$ &$-\sqrt{3}$ &$\frac{2\sqrt{3}}{3}$ &$-2$ &$-\frac{\sqrt{3}}{3}$\\
\hline
$135^\circ$ &$\frac{\sqrt{2}}{2}$ &$-\frac{\sqrt{2}}{2}$ &$-1$ &$\sqrt{2}$ &$-\sqrt{2}$ &$-1$\\
\hline
$150^\circ$ &$\frac{1}{2}$ &$-\frac{\sqrt{3}}{2}$ &$-\frac{\sqrt{3}}{3}$ &$2$ &$-\frac{2\sqrt{3}}{3}$ &$-\sqrt{3}$\\
\hline
$165^\circ$ &$\frac{\sqrt{6}-\sqrt{2}}{4}$ &$\frac{-\sqrt{6}-\sqrt{2}}{4}$ &$\sqrt{3}-2$ &$\sqrt{6}+\sqrt{2}$ &$\sqrt{2}-\sqrt{6}$ &$-2-\sqrt{3}$\\
\hline
\hline
$180^\circ$ &$0$ &$-1$ &$0$ &undefined &$-1$ &undefined\\
\hline
\hline
$195^\circ$ &$\frac{\sqrt{2}-\sqrt{6}}{4}$ &$\frac{-\sqrt{6}-\sqrt{2}}{4}$ &$2-\sqrt{3}$ &$-\sqrt{6}-\sqrt{2}$ &$\sqrt{2}-\sqrt{6}$ &$2+\sqrt{3}$\\
\hline
$210^\circ$ &$-\frac{1}{2}$ &$-\frac{\sqrt{3}}{2}$ &$\frac{\sqrt{3}}{3}$ &$-2$ &$-\frac{2\sqrt{3}}{3}$ &$\sqrt{3}$\\
\hline
$225^\circ$ &$-\frac{\sqrt{2}}{2}$ &$-\frac{\sqrt{2}}{2}$ &$1$ &$-\sqrt{2}$ &$-\sqrt{2}$ &$1$\\
\hline
$240^\circ$ &$-\frac{\sqrt{3}}{2}$ &$-\frac{1}{2}$ &$\sqrt{3}$ &$-\frac{2\sqrt{3}}{3}$ &$-2$ &$\frac{\sqrt{3}}{3}$\\
\hline
$255^\circ$ &$\frac{-\sqrt{6}-\sqrt{2}}{4}$ &$\frac{\sqrt{2}-\sqrt{6}}{4}$ &$2+\sqrt{3}$ &$\sqrt{6}-\sqrt{2}$ &$-\sqrt{6}-\sqrt{2}$ &$2-\sqrt{3}$\\
\hline
\hline
$270^\circ$ &$-1$ &$0$ &undefined &$1$ &undefined &$0$\\
\hline
\hline
$285^\circ$ &$\frac{-\sqrt{6}-\sqrt{2}}{4}$ &$\frac{\sqrt{6}-\sqrt{2}}{4}$ &$-2-\sqrt{3}$ &$\sqrt{2}-\sqrt{6}$ &$\sqrt{2}+\sqrt{6}$ &$\sqrt{3}-2$\\
\hline
$300^\circ$ &$-\frac{\sqrt{3}}{2}$ &$\frac{1}{2}$ &$-\sqrt{3}$ &$-\frac{2\sqrt{3}}{3}$ &$2$ &$-\frac{\sqrt{3}}{3}$\\
\hline
$315^\circ$ &$-\frac{\sqrt{2}}{2}$ &$\frac{\sqrt{2}}{2}$ &$-1$ &$-\sqrt{2}$ &$\sqrt{2}$ &$-1$\\
\hline
$330^\circ$ &$-\frac{1}{2}$ &$\frac{\sqrt{3}}{2}$ &$-\frac{\sqrt{3}}{3}$ &$-2$ &$\frac{2\sqrt{3}}{3}$ &$-\sqrt{3}$\\
\hline
$345^\circ$ &$\frac{\sqrt{2}-\sqrt{6}}{4}$ &$\frac{\sqrt{6}+\sqrt{2}}{4}$ &$\sqrt{3}-2$ &$-\sqrt{6}-\sqrt{2}$ &$\sqrt{6}-\sqrt{2}$ &$-2-\sqrt{3}$\\
\hline
\hline
$360^\circ$ &$0$ &$1$ &$0$ &undefined &$1$ &undefined\\
\hline
\hline

\end{tabular}
\end{center}