Quero que o "Sim" esteja perfeitamente alinhado abaixo. Como a tabela está agora, se houver estrelas antes do "Sim", o texto será empurrado para a esquerda. No entanto, quero que cada coluna de "Sim" seja alinhada de forma que cada "Y" em sim fique diretamente em cima do outro "Y" nos outros sim na coluna, independentemente do número de estrelas que prosseguem.
Eu tentei \phantomcolocar algumas estrelas, mas não funcionou.
Exemplo mínimo:
\documentclass{article}
\usepackage{longtable}
\usepackage{dcolumn}
\usepackage{booktabs}
\usepackage{lscape}
\newcommand{\C}[1]{\multicolumn{1}{c}{#1}}
\newcommand*{\SuperScriptSameStyle}[1]{%
\ensuremath{%
\mathchoice
{{}^{\displaystyle #1}}%
{{}^{\textstyle #1}}%
{{}^{\scriptstyle #1}}%
{{}^{\scriptscriptstyle #1}}%
}%
}
\newcommand*{\oneS}{\SuperScriptSameStyle{*}}
\newcommand*{\twoS}{\SuperScriptSameStyle{**}}
\newcommand*{\threeS}{\SuperScriptSameStyle{*{*}*}}
\newcommand\Ya{\C{Yes}}
\newcommand\Yb{\C{Yes\oneS}}
\newcommand\Yc{\C{Yes\twoS}}
\newcommand\Yd{\C{Yes\threeS}}
\newcolumntype{d}[1]{D{.}{.}{#1}} % "decimal" column type
\begin{document}
\begin{landscape}
\begin{longtable}{@{} l @{\extracolsep{\fill}} *{7}{d{6}} @{}}
\cmidrule[\heavyrulewidth]{1-8}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa} \\
\cmidrule{1-8}
\endfirsthead
\multicolumn{2}{@{}l}{\emph{(continued)}} \\
\cmidrule[\heavyrulewidth]{1-8}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa}
& \multicolumn{1}{c}{Column 1aa} \\
\cmidrule{1-8}
\endhead
\cmidrule[\heavyrulewidth]{1-8}
\multicolumn{8}{r@{}}{\emph{(continued)}}
\endfoot
\cmidrule[\heavyrulewidth]{1-8}
\endlastfoot
\multicolumn{5}{@{}l}{\emph{Estimates}} \\
$\tau = 0.05$ & -0.078 & -0.959 & -0.695 & -1.754\oneS & 0.339 & -2.925 & 2.553 \\
$\tau = 0.10$ & -0.046 & -0.868 & -0.649 & -1.066 & -0.272 & -4.288\twoS & -0.245 \\
$\tau = 0.50$ & -0.424 & -0.910 & -0.786 & -1.625\oneS & 1.569\twoS & -3.569\twoS & 0.086 \\
$\tau = 0.90$ & -1.008\twoS & 0.001 & -1.924\threeS & 0.906 & 0.284 & -2.444 & 1.552 \\
$\tau = 0.95$ & -0.911\twoS & 0.930 & -2.230\threeS & -0.321 & 1.363 & -2.903 & 0.479 \\
& & & & & & & \\
$F:\tau \in \{0.05,0.50\}$ & 0.467 & 0.002 & 0.018 & 0.013 & 1.325 & 0.078 & 1.855 \\
$F:\tau \in \{0.50,0.95\}$ & 0.842 & 2.808\oneS & 5.230\twoS & 1.447 & 0.031 & 0.022 & 0.028 \\
$F:\tau \in \{0.05,0.95\}$ & 2.484 & 2.952\oneS & 3.918\twoS & 1.378 & 0.483 & 0.000 & 0.572 \\
& & & & & & & \\
\multicolumn{5}{@{}l}{\emph{\underline{Sigs}}} \\
$\tau = 0.05$ & \Yb & \Yd & \Ya & \Yd & \Ya & \Yd & \Yd \\
$\tau = 0.10$ & \Ya & \Yd & \Ya & \Yd & \Ya & \Yd & \Ya \\
$\tau = 0.50$ & \Yd & \Ya & \Ya & \Ya & \Ya & \Ya & \Ya \\
$\tau = 0.90$ & \Yd & \Yb & \Yb & \Ya & \Ya & \Yc & \Ya \\
$\tau = 0.95$ & \Yd & \Yc & \Yd & \Yc & \Yd & \Yd & \Yd \\
\end{longtable}
\end{landscape}
\end{document}
Responder1
Uma maneira de fazer isso é colocar as estrelas em rângulo lap(ou \rlap) para que não ocupem espaço horizontalmente. Em resumo, \rlapé equivalente a \makebox[0pt][l]:
\newcommand*{\oneS}{\rlap{\SuperScriptSameStyle{*}}}
\newcommand*{\twoS}{\rlap{\SuperScriptSameStyle{**}}}
\newcommand*{\threeS}{\rlap{\SuperScriptSameStyle{*{*}*}}}
