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Como posso fazer duas colunas em duas colunas

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Como posso fazer duas colunas em duas colunas

Como posso fazer duas colunas em duas colunas iguais às da imagem?

Responder1

Talvez você possa dar otaskspacote (fazia parte do pacoteexsheetspacote) uma tentativa:

insira a descrição da imagem aqui

\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{multicol}
\usepackage{tasks}[2013/04/07]

% renew the {tasks} environment to use bold labels
% and use two columns as default settings:
\RenewTasks[counter-format= tsk.,label-format=\bfseries]{tasks}(2)

\begin{document}

\begin{multicols}{2}
Lorem ipsum dolor sit amet, consetetur sadipscing elitr
\begin{tasks}
 \task foo
 \task bar
 \task baz
 \task foobar
 \task foo
 \task bar
 \task baz
 \task foobar
\end{tasks}

Lorem ipsum dolor sit amet, consetetur sadipscing elitr
\begin{tasks}
 \task foo
 \task bar
 \task baz
 \task foobar
 \task foo
 \task bar
 \task baz
 \task foobar
\end{tasks}

Lorem ipsum dolor sit amet, consetetur sadipscing elitr
\begin{tasks}
 \task foo
 \task bar
 \task baz
 \task foobar
 \task foo
 \task bar
 \task baz
 \task foobar
\end{tasks}

Lorem ipsum dolor sit amet, consetetur sadipscing elitr
\begin{tasks}
 \task foo
 \task bar
 \task baz
 \task foobar
 \task foo
 \task bar
 \task baz
 \task foobar
\end{tasks}
\end{multicols}

\end{document}

Aqui está um exemplo de como a aparência pode ser ainda mais personalizada (graças ag.kovpor fazer a digitação!).Editar:a versão atualizada precisa da v0.10 (20/07/2014) para a \task!sintaxe.

Os itens que devem abranger uma linha completa (itens 31. e 32. na figura abaixo) podem ser alcançados por um dos seguintes métodos:

  • \task!– isso forçará o item específico a começar em uma nova linha usando a linha inteira.
  • \task*– isso forçará o item específico a usar o espaço restante da linha. Neste caso, isso significa que ele usa a linha inteira se for um item da primeira coluna.
  • \task*(<num>)– isso significa que o item abrangerá <num>colunas desde que haja colunas suficientes na linha atual. Caso contrário, ele usará o máximo de colunas possível.

insira a descrição da imagem aqui

\documentclass{article}
\usepackage[left=1.5cm,right=1.5cm,top=1.5cm,bottom=1.5cm]{geometry}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{multicol}
\usepackage{amsmath}

% use tasks v0.10 2014/07/20:
\usepackage{tasks}[2014/07/20]

% declare custom tasks instance that has no stretchable space between
% rows of items:
\DeclareInstance{tasks}{custom}{default}{
  counter-format  = tsk. ,
  label-format    = \bfseries ,
  label-width     = 1.5em ,
  label-offset    = .3333em ,
  after-item-skip = 0pt
}

% renew {tasks} environment to use the new instance and resume the
% item counting:
\RenewTasks[resume,style=custom,label-align=right]{tasks}(2)

\begin{document}

\begin{multicols}{2}
Derivative calculations\par
In Exercises \ref{tsk:st1}--\ref{tsk:end1}, given $y=f(u)$ and $u=g(x)$, find
$dy/dx=f^\prime(g(x))g^\prime(x)$
\begin{tasks}
 \task $y=6u-9,\ u=1/2 x^4$ \label{tsk:st1}
 \task $y=2u^3,\ u=8x-1$
 \task $y=\sin u,\ u=3x+1$
 \task $y=\cos u,\ u=-x/3$
 \task $y=\cos u,\ u=\sin x$
 \task $y=\sin u,\ u=x-\cos x$
 \task $y = \tan u,\ u=10x-5$
 \task $y=-\sec u,\ u=x^2+7x $ \label{tsk:end1}
\end{tasks}

In Exersises  \ref{tsk:st2}--\ref{tsk:end2}, write the function in the form
$y=f(u)$ and $u=g(x)$. Then find $dy/dx$ as a function of $x$.
\begin{tasks}
 \task $y=\left( 2x+1 \right)^5$ \label{tsk:st2} 
 \task $y=\left( 4-3x \right)^9$
 \task $y=\left( 1-\dfrac{x}7 \right)^{-7}$
 \task $y=\left( \dfrac{x}2 -1 \right)^{-10}$
 \task $y=\left( \dfrac{x^2}8 +x -\dfrac1{x} \right)^{4}$
 \task $y=\sqrt{2x^2-4x+6}$
 \task $y=\sec(\tan x)$
 \task $y=\cot\left( \pi -\dfrac1{x} \right)$
 \task $y=\sin^3 x$
 \task $y=5\cos^{-4} x$
 \task $y=e^{-5x}$
 \task $y=e^{2x/3}$
 \task $y=e^{5-7x}$
 \task $y=e^{4\sqrt{x}-x^2}$ \label{tsk:end2}
\end{tasks}

Find the derivatives of the functions in Exercises \ref{eq:st3}--\ref{eq:end3}:
\begin{tasks}
 \task $p=\sqrt{3-t}$ \label{eq:st3}
 \task $q=\sqrt[3]{2r-r^2}$
 \task $s=\dfrac{4}{3\pi}\sin{3t}+\dfrac{4}{5\pi}\cos{5t}$
 \task $s=\sin\dfrac{3\pi t}{2}+\cos\dfrac{3\pi t}{2}$
 \task $r=\left( \csc\theta +\cot\theta \right)^{-1}$
 \task $r=6\left( \sec\theta -\tan\theta \right)^{3/2}$
 \task $y=x^2\sin4x+x\cos^{-2}x$
 \task $y=\dfrac1{x}\sin^{-5}x-\dfrac{x}{3}\cos^{3}x$
 \task! $y=\dfrac1{21}(3x-2)^7+\left( 4-\dfrac1{2x^2}  \right)^{-1}$
 \task! $y=(5-2x)^{-3}+\dfrac1{8}\left( \dfrac2{x}+1  \right)^{4}$
 \task $y=(4x+3)^4(x+1)^{-3}$
 \task $y=(2x-5)^{-1}(x^2-5x)^{6}$
 \task $y=x e^{-x}+e^{3x}$
 \task $y=(1+2x)e^{-2x}$
 \task $y=(x^2-2x+2)e^{5x/2}$
 \task $y=(9x^2-6x+2)e^{x^3}$
 \task $h(x)=x\tan\left( 2\sqrt{x} \right)+7$
 \task $k(x)=x^2\sec\left( \dfrac1x \right)$ \label{eq:end3}
\end{tasks}
\end{multicols}

\end{document}

Responder2

Uma solução um tanto ingênua.

\documentclass{report}
\usepackage{multicol}
\usepackage[english]{babel}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{lmodern}
\usepackage[left=1.5cm,right=1.5cm,top=1.5cm,bottom=1.5cm]{geometry}

\usepackage{newfile}
\newoutputstream{qstream}
\IfFileExists{\jobname.qst}{\input{\jobname.qst}}{}
%
\AtBeginDocument{\openoutputfile{\jobname.qst}{qstream}}
\AtEndDocument{\closeoutputstream{qstream}}
%
\newcount\n
\newdimen\eqboxwd
\eqboxwd=0.38\hsize
\n=0
\newbox\eqbox
\def\qtem$#1${%
\advance\n1\leavevmode\setbox\eqbox=\hbox{\hbox to2em{\hfill$\mathbf{\the\n.}$}\ $#1$\hss}%
\ifnum\wd\eqbox<\eqboxwd \setbox\eqbox=\hbox to\eqboxwd{\unhbox\eqbox\hss}\copy\eqbox%
\else\copy\eqbox\\ \fi%
}

\def\qlab#1{%
\addtostream{qstream}{\noexpand\expandafter\noexpand\def\noexpand\csname[#1]\noexpand\endcsname{\the\n}}
}
\def\qref#1{\ifcsname[#1]\endcsname\csname[#1]\endcsname\else?\fi}

\begin{document}

\begin{multicols}{2}
Derivative calculations\par
In Exercises 
%1--8, 
\qref{eq:st1}--\qref{eq:end1},
given $y=f(u)$ and $u=g(x)$,
find $dy/dx=f^\prime(g(x))g^\prime(x)$. 

\noindent%
\qtem $y=6u-9,\ u=1/2 x^4$ \qlab{eq:st1}%
\qtem $y=2u^3,\ u=8x-1$
\qtem $y=\sin u,\ u=3x+1$
\qtem $y=\cos u,\ u=-x/3$
\qtem $y=\cos u,\ u=\sin x$
\qtem $y=\sin u,\ u=x-\cos x$
\qtem $y = \tan u,\ u=10x-5$
\qtem $y=-\sec u,\ u=x^2+7x $ \qlab{eq:end1}%

In Exersises 
%9--22, 
\qref{eq:st2}--\qref{eq:end2},
write the function in the form $y=f(u)$
and $u=g(x)$. Then find $dy/dx$ as a function of $x$.

\noindent%
\qtem $y=\left( 2x+1 \right)^5$ \qlab{eq:st2}% 
\qtem $y=\left( 4-3x \right)^9$
\qtem $y=\left( 1-\dfrac{x}7 \right)^{-7}$
\qtem $y=\left( \dfrac{x}2 -1 \right)^{-10}$
\qtem $y=\left( \dfrac{x^2}8 +x -\dfrac1{x} \right)^{4}$
\qtem $y=\sqrt{2x^2-4x+6}$
\qtem $y=\sec(\tan x)$
\qtem $y=\cot\left( \pi -\dfrac1{x} \right)$
\qtem $y=\sin^3 x$
\qtem $y=5\cos^{-4} x$
\qtem $y=e^{-5x}$
\qtem $y=e^{2x/3}$
\qtem $y=e^{5-7x}$
\qtem $y=e^{4\sqrt{x}-x^2}$ \qlab{eq:end2}%

Find the derivatives of the functions in Exercises 
%23--50
\qref{eq:st3}--\qref{eq:end3}.

\noindent%
\qtem $p=\sqrt{3-t}$ \qlab{eq:st3}%
\qtem $q=\sqrt[3]{2r-r^2}$
\qtem $s=\dfrac{4}{3\pi}\sin{3t}+\dfrac{4}{5\pi}\cos{5t}$
\qtem $s=\sin\dfrac{3\pi t}{2}+\cos\dfrac{3\pi t}{2}$
\qtem $r=\left( \csc\theta +\cot\theta \right)^{-1}$
\qtem $r=6\left( \sec\theta -\tan\theta \right)^{3/2}$
\qtem $y=x^2\sin4x+x\cos^{-2}x$
\qtem $y=\dfrac1{x}\sin^{-5}x-\dfrac{x}{3}\cos^{3}x$
\qtem $y=\dfrac1{21}(3x-2)^7+\left( 4-\dfrac1{2x^2}  \right)^{-1}$
\qtem $y=(5-2x)^{-3}+\dfrac1{8}\left( \dfrac2{x}+1  \right)^{4}$
\qtem $y=(4x+3)^4(x+1)^{-3}$
\qtem $y=(2x-5)^{-1}(x^2-5x)^{6}$
\qtem $y=x e^{-x}+e^{3x}$
\qtem $y=(1+2x)e^{-2x}$
\qtem $y=(x^2-2x+2)e^{5x/2}$
\qtem $y=(9x^2-6x+2)e^{x^3}$
\qtem $h(x)=x\tan\left( 2\sqrt{x} \right)+7$
\qtem $k(x)=x^2\sec\left( \dfrac1x \right)$ \qlab{eq:end3}%
\end{multicols}

\end{document}

insira a descrição da imagem aqui

Responder3

Aqui está uma solução simples:

\documentclass[twocolumn]{report}
\usepackage{multicol}

\begin{document}
foo\hrulefill foo
\begin{multicols}{2}
\begin{enumerate}
\item foo\hrulefill foo

\item foo\hrulefill foo

\item foo\hrulefill foo

\item foo\hrulefill foo
\end{enumerate}
\end{multicols}
foo\hrulefill foo

\vfill

foo\hrulefill foo

\end{document}

insira a descrição da imagem aqui

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