
Estou tendo o erro a seguir:
! Package pgf Error: No shape named n1 is known.
quando tento compilar este código.
\documentclass[border=1mm]{standalone}
\usepackage{tikz,pgfplots}
\usetikzlibrary{calc,arrows}
\usepackage{xifthen}
\begin{document}
\begin{tikzpicture}[scale=1,>=latex',line width=0.7pt]
\foreach \i/\j in {0/1,1/2,2/3,3/4,4/5,5/6,6/7,7/8}{%
\node (n\i) [draw,minimum size=1cm] at (1.7*\i,0){};
\ifthenelse{\i=7}{}{%
\draw[->] (n\i)--(n\j);}%
}
\end{tikzpicture}
\end{document}
Eu aprecio muito a sua ajuda.
Responder1
Você poderia (pelo menos neste caso) tentar chain
:
\documentclass[tikz,border=5]{standalone}
\usetikzlibrary{chains,arrows}
\begin{document}
\begin{tikzpicture}[>=latex', ultra thick,
start chain, every join/.style=->, node distance=1.7]
\foreach \i in {0,...,8}
\node (n\i) [draw, minimum size=1cm, on chain, join] {};
\end{tikzpicture}
\end{document}
Responder2
Eu proporia usar uma sintaxe mais limpa. Aqui estão duas outras maneiras;
\documentclass[tikz,border=1mm]{standalone}
\usetikzlibrary{arrows}
\begin{document}
\begin{tikzpicture}[scale=1,>=latex',line width=0.7pt]
\node[draw,minimum size=1cm] (n0) at (0,0) {};
\foreach \x[remember=\x as \lastx (initially 0)] in {1,...,7}{%
\node(n\x) [draw,minimum size=1cm] at (1.7*\x,0){};
\draw[<-] (n\x) -- (n\lastx);
}
\end{tikzpicture}
% If feeling adventurous
\begin{tikzpicture}[scale=1,>=latex',line width=0.7pt]
\node[draw,minimum size=1cm] (n0) at (0,0) {};
\foreach \x[remember=\x as \lastx (initially 0)] in {1,...,7}{%
\draw[<-]node[draw,minimum size=1cm,append after command=(n\x) -- (n\lastx)](n\x) at (1.7*\x,0){};
}
\end{tikzpicture}
\end{document}
Se você estiver usando estritamente números inteiros, poderá se safar\ifnum\i=7\else....\fi
Responder3
EDIT: Sem quebrar a \foreach
afirmação, poderíamos ter feito isso de duas maneiras:
\documentclass[border=1mm]{standalone}
\usepackage{tikz,pgfplots}
\usetikzlibrary{calc,arrows}
\usepackage{xifthen}
\begin{document}
\begin{tikzpicture}[>=latex',line width=0.7pt]
\foreach [evaluate=\i as \j using \i-1]\i in {0,...,7}{%
\node (n\i) [draw,minimum size=1cm] at (1.7*\i,0){};
\ifthenelse{\i=0}{}{%
\draw[->] (n\j)--(n\i);}%
}
\end{tikzpicture}
\begin{tikzpicture}[>=latex',line width=0.7pt]
\foreach \i/\j in {0/-1,1/0,2/1,3/2,4/3,5/4,6/5,7/6}{%
\node (n\i) [draw,minimum size=1cm] at (1.7*\i,0){};
\ifthenelse{\i=0}{}{%
\draw[->] (n\j)--(n\i);}%
}
\end{tikzpicture}
\end{document}
Eu concordo com o comentário de Jake. Você pode fazer isso separando o arquivo \foreach
em duas partes da seguinte maneira:
\documentclass[border=1mm]{standalone}
\usepackage{tikz,pgfplots}
\usetikzlibrary{calc,arrows}
\usepackage{xifthen}
\begin{document}
\begin{tikzpicture}[scale=1,>=latex',line width=0.7pt]
\foreach \i/\j in {0/1,1/2,2/3,3/4,4/5,5/6,6/7,7/8}%
\node (n\i) [draw,minimum size=1cm] at (1.7*\i,0){};
\foreach \i/\j in {0/1,1/2,2/3,3/4,4/5,5/6,6/7,7/8}{%
\ifthenelse{\i=7}{}{%
\draw[->] (n\i)--(n\j);}%
}
\end{tikzpicture}
\end{document}
Isso deve funcionar corretamente, pois todos os nós n0
... through n7
são certamente criados no \foreach
loop superior.