Alguém pode me ajudar a redefinir o contador (?) No código abaixo. A seção Resposta deve começar com #1
. eu preciso
\RenewTasks[resume, style=custom,label-align=right]{tasks}(2)
no preâmbulo.
Obrigado.
\documentclass{book}
\usepackage[a4paper, top=2cm, bottom=2cm]{geometry}
\usepackage{multicol, paralist, multirow, amsmath, amsthm, amssymb, amsfonts, ulem}
\usepackage{tasks}[2014/07/20]
\DeclareInstance{tasks}{custom}{default}{
counter-format = tsk. ,
label-format = \bfseries ,
label-width = 2em ,
label-offset = .3333em ,
after-item-skip = 5pt
}
\RenewTasks[resume, style=custom,label-align=right]{tasks}(2)
\begin{document}
%
%
In Exercises 1-8, factor the common factor in the polynomials.
\begin{tasks}(3)
\task
$3x^3 - 21x$
\task
$5x^6 + 15x^4$
\task
$4x^3 + 10x^2 - 2x$
\end{tasks}
%
%
\begin{tasks}(1)
\task
This is a long word problem, more than one line. I can't seem to use rlap for this. I have to use another begin{tasks} section here.
\end{tasks}
In Exercises 8-13, solve the polynomial equations.
\begin{tasks}(2)
\task
$x(x+12) = 0$
\task
$(2x+1)(2x-1) = 0$
\end{tasks}
%
\vspace{1in}
%%%%%%%
Answers:
\begin{tasks}(2)
\task
$3x(x^2-7)$
\task
$5x^4(x^2+3)$
\task
$2x(2x^2+5x-1)$
%
\task
answer to the word problem
\task
$x=0, \, x = -12$
\task
$x = - \, \dfrac 12, \, x = \, \dfrac 12$
\end{tasks}
\end{document}
Responder1
Duas coisas:
Para acomodar um item longo, não é necessário iniciar um novo ambiente. Apenas use\task*
\task*
This is a long word problem, more than one line. I can't seem to use rlap for this. I have to use another begin{tasks} section here.
Segundo, você pode passar a opção [resume=false]
localmente, ao digitar respostas
Answers:
\begin{tasks}[resume=false](2)
Código completo:
\documentclass{book}
\usepackage[a4paper, top=2cm, bottom=2cm]{geometry}
\usepackage{multicol, paralist, multirow, amsmath, amsthm, amssymb, amsfonts, ulem}
\usepackage{tasks}
\DeclareInstance{tasks}{custom}{default}{
counter-format = tsk. ,
label-format = \bfseries ,
label-width = 2em ,
label-offset = .3333em ,
after-item-skip = 5pt
}
\RenewTasks[resume, style=custom,label-align=right]{tasks}(2)
\begin{document}
%
%
In Exercises 1-8, factor the common factor in the polynomials.
\begin{tasks}(3)
\task
$3x^3 - 21x$
\task
$5x^6 + 15x^4$
\task
$4x^3 + 10x^2 - 2x$
%\end{tasks}
%%
%%
%\begin{tasks}(1)
\task*
This is a long word problem, more than one line. I can't seem to use rlap for this. I have to use another begin{tasks} section here.
\end{tasks}
In Exercises 8-13, solve the polynomial equations.
\begin{tasks}(2)
\task
$x(x+12) = 0$
\task
$(2x+1)(2x-1) = 0$
\end{tasks}
%
\vspace{1in}
%%%%%%%
Answers:
\begin{tasks}[resume=false](2)
\task
$3x(x^2-7)$
\task
$5x^4(x^2+3)$
\task
$2x(2x^2+5x-1)$
%
\task
answer to the word problem
\task
$x=0, \, x = -12$
\task
$x = - \, \dfrac 12, \, x = \, \dfrac 12$
\end{tasks}
\end{document}
Além disso, em vez de codificar intervalos de perguntas, você pode rotular as perguntas e usar\ref
Como alternativa, você pode definir estes:
\NewTasks[resume, style=custom,label-align=right]{questions}(2)
\NewTasks[style=custom,label-align=right]{answers}
e usá-los como
\begin{questions}(3)
\task
$3x^3 - 21x$
\end{questions}
\begin{answers}(2)
\task
$3x^3 - 21x$
\end{answers}
para que o código seja mais legível. Você também pode alterar o separador \task
, se desejar. Para obter detalhes, consulte o manual.