Considere o seguinte MWE
\documentclass{beamer}
\usepackage{tikz}
\usepackage{tikz-3dplot}
\usetikzlibrary{positioning}% To get more advances positioning options
\usetikzlibrary{arrows}% To get more arrow heads
\usetikzlibrary{math,calc}
\usetikzlibrary{arrows.meta, bending, decorations.markings, angles, quotes, fit}
\usetikzlibrary{tikzmark}
\usetikzlibrary{scopes}
\mode<presentation> {
\usetheme{Boadilla}
\setbeamertemplate{footline}{}% get rid of footer completely
}
\usepackage{booktabs} % Allows the use of \toprule, \midrule and \bottomrule in tables
\usepackage{amssymb, mathtools, amsfonts}
\definecolor{MyColor1}{rgb}{0.24, 0.59, 0.32}
\definecolor{MyColor2}{rgb}{0.85, 0.49, 0.19}
\definecolor{MyColor3}{rgb}{0.22, 0.42, 0.69}
\usepackage{tikz}
\usefonttheme{serif}
\begin{document}
\begin{frame}\frametitle{Examples}
\begin{center}
\begin{tabular}{c|c}
\onslide<1->{
$\langle\alpha,\beta\rangle = \langle\beta,\alpha\rangle =-1$
& $3\langle\alpha,\beta\rangle= \langle\beta,\alpha\rangle=-3$\\\midrule
& \\
\begin{tikzpicture}[scale=0.7, every node/.style={transform shape}]
\draw (-2,-2) rectangle (2,2);
\node (alpha) at (1.2,0) {$\alpha$};
\node (beta) at (120:1.2) {$\beta$};
\draw[->] (0,0) -- (0:1);
\draw[->] (0,0) -- (120:1);
\only<1>{
\foreach \angle in {60,180,240,300}{
\draw[->] (0,0) -- (\angle:1);
}
}
\draw[MyColor1] (0.5,0) arc (0:120:0.5);
\draw[fill=MyColor1, opacity=0.3] (0,0) -- (0.5,0) arc (0:120:0.5) -- cycle;
\end{tikzpicture} &
\begin{tikzpicture}[scale=0.7, every node/.style={transform shape}]
\draw (-2,-2) rectangle (2,2);
\node (alpha) at (1.2,0) {$\alpha$};
\node (beta) at (150:1.9) {$\beta$};
\draw[->] (0,0) -- (150:1.7320);
\draw[->] (0,0) -- (0:1);
\only<1>{
\foreach \angle in {30,60,90,120,180,210,240,270,300,330}{
\pgfmathsetmacro{\bigradius}{sqrt(3)}
\ifthenelse{\angle=30 \OR
\angle=90 \OR
\angle=150 \OR
\angle=210 \OR
\angle=270 \OR
\angle=330}{
\draw[->] (0,0) -- (\angle:\bigradius);
}{
\draw[->] (0,0) -- (\angle:1);
};
}
}
\draw[MyColor1] (0.5,0) arc (0:150:0.5);
\draw[fill=MyColor1, opacity=0.3] (0,0) -- (0.5,0) arc (0:150:0.5) -- cycle;
\end{tikzpicture}\\
& \\}
\only<2->{
\only<3>{
$\begin{pmatrix*}[r] \hphantom{-2} & \hphantom{-1}\\
\hphantom{-1} & \hphantom{-2}
\end{pmatrix*}$}
\only<4->{
$\begin{pmatrix*}
\only<4->{-2} & \only<5->{\color<5->{MyColor1}{-1}}\\
\only<5->{\color<5->{MyColor1}{-1}} & \only<4->{-2}
\end{pmatrix*}$}
&
\only<3>{
$\begin{pmatrix} \hphantom{-2} & \hphantom{-1}\\
\hphantom{-1} & \hphantom{-2}
\end{pmatrix}$}
\only<4->{
$\begin{pmatrix*}[r] \only<4->{-2} & \only<5->{\color<5->{MyColor1}{-1}}\\
\only<5->{\color<5->{MyColor1}{-3}} & \only<3->{-2}
\end{pmatrix*}$}
}
\end{tabular}
\end{center}
\end{frame}
\end{document}
Ele mostra o que deveria estar na posição correta, ou seja, a ordem das coisas que é revelada está correta. O único problema que tenho com a saída é que as bordas da tabela (a linha central e a primeira linha) mudam quando alguns elementos são revelados. Consegui fazer com que as duas tikzpicturesficassem no lugar, mas quando adiciono as matrizes na mesa elas também começam a mudar...
Eu realmente não entendo onde está o problema, pois acho que apliquei a mesma técnica para manter as coisas no lugar em todo o quadro, mas às vezes parece não funcionar (esseé o que tomei como orientação)... Provavelmente estou abordando esse problema da maneira errada, mas não sei realmente como manter as coisas no lugar, a não ser adicionar espaço vazio quando necessário.
Qualquer dica sobre como posso fazer com que a mesa inteira fique fixa enquanto revelo as diferentes partes será apreciada.
Responder1
Se você usar a [t]opção e a overlay-beamer-stylesbiblioteca, que é feita para isso, e descartar os espaços ocultos você obtém
\documentclass{beamer}
\usepackage{tikz}
\usepackage{ifthen}
\usetikzlibrary{overlay-beamer-styles}
\mode<presentation> {
\usetheme{Boadilla}
\setbeamertemplate{footline}{}% get rid of footer completely
}
\usepackage{booktabs} % Allows the use of \toprule, \midrule and \bottomrule in tables
\usepackage{amssymb, mathtools, amsfonts}
\definecolor{MyColor1}{rgb}{0.24, 0.59, 0.32}
\definecolor{MyColor2}{rgb}{0.85, 0.49, 0.19}
\definecolor{MyColor3}{rgb}{0.22, 0.42, 0.69}
\usefonttheme{serif}
\begin{document}
\begin{frame}[t]
\frametitle{Examples}
\begin{center}
\begin{tabular}{c|c}
\onslide<1->{
$\langle\alpha,\beta\rangle = \langle\beta,\alpha\rangle =-1$
& $3\langle\alpha,\beta\rangle= \langle\beta,\alpha\rangle=-3$\\\midrule
& \\
\begin{tikzpicture}[scale=0.7, every node/.style={transform shape}]
\draw (-2,-2) rectangle (2,2);
\node (alpha) at (1.2,0) {$\alpha$};
\node (beta) at (120:1.2) {$\beta$};
\draw[->] (0,0) -- (0:1);
\draw[->] (0,0) -- (120:1);
\foreach \angle in {60,180,240,300}{
\draw[->,visible on=<1>] (0,0) -- (\angle:1);
}
\draw[MyColor1] (0.5,0) arc (0:120:0.5);
\draw[fill=MyColor1, opacity=0.3] (0,0) -- (0.5,0) arc (0:120:0.5) -- cycle;
\end{tikzpicture} &
\begin{tikzpicture}[scale=0.7, every node/.style={transform shape}]
\draw (-2,-2) rectangle (2,2);
\node (alpha) at (1.2,0) {$\alpha$};
\node (beta) at (150:1.9) {$\beta$};
\draw[->] (0,0) -- (150:1.7320);
\draw[->] (0,0) -- (0:1);
\begin{scope}[visible on=<1>]
\foreach \angle in {30,60,90,120,180,210,240,270,300,330}{
\pgfmathsetmacro{\bigradius}{sqrt(3)}
\ifthenelse{\angle=30 \OR
\angle=90 \OR
\angle=150 \OR
\angle=210 \OR
\angle=270 \OR
\angle=330}{
\draw[->] (0,0) -- (\angle:\bigradius);
}{
\draw[->] (0,0) -- (\angle:1);
};
}
\end{scope}
\draw[MyColor1] (0.5,0) arc (0:150:0.5);
\draw[fill=MyColor1, opacity=0.3] (0,0) -- (0.5,0) arc (0:150:0.5) -- cycle;
\end{tikzpicture}\\
& \\}
\only<2->{%
\only<3>{%
$\begin{pmatrix*}[r] \hphantom{-2} & \hphantom{-1}\\
\hphantom{-1} & \hphantom{-2}
\end{pmatrix*}$}%
\only<4->{%
$\begin{pmatrix*}
\only<4->{-2} & \only<5->{\color<5->{MyColor1}{-1}}\\
\only<5->{\color<5->{MyColor1}{-1}} & \only<4->{-2}
\end{pmatrix*}$}%
&
\only<3>{%
$\begin{pmatrix} \hphantom{-2} & \hphantom{-1}\\
\hphantom{-1} & \hphantom{-2}
\end{pmatrix}$}%
\only<4->{%
$\begin{pmatrix*}[r] \only<4->{-2} & \only<5->{\color<5->{MyColor1}{-1}}\\
\only<5->{\color<5->{MyColor1}{-3}} & \only<3->{-2}
\end{pmatrix*}$}%
}%
\end{tabular}
\end{center}
\end{frame}
\end{document}
O ponto importante é tornar invisíveis os itens que aparecerão apenas em slides especiais nos outros slides. Dessa forma esse material ainda contribui para a caixa delimitadora, evitando assim saltos.
Quanto aos deslocamentos das matrizes, eles vêm de espaços espúrios, que removi adicionando os %caracteres quando apropriado.
Fora do tópico: removi bibliotecas que não estão em uso aqui. Se se deve ou não usar a \ifthenelsemacro quando se tem o pgf à disposição, não sei, mas guardei-a.
Responder2
Apenas por uma questão de solução usandooverlayarea
\documentclass{beamer}
\usepackage{tikz}
\usepackage{ifthen}
\usetikzlibrary{overlay-beamer-styles}
\mode<presentation> {
\usetheme{Boadilla}
\setbeamertemplate{footline}{}% get rid of footer completely
}
\usepackage{booktabs} % Allows the use of \toprule, \midrule and \bottomrule in tables
\usepackage{amssymb, mathtools, amsfonts}
\definecolor{MyColor1}{rgb}{0.24, 0.59, 0.32}
\definecolor{MyColor2}{rgb}{0.85, 0.49, 0.19}
\definecolor{MyColor3}{rgb}{0.22, 0.42, 0.69}
\usefonttheme{serif}
\begin{document}
\begin{frame}\frametitle{Examples}
\begin{overlayarea}{\textwidth}{0.5\paperheight}
\begin{center}
\begin{tabular}{c|c}
\onslide<1->{%
$\langle\alpha,\beta\rangle = \langle\beta,\alpha\rangle =-1$
& $3\langle\alpha,\beta\rangle= \langle\beta,\alpha\rangle=-3$\\\midrule
& \\
\begin{tikzpicture}[scale=0.7, every node/.style={transform shape}]
\draw (-2,-2) rectangle (2,2);
\node (alpha) at (1.2,0) {$\alpha$};
\node (beta) at (120:1.2) {$\beta$};
\draw[->] (0,0) -- (0:1);
\draw[->] (0,0) -- (120:1);
\only<1>{
\foreach \angle in {60,180,240,300}{
\draw[->] (0,0) -- (\angle:1);
}
}
\draw[MyColor1] (0.5,0) arc (0:120:0.5);
\draw[fill=MyColor1, opacity=0.3] (0,0) -- (0.5,0) arc (0:120:0.5) -- cycle;
\end{tikzpicture} &
\begin{tikzpicture}[scale=0.7, every node/.style={transform shape}]
\draw (-2,-2) rectangle (2,2);
\node (alpha) at (1.2,0) {$\alpha$};
\node (beta) at (150:1.9) {$\beta$};
\draw[->] (0,0) -- (150:1.7320);
\draw[->] (0,0) -- (0:1);
\only<1>{
\foreach \angle in {30,60,90,120,180,210,240,270,300,330}{
\pgfmathsetmacro{\bigradius}{sqrt(3)}
\ifthenelse{\angle=30 \OR
\angle=90 \OR
\angle=150 \OR
\angle=210 \OR
\angle=270 \OR
\angle=330}{
\draw[->] (0,0) -- (\angle:\bigradius);
}{
\draw[->] (0,0) -- (\angle:1);
};
}
}
\draw[MyColor1] (0.5,0) arc (0:150:0.5);
\draw[fill=MyColor1, opacity=0.3] (0,0) -- (0.5,0) arc (0:150:0.5) -- cycle;
\end{tikzpicture}\\
& \\}%
\only<2->{%
\only<3>{%
$\begin{pmatrix*}[r] \hphantom{-2} & \hphantom{-1}\\
\hphantom{-1} & \hphantom{-2}
\end{pmatrix*}$}%
\only<4->{%
$\begin{pmatrix*}
\only<4->{-2} & \only<5->{\color<5->{MyColor1}{-1}}\\
\only<5->{\color<5->{MyColor1}{-1}} & \only<4->{-2}
\end{pmatrix*}$}
&
\only<3>{%
$\begin{pmatrix} \hphantom{-2} & \hphantom{-1}\\
\hphantom{-1} & \hphantom{-2}
\end{pmatrix}$}%
\only<4->{%
$\begin{pmatrix*}[r] \only<4->{-2} & \only<5->{\color<5->{MyColor1}{-1}}\\
\only<5->{\color<5->{MyColor1}{-3}} & \only<3->{-2}
\end{pmatrix*}$}%
}%
\end{tabular}
\end{center}
\end{overlayarea}
\end{frame}
\end{document}