Círculo do nó da folha terminal

Question

Esta é uma pergunta de acompanhamento paraesse.

Código:

\documentclass[12pt]{article}
\usepackage{istgame}
\usepackage{tikz}
\usetikzlibrary{shapes,arrows.meta, positioning}

\begin{document}    
    \begin{center}
        \begin{istgame}
            \setistNewNodeStyle{max}
            [regular polygon, regular polygon sides = 3]{1.5cm}
            \setistNewNodeStyle{min}
            [regular polygon, regular polygon sides = 3, shape border rotate = 180]{1.5cm}
            \setistNewNodeStyle{chance}
            [circle]{1.2cm}
            %\xtShowTerminalNodes[box node, minimum size = 1cm]
            \def\distFactor{20};
            \xtdistance{\distFactor mm}{4*\distFactor mm}
            \setxtarrowtips[blue, thick]
            \istroot(0)[max]<center, blue>{1.5}
            \istb[blue, ->-] \istb \endist
            \xtdistance{\distFactor mm}{2*\distFactor mm}
            \istroot(1)(0-1)[chance]<center, purple>{1.5}
            \istb{0.5}[al] \istb{0.5}[ar] \endist
            \istroot(2)(0-2)[chance]<center, purple>{$\leq 1$}
            \istb{0.5}[al] \istb{0.5}[ar] \endist
            \xtdistance{\distFactor mm}{\distFactor mm}
            \istroot(3)(1-1)[min]<center, red>{2}
            \istb{}{2} \istb{}{5000}[[circle, draw, yshift = 2pt, minimum size = 0.75cm] below] \endist
            \istroot(4)(1-2)[min]<center, red>{1}
            \istb{}{1} \istb{}{100}[[circle, draw, yshift = 2pt, minimum size = 0.75cm] below] \endist
            \istroot(5)(2-1)[min]<center, red>{0}
            \istb{}{0} \istb{}{2}[[circle, draw, yshift = 2pt, minimum size = 0.75cm] below] \endist
            \istroot(6)(2-2)[min]
            \istb{}{-1}[[circle, draw, yshift = 2pt, minimum size = 0.75cm] below] \istb{}{0}[[circle, draw, yshift = 2pt, minimum size = 0.75cm] below] \endist
        \end{istgame}
    \end{center}
\end{document}

Saída:

minimum sizefaz parte da solução, mas existe alguma maneira de alinhar os valores terminais com aqueles dentro do círculo maior? (Observe que os valores dos terminais estão listados incorretamente para obter esta saída)

Answer 1

Uma maneira de fazer isso é usar \xtShowEndPointsseguido de xtShowTerminalNodes:

\documentclass[12pt,border=2pt]{standalone}
\usepackage{istgame}
%\usepackage{tikz}
%\usetikzlibrary{shapes,arrows.meta, positioning}

\begin{document}    

\begin{istgame}
\setistNewNodeStyle{max}
  [regular polygon, regular polygon sides = 3]{1.5cm}
\setistNewNodeStyle{min}
  [regular polygon, regular polygon sides = 3, shape border rotate = 180]{1.5cm}
\setistNewNodeStyle{chance}
  [circle]{1.2cm}
\def\distFactor{20};
\xtdistance{\distFactor mm}{4*\distFactor mm}
\setxtarrowtips[blue, thick]
\istroot(0)[max]<center, blue>{1.5}
  \istb[blue, ->-] 
  \istb 
  \endist
\xtdistance{\distFactor mm}{2*\distFactor mm}
\istroot(1)(0-1)[chance]<center, purple>{1.5}
  \istb{0.5}[al] 
  \istb{0.5}[ar] 
  \endist
\istroot(2)(0-2)[chance]<center, purple>{$\leq 1$}
  \istb{0.5}[al] 
  \istb{0.5}[ar] 
  \endist
%% terminal nodes with or without circles (TRICK!!)
\xtShowEndPoints[circle,draw,minimum size=1.1cm] % comes before \xtShowTerminalNodes
\xtShowTerminalNodes[circle,draw=none,minimum size=1.1cm]
\xtdistance{\distFactor mm}{\distFactor mm}
\istroot(3)(1-1)[min]<center, red>{2}
  \istbt{}{2}[center]   %
  \istb{}{5000}[center] 
  \endist
\istroot(4)(1-2)[min]<center, red>{1}
  \istbt{}{1}[center]   %
  \istb{}{100}[center] 
  \endist
\istroot(5)(2-1)[min]<center, red>{0}
  \istbt{}{0}[center]   %
  \istb{}{2}[center] 
  \endist
\istroot(6)(2-2)[min]
  \istb{}{-1}[center] 
  \istb{}{0}[center] 
  \endist
\end{istgame}

\end{document}