我在 if 語句中遇到困難
我希望每當記憶體使用率或 CPU 使用率超過 70% 時就會彈出「系統利用率很高」的訊息,現在我在 if 語句中嘗試了以下 2 個條件,但它給了我錯誤。
# This script monitors CPU and memory usage
RED='\033[0;31m'
NC='\033[0m' # No Color
while :
do
# Get the current usage of CPU and memory
limit=70.0
cpuUsage=$(top -bn1 | awk '/Cpu/ { print $2}')
memTotal=$(free -m | awk '/Mem/{print $2}')
memUsage=$(free -m | awk '/Mem/{print $3}')
memUsage=$(( (memUsage * 100) / memTotal ))
# Print the usage
echo "CPU Usage: $cpuUsage%"
echo "Memory Usage: $memUsage%"
# Sleep for 1 second
sleep 1
if (( $(echo "$cpuUsage > $limit ; $memUsage > $limit" |bc -l) ))
then
printf "${RED}The system is highly utilized${NC}\n"
else
echo The system is not highly utilized
fi
done
據我所知;執行檢查第一個條件,然後無論是否成功都轉到第二個條件。無論如何,我收到此錯誤:0:表達式中的語法錯誤(錯誤標記為“0”)
答案1
bc
理解||
並且&&
。
if (( $(echo "$cpuUsage > $limit || $memUsage > $limit" | bc -l) ))
答案2
儘管(如您所見),您可以使用 GNU bc (和 busybox bc)中的邏輯來組合表達式,但 POSIX 1||
不支援它。
由於您已經使用 awk 來解析top
和free
輸出,因此另一種方法是在 awk 中進行算術和關係測試 - 然後您可以在 shell 中使用簡單的整數比較(甚至不需要 bash):
#!/bin/sh
# This script monitors CPU and memory usage
RED='\033[0;31m'
NC='\033[0m' # No Color
limit=${1:-70.0}
while :
do
# Get the current usage of CPU and memory
top -bn1 | awk -v limit="$limit" '
/^%Cpu/ {printf "CPU Usage: %.1f%%\n", $2; exit ($2+0 > limit ? 1 : 0)}
'
cpuHi=$?
free -m | awk -v limit="$limit" '
/^Mem/ {usage = 100*$3/$2; printf "Memory Usage: %.0f%%\n", usage; exit (usage > limit ? 1 : 0)}
'
memHi=$?
sleep 1
if [ "$cpuHi" -ne 0 ] || [ "$memHi" -ne 0 ]
then
printf "${RED}The system is highly utilized${NC}\n"
else
printf "The system is not highly utilized\n"
fi
done
事實上,POSIX bc 甚至不支援條件構造或循環之外的關係運算符,例如:
$ echo '2 > 1 || 1 > 2' | bc 1
但啟用警告後:
$ echo '2 > 1 || 1 > 2' | bc -w (standard_in) 1: (Warning) || operator (standard_in) 2: (Warning) comparison in expression 1
與 busybox 類似
$ echo '2 > 1 || 1 > 2' | busybox bc -w bc: POSIX does not allow boolean operators; this is bad: || bc: POSIX does not allow comparison operators outside if or loops 1
答案3
擴充一下@choroba 的答案:
echo "$cpuUsage > $limit ; $memUsage > $limit" |bc -l
將輸出2行。
示範
$ set -x
+ set -x
$ ans=$(echo "1==1; 2==1" | bc -l)
++ bc -l
++ echo '1==1; 2==1'
+ ans='1
0'
$ if (( $ans )); then echo yes; fi
+ (( 1
0 ))
bash: ((: 1
0 : syntax error in expression (error token is "0 ")