使用 grep 顯示文本中不同行上 3 個單字之間的文本

Question

我想顯示 1 個文件中文字中 3 個單字之間的文字：

lalala
<ticket>
BASH is awesome
BASH is awesome1
</ticket>
lalalala
<ticket>
BASH is awesome2
BASH is awesome3
texttext
</ticket>
lololo
<ticket>
awesome
BASH is awesome4
BASH is awesome5
</ticket>
lalalla

我試試這個：

grep -Pzo '(?s)<ticket>.*\n.*awesome3.*\n.*</ticket>' file.txt

結果：

<ticket>
BASH is awesome
BASH is awesome1
</ticket>
lalalala
<ticket>
BASH is awesome2
BASH is awesome3
texttext
</ticket>
lololo
<ticket>
awesome
BASH is awesome4
BASH is awesome5
</ticket>

期望：

<ticket>
BASH is awesome2
BASH is awesome3
texttext
</ticket>

Answer 1

使用以下內容grep方法：

grep -Pzo '(?s)<ticket>[^<>]*?awesome3.*?</ticket>' file.txt

輸出：

<ticket>
BASH is awesome2
BASH is awesome3
texttext
</ticket>

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*?- 非貪婪修飾符