如何使用 tr 刪除八進位字元序列?

如何使用 tr 刪除八進位字元序列?

我正在嘗試從 .dat 檔案中刪除此: --More--這是該檔案的一個片段,舉個例子:

Device ID: N7K-LAN(JAF1651ANDL)
  IP address: 148.228.4.192
Interface: GigabitEthernet0/1,  Port ID (outgoing port): Ethernet7/19
Device ID: CIRC_INF_IDF1
  IP address: 148.228.107.252
Interface: FastEthernet0/20,  Port ID (outgoing port): GigabitEthernet0/1
  IP address: 148.228.107.252
Device ID: CIRC_INF_IDF3
  IP address: 148.228.107.250
 --More--         Interface: FastEthernet0/23,  Port ID (outgoing port): GigabitEthernet0/1
  IP address: 148.228.107.250
Device ID: CIRC_INF_IDF2
  IP address: 148.228.107.251
Interface: FastEthernet0/22,  Port ID (outgoing port): GigabitEthernet0/1
  IP address: 148.228.107.251
Device ID: SEP1CAA0711CFBE
 --More--           IP address: 148.228.199.103
Interface: FastEthernet0/2,  Port ID (outgoing port): Port 1
Device ID: SEP1CAA0711CD67
  IP address: 148.228.199.154
Interface: FastEthernet0/5,  Port ID (outgoing port): Port 1

使用十六進製文字編輯器我已經識別了不可見的字符 在此輸入影像描述

現在我試圖刪除整個字元序列但我還沒有成功,

這些是我的嘗試:

tr -d --More--           < tabladetallada.dat >temporaltabla.dat

tr -d '\015' '\012' '\20' '\055' '\055' '\115' < tabladetallada.dat >temporaltabla.dat

sed 's/--More--␣//' tabladetallada.dat>tabladetallada2.dat

tr -d ' --More-- ^H^H^H^H^H^H^H^H^H        ^H^H^H^H^H^H^H^H^H' < tabladetallada.dat >temporaltabla.dat

有什麼幫助嗎?

謝謝。

這是它在 vi 的樣子:

Device ID: N7K-LAN(JAF1651ANDL)^M
  IP address: 148.228.4.192^M
Interface: GigabitEthernet0/1,  Port ID (outgoing port): Ethernet7/19^M
Device ID: CIRC_INF_IDF1^M
  IP address: 148.228.107.252^M
Interface: FastEthernet0/20,  Port ID (outgoing port): GigabitEthernet0/1^M
  IP address: 148.228.107.252^M
Device ID: CIRC_INF_IDF3^M
  IP address: 148.228.107.250^M
 --More-- ^H^H^H^H^H^H^H^H^H        ^H^H^H^H^H^H^H^H^HInterface: FastEthernet0/23,  Port ID (outgoing port): GigabitEthernet0/1^M
  IP address: 148.228.107.250^M
Device ID: CIRC_INF_IDF2^M
  IP address: 148.228.107.251^M
Interface: FastEthernet0/22,  Port ID (outgoing port): GigabitEthernet0/1^M
  IP address: 148.228.107.251^M
Device ID: SEP1CAA0711CFBE^M
 --More-- ^H^H^H^H^H^H^H^H^H        ^H^H^H^H^H^H^H^H^H  IP address: 148.228.199.103^M
Interface: FastEthernet0/2,  Port ID (outgoing port): Port 1^M
Device ID: SEP1CAA0711CD67^M
  IP address: 148.228.199.154^M
Interface: FastEthernet0/5,  Port ID (outgoing port): Port 1^M
Device ID: SEP1CAA0711D11A^M
  IP address: 148.228.199.4^M
Interface: FastEthernet0/10,  Port ID (outgoing port): Port 1^M
Device ID: SEPece1a985bb74^M
  IP address: 148.228.199.21^M
Interface: FastEthernet0/12,  Port ID (outgoing port): Port 1^M
Device ID: SEPf84f5794c5c4^M
  IP address: 148.228.199.23^M
Interface: FastEthernet0/11,  Port ID (outgoing port): Port 1^M
Device ID: SEP1CAA0711D276^M
  IP address: 148.228.199.102^M
 --More-- ^H^H^H^H^H^H^H^H^H        ^H^H^H^H^H^H^H^H^HInterface: FastEthernet0/9,  Port ID (outgoing port): Port 1^M
Device ID: SEPece1a985b5d5^M
  IP address: 148.228.199.24^M
Interface: FastEthernet0/14,  Port ID (outgoing port): Port 1^M
Device ID: SEP1CAA0711497C^M
Interface: FastEthernet0/4,  Port ID (outgoing port): Port 1^M
Device ID: SEPf84f5794c8c2^M
  IP address: 148.228.199.22^M
Interface: FastEthernet0/3,  Port ID (outgoing port): Port 1^M
Device ID: Circulo_Camaras4^M
 --More-- ^H^H^H^H^H^H^H^H^H        ^H^H^H^H^H^H^H^H^H  IP address: 148.228.101.5^M
Interface: FastEthernet0/24,  Port ID (outgoing port): GigabitEthernet1/0/24^M
  IP address: 148.228.101.5^M

答案1

sed -e 's/^[ ]*--More--.*\x8//' -e 's/\xD$//'

  • s/ */../我個人的偏好不是寫,而是s/[ ]*/../因為當它是空格/製表符時,它會*明顯地附加到左邊的原子上。
  • GNU sed具有六角匹配設施\x十六進位數字順序。

答案2

最簡單的解決方法就是換個角度思考。不要嘗試定義您不需要的字符,而是定義您確實想要的字符並刪除其他任何內容:

sed 's/--More--[^ a-zA-Z0-9]*//' file 

這將刪除該字串--More--及其後的 0 個或多個非空格、字母或數字的字元。根據您的數據,您可能需要稍微調整該設定(例如也允許_或您需要的任何內容)。

現在,您問題中的第一個--More--似乎包含退格字元(八進位 010、十六進位 7、ASCII \b),所以您也可以這樣做:

perl -pe 's/[\b]//g' file

--More--或者,也刪除:

perl -pe 's/--More--[\b]+//g' file

相關內容