代碼是:
#!/bin/bash
ips[0]='192.168.0.1'
ips[1]='192.168.0'
ips[2]='255.255.255.256'
ips[3]='123.123.123.123.123'
ips[4]='a.b.c.d'
ips[5]='255.255.255.255'
ips[6]='0.0.0.0'
ips[7]='192.168.1.1'
ips[8]='4.2.2.2'
regex="^((25[0-5]|2[0-4][0-9]|[01][0-9][0-9]|[0-9]{1,2})[.]){3}(25[0-5]|2[0-4][0-9]|[01][0-9][0-9]|[0-9]{1,2})$"
regexVar=$(printf "\033[33mSaved in a VARIABLE\033[0m")
regexStr=$(printf "\033[34mIs a STRING\033[0m")
validOut=$(printf "\033[32mValid\033[0m")
invalidOut=$(printf "\033[31mInvalid\033[0m")
noQuotes="NO quotes"
singleQuotes="Single quotes"
doubleQuotes="Double quotes"
printStyle="%-25s %-10s %-20s %-10s\n"
printTitle=$(printf "${printStyle}" "IP Address" "Validity" "Regex" "Quote Type")
print2ndLine=$(printf "${printStyle}" "====================" "==========" "====================" "==========")
function validIP1a() {
echo "${printTitle}"
echo "${print2ndLine}"
for (( i=0; i<${#ips[@]}; i++ )); do
if [[ "${ips[i]}" =~ $regex ]]; then
printf "${printStyle}" "${ips[i]}" "${validOut}" "${regexVar}" "${noQuotes}"
else
printf "${printStyle}" "${ips[i]}" "${invalidOut}" "${regexVar}" "${noQuotes}"
fi
done
}
validIP1a
輸出是:
預期輸出為:
為什麼我無法得到預期的結果?怎麼解決呢?
答案1
因為printf
統計了設定顏色的轉義碼中的字元;它不知道它們實際上並沒有打印。您需要將它們放在固定長度格式化 ( %-20s
) 字串之外。這裡比較兩個printf
:
#!/bin/bash
green=$'\033[32m'
yellow=$'\033[33m'
normal=$'\033[0m'
printf "1234567890123456789012345678901234567\n";
printf "%-20s %s\n" "${yellow}some string${normal}" "next col"
printf "${yellow}%-20s${normal} %s\n" "some string" "next col"
輸出應如下所示:
當然,如果顏色可以改變,我們可以把它放在另一個變數中:
printf "%s%-20s${normal} %s\n" "$green" "some string" "next col"
答案2
您可能想要計算validOut
和中的字元數invalidOut
;我數了數,每一個都超過10個:
# 11 11111
# 1 2245678901 23456
validOut=$(printf "\033[32mValid\033[0m")
invalidOut=$(printf "\033[31mInvalid\033[0m")
請記住,窮人printf
不可能知道其中一些字元是不可見的並會改變顏色...您請求一個至少包含 10 個字元的左對齊字段,然後繼續用超過 10 個字元的字串填充它;難怪結果不是垂直對齊的。