使用 bash 腳本僅選擇/查看日誌檔案中的特定數據

使用 bash 腳本僅選擇/查看日誌檔案中的特定數據

我的 NAS 會建立以下格式的日誌檔案:

<30>1 2014-07-21T05:02:10+02:00 ABC-NAS qlogd 6432 - - qlogd[6432]: event log: Users: Glacier, Source IP: 127.0.0.1, Computer name: localhost, Content: [Glacier] Backup job [Backup ABC-PC] finished successfully

<30>1 2014-07-21T05:02:27+02:00 ABC-NAS qlogd 6432 - - qlogd[6432]: event log: Users: Glacier, Source IP: 127.0.0.1, Computer name: localhost, Content: [Glacier] Backup job [Backup ABC-HTPC] finished successfully

<28>1 2014-07-21T05:10:59+02:00 ABC-NAS qlogd 6920 - - qlogd[6920]: event log: Users: Glacier, Source IP: 127.0.0.1, Computer name: localhost, Content: [Glacier] Backup job [Backup ABC-NAS] is abnormal shutdown

<30>1 2014-07-21T06:00:15+02:00 ABC-NAS qlogd 6920 - - qlogd[6920]: event log: Users: Glacier, Source IP: 127.0.0.1, Computer name: localhost, Content: [Glacier] Backup job [Backup ABC Metadata] started

<30>1 2014-07-21T06:00:27+02:00 ABC-NAS qlogd 6920 - - qlogd[6920]: event log: Users: Glacier, Source IP: 127.0.0.1, Computer name: localhost, Content: [Glacier] Backup job [Backup ABC Metadata] finished successfully

使用 BASH 腳本我想建立一個僅包含以下內容的文字檔案:

Monday 21 July 2014 - 04:10 AM
Glacier Backup job [Backup ABC-PC] finished successfully

Monday 21 July 2014 - 07:02 AM
Glacier Backup job [Backup ABC-HTPC] finished successfully

等等。

我一直在嘗試使用 cat 和 grep,但它很快對我來說就變得太複雜了。誰能幫助我朝著正確的方向前進?

答案1

這是一個超級簡單的暴力破解 bash 腳本

cat log | cut -d " " -f 2,20- | while read -r date message; do
  echo $date
  echo $message
done

樣本輸出

2014-07-21T05:02:10+02:00
[Glacier] Backup job [Backup ABC-PC] finished successfully


2014-07-21T05:02:27+02:00
[Glacier] Backup job [Backup ABC-HTPC] finished successfully

如果你想要更多的功能,那我強烈建議你學習Python。

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