我如何使用批次命令搜尋“//packages/thirdparty/release/main.txt #10”並將#10替換為#15(set VARIABLE =“#15”)忽略空間。 #10 可以是任何東西,讓我們假設#XXX。 命令列中的範例是首選。
測試日誌.txt
//packages/thirdparty/release/config.txt #8
//packages/thirdparty/release/config2.txt #3
//packages/thirdparty/release/config1.txt #4
//packages/thirdparty/release/main.txt #10
這是我的嘗試
@ECHO OFF
set $FindStr=//packages/thirdparty/release/main.txt#10
set $ReplString=//packages/thirdparty/release/main.txt#15
setlocal enabledelayedexpansion
for /f "delims=" %%a in ('type testlog.txt') do (
set $Ver=%%a
set $Ver=!$Ver: =!
If /i !$Ver!==%$FindStr% set $Ver=%$ReplString%
echo !$Ver! ) >> testlog.txt
答案1
你可以使用複製蝙蝠腳本來執行此操作。只需保存並運行它,如下所示:
type testlog.txt|repl.bat "#\d\d?$" "#15"
如果你只想替換某個數字那你只需要稍微修改一下:
type testlog.txt|repl.bat "#10$" "#15"
如果您想要更多地控制如何替換內容,那麼您可以使用另一個腳本:
@ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
COPY /A testlog.txt textlog.out.txt >nul
SET VARIABLE=0
FOR %%S IN ( 1 3 4 8 10 20 ) DO (
SET /A VARIABLE=!VARIABLE!+1
COPY /A textlog.out.txt textlog.tmp.txt >nul
TYPE textlog.tmp.txt|repl.bat "#%%S$" "#!VARIABLE!" > textlog.out.txt
)
DEL textlog.tmp.txt
ENDLOCAL