
我正在嘗試使用下面的 echo 命令將一些配置複製到 unix 端點,複製後我發現很少有字元丟失或有時會出現前綴。下面的例子。
這裡需要您的建議。
set system login user b48368 authentication encrypted-password '$1$trz5zI9f$2jL1PHnXNxY/'
set system login user b48368 authentication plaintext-password ''
set system login user bb0k93 authentication encrypted-password '$1$/y8uENjM$C7WQQZDQRbRJOeh/'
set system login user bb0k93 authentication plaintext-password ''
set system login user bb0k93 level 'admin'
set system login user bb0r4w authentication encrypted-password '$1$2.i88iIa$ZkREPOKUNjaJflNJ4/'
set system login user bb0r4w authentication plaintext-password ''
set system login user 430140 authentication encrypted-password '$1$qs.a5lXh$zjsssrtmCjsaSIfAv1'
set system login user 430140 authentication plaintext-password ''
set system login user 430140 level 'admin'
set system login user pa3n authentication encrypted-password '$1$yffNZqPG$EpMR/2RxniVYq0'
set system login user pat3n authentication plaintext-password ''
set system login user pa4n authentication encrypted-password '$1$NKWjQnX8$ZExZcYAm7ECEyI2/'
set system login user pa4n authentication plaintext-password ''
set system login user pa5n authentication encrypted-password '$1$8Km21dzm$q2NlHcRlZX1Oc6M0'
set system login user pa5n authentication plaintext-password ''
set system login user pa6n authentication encrypted-password '$1$qjkBDXXU$vJn4o6gF7aK/i/'
set system login user patn authentication plaintext-password ''
set system login user root authentication encrypted-password '$1$T1PHVDEj$UXtfPX/yuGtm0'
set system login user root authentication plaintext-password ''
複製輸出,缺少一些字符
set system login user a48368 authentication encrypted-password 'jL1hU238TJXNxY/'
set system login user a48368 authentication plaintext-password ''
set system login user ab0k93 authentication encrypted-password '$/y8uENjM/'
set system login user ab0k93 authentication plaintext-password ''
set system login user ab0k93 level 'admin'
set system login user ab0r4w authentication encrypted-password '.i88iIa/'
set system login user ab0r4w authentication plaintext-password ''
set system login user 430140 authentication encrypted-password '.a5lXh'
set system login user 430140 authentication plaintext-password ''
set system login user 430140 level 'admin'
set system login user pt3n authentication encrypted-password '/2RxnpQU7CiVYq0'
set system login user pa3n authentication plaintext-password ''
set system login user pa4n authentication encrypted-password '/'
set system login user pa4n authentication plaintext-password ''
set system login user pa5n authentication encrypted-password 'Km21dzm'
set system login user pa5n authentication plaintext-password ''
set system login user pa6n authentication encrypted-password '/oAi/'
set system login user pa6n authentication plaintext-password ''
set system login user root authentication encrypted-password '/yuGtuKm0'
答案1
當您使用 echo 命令時,您很可能已將其用雙引號引起來。這允許對文本進行一些解釋 - 特別是 $XXX 被識別為變數 XXX 並且對它的引用將被替換為該變數的內容(通常沒有)。
為了解決這個問題,您需要以不同的方式輸入資料或正確地轉義字串 - 您很可能在您的情況下通過在“$”符號前加上“\”來確保它被按字面意思解釋。
您沒有建議您如何使用它(例如原始程式碼),但處理它的另一種方法可能是使用“這裡的文件”,它允許您將來源檔案的輸入視為原始文字並將其重定向