分支字串是24000ACB
,我如何將其取出sed
?
我試過echo 'origin/releases/2400ACB 294125569b2dc926158b64115f1467f916c9 WIP' | sed 's/[origin/releases/]//g'
。
答案1
origin/releases/
列印以下包含多個非空格字元的部分:
echo 'origin/releases/2400ACB 294125569b2dc926158b64115f1467f916c9 WIP' | sed -n 's/origin\/releases\/\([^ ]\+\).*/\1/p'
或列印最後一個/
包含多個非空格字元的部分:
echo 'origin/releases/2400ACB 294125569b2dc926158b64115f1467f916c9 WIP' | sed -n 's/.*\/\([^ ]\+\).*/\1/p'
答案2
嘗試echo 'origin/releases/2400ACB 294125569b2dc926158b64115f1467f916c9 WIP' | sed 's/[origin/releases/]//g' | awk '{print $1}'