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如何直接顯示已知dll ID的圖示？

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如何直接顯示已知dll ID的圖示？

有人知道如何直接以「註冊表」格式顯示圖示嗎？例如“%SystemRoot%\system32\shell32.dll,112”，即 C:\Windows\System32\shell32.dll,112，通常是圖示的 ID，因為它可以在「IconPath」值的登錄資料中找到。該路徑是真實的，“112”圖標代碼只是一個隨機數字。

重點是，當 dll 由數百個圖示組成時，即使使用像這樣的工具，找到正確的圖示也很麻煩圖示擷取器，當遊標懸停在圖示上時將顯示圖示資訊。所有這些工具似乎只是以相反的方式起作用：必須加載 dll，然後希望找到帶有相應程式碼的圖示。

答案1

文件類型的圖示是嵌入已知DLL中的資源（即任何類型的圖像、媒體等）。該圖示編號（或圖示組索引）不是隨機的。 DLL 檔案有一個部分來儲存這些資源。每個圖示都儲存有唯一的編號。一種類型的圖示可以由不同的圖示大小、尺寸和位元深度組成。此圖示 ID 來自圖示群組編號，因此當使用者更改縮放等級時，它僅更改圖示大小而不更改圖示本身。

透過一個例子就可以很容易地理解這一點。對於這種情況，我使用資源駭客。以下是 Resource Hacker 中捷徑檔案（.LNK 副檔名）的圖示截圖（圖示可能有所不同）：

Resource_Hacker_Shell32

這是註冊表設定：

Windows Registry Editor Version 5.00
[HKEY_LOCAL_MACHINE\SOFTWARE\Classes\.lnk\ShellNew]
"Handler"="{ceefea1b-3e29-4ef1-b34c-fec79c4f70af}"
"IconPath"="%SystemRoot%\system32\shell32.dll,-16769"
"ItemName"="@shell32.dll,-30397"
"MenuText"="@shell32.dll,-30318"
"NullFile"=""

看到數字“16769”，將其與螢幕截圖進行匹配。但如何打開它資源駭客？答案：下載並執行該軟體 --> 複製shell32.dll（或任何 dll/exe 檔案）到桌面/工作資料夾 --> 將該檔案拖曳到 Resource Hacker 視窗中 --> 雙擊「圖示群組」 --> 捲動到那個數字。請注意，一個圖標組中有許多圖標，其尺寸為 16x16、20x20 等。

答案2

當dll由數百個圖示組成時，找到正確的圖示很麻煩

您可以使用以下 Powershell 腳本.\DisplayIcon.ps1：

<#
.SYNOPSIS
    Exports an ico and bmp file from a given source to a given destination
.Description
    You need to set the Source and Destination locations. First version of a script, I found other examples 
    but all I wanted to do as grab and ico file from an exe but found getting a bmp useful. Others might find useful
.EXAMPLE
    This will run but will nag you for input
    .\Icon_Exporter.ps1
.EXAMPLE
    this will default to shell32.dll automatically for -SourceEXEFilePath
    .\Icon_Exporter.ps1 -TargetIconFilePath 'C:\temp\Myicon.ico' -IconIndexNo 238
.EXAMPLE
    This will give you a green tree icon (press F5 for windows to refresh Windows explorer)
    .\Icon_Exporter.ps1 -SourceEXEFilePath 'C:/Windows/system32/shell32.dll' -TargetIconFilePath 'C:\temp\Myicon.ico' -IconIndexNo 41

.Notes
    Based on http://stackoverflow.com/questions/8435/how-do-you-get-the-icons-out-of-shell32-dll Version 1.1 2012.03.8
    New version: Version 1.2 2015.11.20 (Added missing custom assembly and some error checking for novices)
#>
Param ( 
    [parameter(Mandatory = $true)]
    [string] $SourceEXEFilePath = 'C:/Windows/system32/shell32.dll',
    [parameter(Mandatory = $true)]
    [string] $TargetIconFilePath,
    [parameter(Mandatory = $False)]
    [Int32]$IconIndexNo = 0
)

$code = @"
using System;
using System.Drawing;
using System.Runtime.InteropServices;

namespace System
{
    public class IconExtractor
    {

     public static Icon Extract(string file, int number, bool largeIcon)
     {
      IntPtr large;
      IntPtr small;
      ExtractIconEx(file, number, out large, out small, 1);
      try
      {
       return Icon.FromHandle(largeIcon ? large : small);
      }
      catch
      {
       return null;
      }

     }
     [DllImport("Shell32.dll", EntryPoint = "ExtractIconExW", CharSet = CharSet.Unicode, ExactSpelling = true, CallingConvention = CallingConvention.StdCall)]
     private static extern int ExtractIconEx(string sFile, int iIndex, out IntPtr piLargeVersion, out IntPtr piSmallVersion, int amountIcons);

    }
}
"@

If  (-not (Test-path -Path $SourceEXEFilePath -ErrorAction SilentlyContinue ) ) {
    Throw "Source file [$SourceEXEFilePath] does not exist!"
}

[String]$TargetIconFilefolder = [System.IO.Path]::GetDirectoryName($TargetIconFilePath) 
If  (-not (Test-path -Path $TargetIconFilefolder -ErrorAction SilentlyContinue ) ) {
    Throw "Target folder [$TargetIconFilefolder] does not exist!"
}

Try {
    If ($SourceEXEFilePath.ToLower().Contains(".dll")) {
        Add-Type -TypeDefinition $code -ReferencedAssemblies System.Drawing
        $Icon = [System.IconExtractor]::Extract($SourceEXEFilePath, $IconIndexNo, $true)    
    } Else {
        [void][Reflection.Assembly]::LoadWithPartialName("System.Drawing")
        [void] [System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms")
        $image = [System.Drawing.Icon]::ExtractAssociatedIcon("$($SourceEXEFilePath)").ToBitmap()
        $bitmap = new-object System.Drawing.Bitmap $image
        $bitmap.SetResolution(72,72)
        $icon = [System.Drawing.Icon]::FromHandle($bitmap.GetHicon())
    }
} Catch {
    Throw "Error extracting ICO file"
}

Try {
    $stream = [System.IO.File]::OpenWrite("$($TargetIconFilePath)")
    $icon.save($stream)
    $stream.close()
} Catch {
    Throw "Error saving ICO file [$TargetIconFilePath]"
}
Write-Host "Icon file can be found at [$TargetIconFilePath]"

# Loosely based on http://www.vistax64.com/powershell/202216-display-image-powershell.html

[void][reflection.assembly]::LoadWithPartialName("System.Windows.Forms")

$img = [System.Drawing.Image]::Fromfile($TargetIconFilePath);

# This tip from http://stackoverflow.com/questions/3358372/windows-forms-look-different-in-powershell-and-powershell-ise-why/3359274#3359274
[System.Windows.Forms.Application]::EnableVisualStyles();
$form = new-object Windows.Forms.Form
$form.Text = "Image Viewer"
$form.Width = $img.Size.Width;
$form.Height =  $img.Size.Height;
$pictureBox = new-object Windows.Forms.PictureBox
$pictureBox.Width =  $img.Size.Width;
$pictureBox.Height =  $img.Size.Height;

$pictureBox.Image = $img;
$form.controls.add($pictureBox)
$form.Add_Shown( { $form.Activate() } )
$form.ShowDialog()
#$form.Show();

輸出範例：

> .\DisplayIcon.ps1 -SourceEXEFilePath 'C:\Windows\system32\shell32.dll' -TargetIconFilePath 'f:\test\Myicon.ico' -IconIndexNo 41
Icon file can be found at [f:\test\Myicon.ico]

在此輸入影像描述

筆記：

  • 該腳本是使用下面列出的來源建立的。
  • 謝謝本·N在根訪問權限感謝他幫助調試代碼。

資料來源：

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