我有一個像這樣的文字檔：
eeeeeeee6fd6e6e7000000800010884f image_0001.png
eeeeeeee6fd6e6e7000000800010884f image_0002.png
e6eee7afef77c6c7000000808860003b image_0003.png
e6eeefa7cfe777170100000008886033 image_0004.png
e6eeefa7cfe777170100000008886033 image_0005.png
eeeecfe7afcfe7770100000030088c27 image_0006.png
efebefe7a7cfc7e70101080000300c03 image_0007.png
ef6befdf674f97c7000000900200301f image_0008.png
ef6befdf674f97c7000000900200301f image_0009.png
6d6d6faff767479700004008810000e1 image_0010.png
ed6d6dada5f767570000400098830401 image_0011.png
ed6d6dada5f767570000400098830401 image_0012.png
efed6d4da595f7a70202004000181303 image_0013.png
ebececcc2f2797f10000008051043c5b image_0014.png
e9edecce4e6e26ba120101808058042a image_0015.png
e9edecce4e6e26ba120101808058042a image_0016.png
ececeeefcf6f67a61000000080585887 image_0017.png
cc6ceeefcf4f67e710000020000149d8 image_0018.png
cc6cefefefcf6fe71000000040000001 image_0019.png
cc6cefefefcf6fe71000000040000001 image_0020.png
8ceceeefefcfcfe700000000c0000009 image_0021.png
我想使用 Notepad++ 刪除所有重複字串（左側的雜湊值），只保留一個，並將該行的該部分留空，保留右側的檔案名，如下所示：
eeeeeeee6fd6e6e7000000800010884f image_0001.png
image_0002.png
e6eee7afef77c6c7000000808860003b image_0003.png
e6eeefa7cfe777170100000008886033 image_0004.png
image_0005.png
eeeecfe7afcfe7770100000030088c27 image_0006.png
efebefe7a7cfc7e70101080000300c03 image_0007.png
ef6befdf674f97c7000000900200301f image_0008.png
image_0009.png
6d6d6faff767479700004008810000e1 image_0010.png
ed6d6dada5f767570000400098830401 image_0011.png
image_0012.png
...etc.
當然，有許多不同的字串需要替換，因此這並不像人們想像的那麼容易（特別是對於數千個這樣的行）。是否有正規表示式或任何其他方法可以實現此目的？謝謝
答案1
使用 Python 有很多方法可以做到這一點。這是一種方法：
# Note: Your output file must be different to your input file!
# Use absolute filepaths unless the files are in the current working directory.
input_filepath = r"C:\Users\Admin\Desktop\file hashes.txt"
output_filepath = r"C:\Users\Admin\Desktop\file hashes (processed).txt"
hashes = set() # This set keeps track of known file hashes
with open(input_filepath) as fin:
with open(output_filepath, "w") as fout:
# After opening both the input and output files,
# loop over every line in the input file.
for line in fin:
# Get the hash, which is between the start of the line and the first space.
file_hash = line[:line.find(" ")]
# Check if it is in the set of known hashes.
# If it is, write the current line without the hash to the output file.
# If it isn't, write the current line with the hash to the output file,
# and add the hash to our set of known hashes
if file_hash in hashes:
hash_len = len(file_hash)
fout.write(" " * hash_len + line[hash_len:])
else:
fout.write(line)
hashes.add(file_hash)
file hashes (processed).txt好像：
eeeeeeee6fd6e6e7000000800010884f image_0001.png
image_0002.png
e6eee7afef77c6c7000000808860003b image_0003.png
e6eeefa7cfe777170100000008886033 image_0004.png
image_0005.png
eeeecfe7afcfe7770100000030088c27 image_0006.png
efebefe7a7cfc7e70101080000300c03 image_0007.png
ef6befdf674f97c7000000900200301f image_0008.png
image_0009.png
6d6d6faff767479700004008810000e1 image_0010.png
ed6d6dada5f767570000400098830401 image_0011.png
image_0012.png
efed6d4da595f7a70202004000181303 image_0013.png
ebececcc2f2797f10000008051043c5b image_0014.png
e9edecce4e6e26ba120101808058042a image_0015.png
image_0016.png
ececeeefcf6f67a61000000080585887 image_0017.png
cc6ceeefcf4f67e710000020000149d8 image_0018.png
cc6cefefefcf6fe71000000040000001 image_0019.png
image_0020.png
8ceceeefefcfcfe700000000c0000009 image_0021.png
我不確定Python是如何在你的系統中設定的，但是你應該能夠透過將上面的程式碼複製到一個名為類似的檔案中來運行它remove_duplicate_hashes.py，然後透過雙擊它或進入python remove_duplicate_hashes.py命令提示字元來運行它。