如何刪除行中分隔符號之前的重複使用者名稱？

Question

Ctrl+H
找什麼：^((.*?:).+\R)(\2.+\R)+
用。$1
查看環繞
查看 正規表示式
取消選取 . matches newline
Replace all

解釋：

^       # beginning of line
    (       # start group 1
        (       # start group 2
            .*?     # 0 or more any character but newline, not greedy
            :       # a colon
        )       # end group 2
        .+      # 0 or more any character but newline
        \R      # any kind of linebreak (i.e. \r, \n, \r\n)
    )       # end group 1
    (       # group 3, you can use (?: for non capture group
        \2      # back reference to group 2 (i.e. the part before the colon)
        .+      # 0 or more any character but newline
        \R      # any kind of linebreak (i.e. \r, \n, \r\n)
    )+      # end of group 3, may appear 0 or more times

替代品：

$1          # content of group 1, the value of the first line

截圖（之前）：

截圖（之後）：

Answer 1

Ctrl+H
找什麼：^((.*?:).+\R)(\2.+\R)+
用。$1
查看環繞
查看 正規表示式
取消選取 . matches newline
Replace all

解釋：

^       # beginning of line
    (       # start group 1
        (       # start group 2
            .*?     # 0 or more any character but newline, not greedy
            :       # a colon
        )       # end group 2
        .+      # 0 or more any character but newline
        \R      # any kind of linebreak (i.e. \r, \n, \r\n)
    )       # end group 1
    (       # group 3, you can use (?: for non capture group
        \2      # back reference to group 2 (i.e. the part before the colon)
        .+      # 0 or more any character but newline
        \R      # any kind of linebreak (i.e. \r, \n, \r\n)
    )+      # end of group 3, may appear 0 or more times

替代品：

$1          # content of group 1, the value of the first line

截圖（之前）：

截圖（之後）：

如何刪除行中分隔符號之前的重複使用者名稱？

答案1

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