我想知道我將如何做
printf "Credentials found!"
當找到多個憑證時僅一次。
Attempting Dictionary Attack on 192.168.91.130
Credentials Found!
Log into the telnet server by running telnet -l admin 192.168.91.130
When prompted enter the password found 'admin'
Credentials Found!
Log into the telnet server by running telnet -l sfx 192.168.91.130
When prompted enter the password found 'toor'
循環bash
:
for i in "${!user[@]}"; do
printf "The Username & Password is %s : %s\n\n" "${user[i]}" "${pass[i]}" >> SSH-Credentials.txt
printf "${NCB}Credentials Found!${NC}\n\n"
printf "Log into the SSH server by running ${YELLOW}ssh ${user[i]}@$ip${NC}\n\nWhen prompted enter the password found ${YELLOW}'${pass[i]}'\n"
printf "${NC}\n"
done
答案1
$i
您可以進行以下測試:
[[ "$i" -lt 1 ]] && printf "I am only printed once\n"
# OR
(( i < 1 )) && printf "I am only printed once\n"
# OR
! (( i )) && printf "I am only printed once\n"
# OR
[ "$i" -lt 1 ] && printf "I am only printed once\n"
# OR
if [[ "$i" -lt 1 ]]; then
printf "I am only printed once\n"
fi
假設你不使用關聯 bash 數組。
簡而言之:如果索引小於 1,則列印。
為了方便閱讀,我也會分解這些行。路寬。請注意,您也可以說:
printf '%s %s some long text' \
"$var1" "$var2"
使用大寫字母表示變數也是一個壞習慣。
資訊通常也應列印在stderr
, 所以>&2
。
還會使用:
prinf '%s@%s' "${user[i]}" "$ip" >&2
代替:
prinf "${user[i]}@$ip" >&2
答案2
user
如果數組中有元素,則輸出標頭。
if [[ ${#user[@]} -gt 0 ]]; then
printf '%sCredentials Found!%s\n\n' "$NCB" "$NC"
fi
然後做你的循環。
for i in "${!user[@]}"; do
printf 'The Username & Password is %s : %s\n\n' "${user[i]}" "${pass[i]}" >> SSH-Credentials.txt
cat <<END_MESSAGE
Log into the SSH server using ${YELLOW}ssh ${user[i]}@$ip$NC
When prompted, enter the password found: ${YELLOW}${pass[i]}$NC
END_MESSAGE
done