如何刪除第一列為空的行？

Question

輸入：

CC2352345|m,safnlasndfmnyxdcvyxcvyxcv             |klasjdf |3|lasdjflasdf|                    |2345567356
CC3543353|asdfasdffghntz                          |klasjdf |3|lsajdfl |                       |3456561235
CC5634554|asfjmklasdfassasdasasdsdfas             |klasjdf |3|lsajdfl |                       |2345635636
     |masdfjklasdfjasldfjlasjdfklas|          | |       |                       |2345234566
CC4723456|asdjkfasjkldfjaklsjdflkajldkfjlasjdflk  |klasjdf |2|lsajdfl |                       |2345234525
DD3455463|asldfklklfaem,.rtklqerktljekltjklqe     |klasjdf |3|lsajdfl |                       |4565467546

輸出：

CC2352345|m,safnlasndfmnyxdcvyxcvyxcv             |klasjdf |3|lasdjflasdf|                    |2345567356
CC3543353|asdfasdffghntz                          |klasjdf |3|lsajdfl |                       |3456561235
CC5634554|asfjmklasdfassasdasasdsdfas             |klasjdf |3|lsajdfl |                       |2345635636
CC4723456|asdjkfasjkldfjaklsjdflkajldkfjlasjdflk  |klasjdf |2|lsajdfl |                       |2345234525
DD3455463|asldfklklfaem,.rtklqerktljekltjklqe     |klasjdf |3|lsajdfl |                       |4565467546

問題：如何刪除第一列為空的行？

Answer 1

用這個：

sed '/^\s\s*/d' file

甚至：

grep -v '^\s' file

Answer 2

怎麼樣awk，因為沒有提到？

awk -F\| '$1~/\w/' file