有人可以解釋一下 xrandr --scale 是如何運作的嗎?

有人可以解釋一下 xrandr --scale 是如何運作的嗎?

來自文件:

              Changes the dimensions of the output picture.  If the y value is
              omitted,  the  x value will be used for both dimensions.  Values
              larger than 1 lead to a compressed screen (screen dimension big‐
              ger than the dimension of the output mode), and values less than
              1 lead to a zoom in on the output.  This option  is  actually  a
              shortcut version of the --transform option.

咱們試試:

當我打字時,--xrandr --output eDP 1.2x1.2螢幕會變小約 20%(這一點已驗證)

當我打字時,--xrandr --output eDP 0.8x0.8螢幕變得絕對巨大,放大了 20% 以上(這偽造了文件)

當我打字時,--xrandr --output eDP 1x1它會變得更大!它正在放大。

當我打字時,--xrandr --output eDP 1.5x1.5它又變小了。但它仍然大於--scale 1.2x1.2,相對縮放的進一步證據。

當我打字時--xrandr --output eDP 1.5x1.5什麼事也沒有發生。等等——這是否意味著這些變換不是相對應用的?

當我打字時,--xrandr --output eDP 2x2它基本上會回到原來的大小......這不是 2 倍比例! (原始尺寸為 1920x1080,縮放比例為 1 倍)。

--scale的簡寫也是如此--transform,其描述為:

       --transform a,b,c,d,e,f,g,h,i
              Specifies a transformation matrix to apply on the output.  A bi‐
              linear filter is selected automatically unless the --filter  pa‐
              rameter  is  also  specified.  The mathematical form corresponds
              to:
                     a b c
                     d e f
                     g h i
              The transformation is based on homogeneous coordinates. The  ma‐
              trix  multiplied by the coordinate vector of a pixel of the out‐
              put gives the transformed coordinate vector of a  pixel  in  the
              graphic  buffer.  More precisely, the vector (x y) of the output
              pixel is extended to 3 values (x y w), with 1 as the  w  coordi‐
              nate and multiplied against the matrix. The final device coordi‐
              nates of the pixel are then calculated with  the  so-called  ho‐
              mogenic  division  by  the  transformed  w coordinate.  In other
              words, the device coordinates (x' y') of the  transformed  pixel
              are:
                     x' = (ax + by + c) / w'   and
                     y' = (dx + ey + f) / w'   ,
                     with  w' = (gx + hy + i)  .
              Typically,  a  and  e  corresponds to the scaling on the X and Y
              axes, c and f corresponds to the translation on those axes,  and
              g,  h, and i are respectively 0, 0 and 1. The matrix can also be
              used to express more complex transformations  such  as  keystone
              correction,  or  rotation.   For  a rotation of an angle T, this
              formula can be used:
                     cos T  -sin T   0
                     sin T   cos T   0
                      0       0      1
              As a special argument, instead of passing a matrix, one can pass
              the  string  none,  in which case the default values are used (a
              unit matrix without filter).

因此,如果我寫“xrandr --output eDP --scale 1.5x1.5”,這將創建一個變換矩陣:

M = 
  1.5  0    0
  0    1.5  0
  0    0    1

我使用 * 表示點積,(x,y) 是一些座標

所以這等於:

w' = (0x + 0y + 1) = 1
x' = (1.5x + 0y + 1) / w' = 1.5x
y' = (0x + 1.5y + 1) / w' = 1.5y

這需要從最後一個 x,y 座標進行線性和相對變換!可是等等,如果根據文檔,比例值 > 1 應該壓縮輸出,這似乎實際上是在擴展輸出,因為 (x,y) 被乘以 1.5。

我正在使用兩個顯示器,如果這意味著什麼的話,我什至沒有了解它如何影響另一個顯示器的螢幕空間

答案1

我試圖幫助你 - 昨天我讀了文檔,但很難理解。
我在下面畫了這幅畫。

x'=x cos T + y -sin T + c  | a b c
y'=x sin T + y  cos T + f  | d e f   | g=0, h=0, i=1

x 和 y(以顯示器上輸出模式的像素為單位)
x' 和 y'(以圖形緩衝區中螢幕影像的像素為單位)

蘭德爾

我有一台顯示器:例如角度 10 度,比例 1.2 -> cos 10 x 1.2 = 1.1818,sin 10 x 1.2 = 0.2084

xrandr --output "DVI-D-0" --transform 1.1818,-0.2084,0,0.2084,1.1818,0,0,0,1

之後呼叫 xrandr 的輸出xrandr

Screen 0: minimum 8 x 8, current 2270 x 1677, maximum 32767 x 32767
DVI-D-0 connected primary 2176x930+0+0 (normal left inverted right x axis y axis) 531mm x 299mm
   1920x1080     60.00*+
   1680x1050     59.95  
   1600x1200     60.00  
   1440x900      59.89  
   1280x1024     75.02    60.02  
   1280x960      60.00  
   1152x864      75.00  
   1024x768      75.03    70.07    60.00  
   800x600       75.00    72.19    60.32    56.25  
   640x480       75.00    72.81    59.94  
HDMI-0 disconnected (normal left inverted right x axis y axis)
DP-0 disconnected (normal left inverted right x axis y axis)
DP-1 disconnected (normal left inverted right x axis y axis)

2176x930 必須是圖形緩衝區中的圖像
(2176 x cos 10 + 930 x sin 10) / 1.2 = 1920

但我不確定畫中的螢幕(黃色)!

緩衝區頂部像素中的圖像到顯示器螢幕底部之間的距離為:
2176 x sin 10 + 1080 x 1,2=1674,
但這包括空白顯示器,但如果圖像超出顯示器,我敢打賭這幅畫是正確的。

您可以透過以下方式返回舊設定:
xrandr --output "DVI-D-0" --transform 1,0,0,0,1,0,0,0,1

保存您打開的每個文件,有兩次我崩潰了,我的顯示器沒有信號,因為輸入錯誤,不得不重新啟動!

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