我正在嘗試為僅滿足一周中某些日子(M,W)的課程編寫課程大綱。我想查看上課日期,並根據日期提前 2 天或 5 天。以下程式碼似乎不起作用(在\ifthenelse
語句處失敗)
\documentclass{article}
\usepackage{advdate}
\usepackage[ddmmyyyy]{datetime}
\usepackage{tikz}
\newdateformat{syldate}{\THEMONTH/\THEDAY%(\shortdayofweekname%{\THEDAY}{\THEMONTH}{\THEYEAR})}
\newcommand{\class}[1]{
\def \currday {\shortdayofweekname{\the\day}{\the\month}{\the\year}}
\ifthenelse{\equal{\currday}{Mon}}{\AdvanceDate[2]}{\AdvanceDate[5]}
\section* {\syldate{\today} \quad #1}
}
\SetDate[06/01/2014]
\begin{document}
\class{First Class}
\class{Second class}
\class{Class after holiday}
\end{document}
我想這樣做的原因是因為我想檢查它是否\today
在假期列表中,如果是,則自動前進到下一個上課日。關於如何做到這一點有什麼建議嗎?更有效率的程式碼也受到讚賞。
答案1
希望這就是您所追求的:
\documentclass{article}
\usepackage[ddmmyyyy]{datetime}% http://ctan.org/pkg/datetime
\usepackage{advdate}% http://ctan.org/pkg/advdate
\newdateformat{syldate}{\THEMONTH/\THEDAY/\THEYEAR}%(\shortdayofweekname%{\THEDAY}{\THEMONTH}{\THEYEAR})}
\newsavebox{\MONDAY}\savebox{\MONDAY}{Mon}% Mon
\makeatletter
\newcommand{\cleardate}[1]{%
\expandafter\let\csname date@#1@d\endcsname\relax% Clear day
\expandafter\let\csname date@#1@m\endcsname\relax% Clear month
\expandafter\let\csname date@#1@y\endcsname\relax% Clear year
}
\makeatother
\newcommand{\class}[1]{%
\cleardate{mydate}% Clear date
\newdate{mydate}{\the\day}{\the\month}{\the\year}% Store date
\section*{\displaydate{mydate} \quad #1}% Set heading
\setbox1=\hbox{\shortdayofweekname{\getdateday{mydate}}{\getdatemonth{mydate}}{\getdateyear{mydate}}}%
\ifdim\wd1=\wd\MONDAY
\AdvanceDate[2]
\else
\AdvanceDate[5]
\fi%
}
\SetDate[06/01/2014]
\begin{document}
\class{First class}
\class{Second class}
\class{Third class}
\class{Fourth class}
\class{Fifth class}
\class{Sixth class}
\class{Seventh class}
\end{document}
mydate
此流程儲存加入介面的日期datetime
和advdate
。與星期幾的比較是透過測試單字的寬度來完成的Mon
。每個三個字母/短日期都有不同的長度: