命題內部與證明內部的枚舉

命題內部與證明內部的枚舉

我在枚舉時遇到一個問題。當枚舉在命題「內部」完成時,項目的符號與在證明「內部」完成枚舉時看起來不同。

程式碼

\documentclass[11pt,a5paperfootinclude=true,headinclude=true]{scrbook} % KOMA-Script book
\usepackage[T1]{fontenc}                
\usepackage{lipsum}
\usepackage[linedheaders,parts,pdfspacing]{classicthesis} % ,manychapters
\usepackage[bitstream-charter]{mathdesign}
%\usepackage[osf]{libertine}
\titleformat{\section}
  {\normalfont\bfseries}{\thesection}{1em}{}






\usepackage{amsthm}
\usepackage{amsmath}
 \usepackage{multicol}
 \usepackage{IEEEtrantools}

\usepackage{anysize}
\marginsize{0.1\paperwidth}{0.1\paperheight}{2cm}{2cm}
\newcommand{\bigslant}[2]{{\raisebox{.2em}{$#1$}\left/\raisebox{-.2em}{$#2$}\right.}}

\usepackage{enumerate}



\begin{document}



\theoremstyle{plain}
\newtheorem{thm}{Theorem}[chapter] % reset theorem numbering for each chapter

\theoremstyle{definition}
\newtheorem{defn}[thm]{Definition} % definition numbers are dependent on theorem numbers
\newtheorem{exmp}[thm]{Example}

\theoremstyle{corollary}
\newtheorem{cor}[thm]{Corollary}

\theoremstyle{lemma}
\newtheorem{lem}[thm]{Lemma}

\theoremstyle{proposition}
\newtheorem{prop}[thm]{Proposition}
\newcommand{\ndiv}{\hspace{-4pt}\not|\hspace{2pt}}

\begin{prop}
\begin{enumerate}[(a)] % (a), (b), (c), ...
\item
\item
\end{enumerate}
\end{prop}

\begin{proof}
\begin{enumerate}[(a)] % (a), (b), (c), ...
\item
\item
\end{enumerate}
\end{proof}


\end{document}

和結果

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有什麼補救措施可以讓它們看起來相同還是不可能?我們是否也可以參考列舉的項目?

謝謝

答案1

我會使用enumitem比定理和證明中的此類枚舉更靈活的包enumerate,並為定理和證明中的此類枚舉定義一個新環境。

\documentclass[11pt,a5paper,footinclude=true,headinclude=true]{scrbook} % KOMA-Script book
\usepackage[T1]{fontenc}
\usepackage[linedheaders,parts,pdfspacing]{classicthesis} % ,manychapters
\usepackage[bitstream-charter]{mathdesign}

\usepackage{lipsum}
\usepackage{amsmath}
\usepackage{amsthm}

\usepackage{enumitem}

\theoremstyle{plain}
\newtheorem{thm}{Theorem}[chapter] % reset theorem numbering for each chapter
\newtheorem{cor}[thm]{Corollary}
\newtheorem{lem}[thm]{Lemma}
\newtheorem{prop}[thm]{Proposition}

\theoremstyle{definition}
\newtheorem{defn}[thm]{Definition} % definition numbers are dependent on theorem numbers
\newtheorem{exmp}[thm]{Example}

\newenvironment{roster}
 {\begin{enumerate}[font=\upshape,label=(\alph*)]}
 {\end{enumerate}}


\begin{document}



\begin{prop}
\begin{roster}
\item Something
\item Something else
\end{roster}
\end{prop}

\begin{proof}
\begin{roster}
\item Easy
\item The same\qedhere
\end{roster}
\end{proof}


\end{document}

請注意,定理聲明應該放在前面,\begin{document}並且您使用的是不存在的樣式。我刪除了不重要的部分。

要結束枚舉中的證明,請使用\qedhere,以便墓碑將放置在最後一行。

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答案2

您可以將項目標籤設定為[\upshape (a)]而不是[(a)]。請注意,這\textup{(a)}不適用於enumarate包,並且佔位符a隱藏在群組中{...}

樣本輸出

\documentclass{article}

\usepackage{amsthm,enumerate}

\newtheorem{theorem}{Theorem}[section]

\begin{document}

\begin{theorem}
  This has two parts.
  \begin{enumerate}[\upshape (a)]
  \item First part.
  \item Second part.
  \end{enumerate}
\end{theorem}

\begin{proof}
  Also two parts to the proof.
  \begin{enumerate}[\upshape (a)]
  \item Proof of first part.
  \item Proof of second part.
  \end{enumerate}
\end{proof}

\end{document}

答案3

與 類似的解決方案enumitem,但強調交叉引用項目within a theorem environment works with enumitem, while it did not with枚舉. I also loaded thesmartref` 包,因為它允許不鍵入正在引用的對象類型,而僅鍵入其標籤 - 這樣,如果定理在更高版本中出現一個命題,您不必進行搜尋和取代。

        \documentclass[11pt,a5paperfootinclude=true,headinclude=true]{scrbook} % KOMA-Script book
        \usepackage[utf8]{inputenc}
        \usepackage[T1]{fontenc}
        \usepackage{lmodern}

        \usepackage{titlesec}
        \titleformat{\section} {\normalfont\bfseries}{\thesection}{1em}{}

        \usepackage{amsthm}
        \usepackage{amsmath}
        \usepackage[shortlabels]{enumitem}

        \usepackage{cleveref}

        \theoremstyle{plain}
        \newtheorem{thm}{Theorem}[chapter] % reset theorem numbering for each chapter

        \theoremstyle{definition}
        \newtheorem{defn}[thm]{Definition} % definition numbers are dependent on theorem numbers \newtheorem{exmp}[thm]{Example}

        \newtheorem{cor}[thm]{Corollary}
        \newtheorem{lem}[thm]{Lemma}
        \newtheorem{prop}[thm]{Proposition}

        \begin{document}

        \begin{prop}\label{pr1}
        \begin{enumerate}[\upshape(a)] % (a), (b), (c), ...
        \item  \label{item1} Once upon a time…
        \item So what?
        \end{enumerate}
        \end{prop}

        \begin{proof} \begin{enumerate}[(a)] % (a), (b), (c), ...
        \item According to \cref{pr1}\ref{item1}

        \item What else? \qedhere

        \end{enumerate}
        \end{proof}
        \end{document} 

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