水平並排對齊方程式

Question

我想水平對齊這兩個並排的方程組。我嘗試這樣做

\documentclass[12pt,letterpaper]{article}
\usepackage{amsmath}
\begin{document}
\begin{center}
\begin{tabular}{p{4cm}p{4cm}}
{\begin{align}
&\alpha =\alpha_{1}=\sqrt[3]{19}\nonumber \\
&\alpha_{2} =\varepsilon\sqrt[3]{19}\nonumber \\
&\alpha_{3} =\varepsilon^2\sqrt[3]{19}\nonumber
\end{align}}
&
{\begin{align}
&\beta =\beta_{1}=\frac{1+\sqrt[3]{19}+\sqrt[3]{19^2}}{3}\nonumber \\
&\beta_{2}=\frac{1+\varepsilon\sqrt[3]{19}+\varepsilon^2\sqrt[3]{19^2}}{3}\nonumber \\
&\beta_{3}=\frac{1+\varepsilon^2\sqrt[3]{19}+\varepsilon\sqrt[3]{19^2}}{3}\nonumber 
\end{align}}
\end{tabular}
\end{center}
\end{document}

我明白了

如何將所有 beta 與 alpha 等級對齊？

Answer 1

該align環境支援多組對齊。而且\nonumber指令沒用：使用align*環境就夠了。我給出兩種可能性：

        \documentclass[12pt,letterpaper]{article}
        \usepackage{amsmath}
        \begin{document}

        \begin{align*}
        \alpha=\alpha_{1}&= \sqrt[3]{19} &\beta=\beta_{1}&= \frac{1+\sqrt[3]{19}+\sqrt[3]{19^2}}{3}\nonumber \\
        \alpha_{2} &= \varepsilon\sqrt[3]{19} & \beta_{2} &= \frac{1+\varepsilon\sqrt[3]{19}+\varepsilon^2\sqrt[3]{19^2}}{3}\\
        \alpha_{3} &= \varepsilon^2\sqrt[3]{19} &\beta_{3} &= \frac{1+\varepsilon^2\sqrt[3]{19}+\varepsilon\sqrt[3]{19^2}}{3}
        \end{align*}
        Other possibility: 
        \begin{align*}
        & \alpha= \alpha_{1}= \sqrt[3]{19}&&\beta=\beta_{1}= \frac{1+\sqrt[3]{19}+\sqrt[3]{19^2}}{3}\nonumber \\
        &\alpha_{2}= \varepsilon\sqrt[3]{19} & &\beta_{2}= \frac{1+\varepsilon\sqrt[3]{19}+\varepsilon^2\sqrt[3]{19^2}}{3}\\
        &\alpha_{3}= \varepsilon^2\sqrt[3]{19} & &\beta_{3}= \frac{1+\varepsilon^2\sqrt[3]{19}+\varepsilon\sqrt[3]{19^2}}{3}
        \end{align*}
        \end{document}