我正在使用漂亮的changes
包。其中基本上提供了三個命令\added
,\deleted
和\replaced
。由於其結構和它所採用的可選參數這一事實,我認為可以簡化其使用。我按照xparse
套件文檔查看是否可以建立一個簡化呼叫的命令。
下面是 MWE。我能夠建立兩個版本的命令,一種版本delete
取決於replace
參數的數量。但我很快就失去了動力。
總之,這裡是我想透過定義新指令來實現的映射\ME
:
\ME{deleted}
映射到\deleted[id=Me]{deleted}
\ME[added]
映射到\added[id=Me]{added}
(或至少等於\ME[added]{}
)\ME[replacing]{replaced}
映射到\replaced[id=Me]{replacing}{replaced}
\ME[comment]{deleted}
映射到\deleted[id=Me, remark={comment}]{deleted}
\ME[comment][added]
映射到\added[id=Me,remark={comment}]{added}
(或等效於\ME[comment][added]{}
)\ME[comment][replacing]{replaced}
映射到\replaced[id=Me, remark={comment}]{replacing}{replaced}
.
微量元素:
\documentclass{article}
\usepackage{changes}
\usepackage{xparse}
\definechangesauthor[name={MyName},color=blue]{ME}
\DeclareDocumentCommand \ME { o m }{%
\IfNoValueTF{#1}{
\deleted[id=ME]{#2}}{
\replaced[id=ME]{#1}{#2}
}
}
%\newcommand{\ME}[1]{\deleted[id=ME]{#1}} %ok
%\newcommand{\ME}[1][]{\added[id=ME]{#1}} % not working
\begin{document}
\added[id=ME,remark={added}]{added}
\deleted[id=ME,remark={deleted}]{deleted}
\replaced[id=ME,remark={replaced}]{replacing}{replaced}
\ME{aaa} % ok
\ME[aaa]{bbb} % ok
\ME[aaa]{} % ok
\ME{remark}[aaa]{}
\end{document}
編輯:總結,到目前為止。感謝 @AxelBall 和 @ChristianHupfer 我得到了這個語法,它幾乎是理想的(除了純註釋),實現如下:
\ME{addonly}
\ME{add}<deleted>
\ME<deleteonly>
\ME[addonlycommet]{addonly}
\ME[adddeletecomment]{add}<delete>
\ME[deleteonlycomment]<deleteonly>
text\ME[commentonly]
最後是星型變體,id
在修訂版中加入了:
\ME*[deleteonlycomment]<deleteonly>
代碼:
\NewDocumentCommand{\ME}{sogd<>}{
\IfBooleanTF#1{
\IfNoValueTF{#2}{\IfNoValueTF{#3}{\IfNoValueF{#4}{\deleted[id=ME]{#4}}}{\IfNoValueTF{#4}{\added[id=ME]{#3}}{\replaced[id=ME]{#3}{#4}}}}{\IfNoValueTF{#3}{\IfNoValueTF{#4}{\added[id=ME,remark={#2}]{}}{\deleted[id=ME, remark={#2}]{#4}}}{\IfNoValueTF{#4}{\added[id=ME,remark={#2}]{#3}}{\replaced[id=ME, remark={#2}]{#3}{#4}}}}
}{
\IfNoValueTF{#2}{\IfNoValueTF{#3}{\IfNoValueF{#4}{\deleted{#4}}}{\IfNoValueTF{#4}{\added{#3}}{\replaced{#3}{#4}}}}{\IfNoValueTF{#3}{\IfNoValueTF{#4}{\added[remark={#2}]{}}{\deleted[remark={#2}]{#4}}}{\IfNoValueTF{#4}{\added[remark={#2}]{#3}}{\replaced[remark={#2}]{#3}{#4}}}}
}
}
答案1
\ME
這裡我們定義一個有三個可選參數的命令:
\ME[optional comment]<deleted content>(added content)
<deleted>
必須給予和中的一個或兩個(added)
,否則命令不執行任何操作(但不會引發錯誤/警告)。
(編輯糾正替換行為。
\documentclass{standalone}
\usepackage{changes}
\usepackage{xparse}
\definechangesauthor[name={MyName},color=blue]{ME}
\NewDocumentCommand{\ME}{od<>d()}{%
\IfNoValueTF{#1}{%
\IfNoValueTF{#2}{%
\IfNoValueF{#3}{%
% (#3)
\added[id=ME]{#3}%
}%
}{%
\IfNoValueTF{#3}{%
% <#2>
\deleted[id=ME]{#2}%
}{% <#2>(#3)
\replaced[id=ME]{#3}{#2}%
}%
}%
}{%
\IfNoValueTF{#2}{%
\IfNoValueF{#3}{%
% [#1](#3)
\added[id=ME,remark={#1}]{#3}%
}%
}{%
\IfNoValueTF{#3}{%
% [#1]<#2>
\deleted[id=ME, remark={#1}]{#2}%
}{% [#1]<#2>(#3)
\replaced[id=ME, remark={#1}]{#3}{#2}%
}%
}%
}%
}
\begin{document}
\begin{tabular}{ll}
\deleted[id=ME]{deleted}
& \ME<deleted> \\
\added[id=ME]{added}
& \ME(added) \\
\replaced[id=ME]{replacing}{replaced}
& \ME<replaced>(replacing)\\
\deleted[id=ME, remark={comment}]{deleted}
& \ME[comment]<deleted> \\
\added[id=ME,remark={comment}]{added}
& \ME[comment](added)\\
\replaced[id=ME, remark={comment}]{replacing}{replaced}
& \ME[comment]<replaced>(replacing)\\
\end{tabular}
\end{document}
如果您擔心使用括號,請不要擔心。xparse
如果您在第三個參數中使用平衡括號,則可以很好地應對;如果您想要一個不平衡的,請將其括在大括號中:\ME(like {(} this)
。
如果您確實想對最後一個參數使用大括號,則可以使用g
說明符:
\NewDocumentCommand{\ME}{od<>g}{...}
編輯
好的,這應該可以滿足您的要求:
\documentclass[border=12pt]{standalone}
\usepackage{changes}
\usepackage{xparse}
\definechangesauthor[name={MyName},color=blue]{ME}
\NewDocumentCommand{\ME}{ogd<>}{%
\IfNoValueTF{#1}{%
\IfNoValueTF{#2}{%
\IfNoValueF{#3}{%
% <#3>
\deleted[id=ME]{#3}%
}%
}{%
\IfNoValueTF{#3}{%
% {#2}
\added[id=ME]{#2}%
}{% {#2}<#3>
\replaced[id=ME]{#2}{#3}%
}%
}%
}{%
\IfNoValueTF{#2}{%
\IfNoValueTF{#3}{%
% [1]
\added[id=ME,remark={#1}]{}%
}{% [#1]<#3>
\deleted[id=ME, remark={#1}]{#3}%
}%
}{%
\IfNoValueTF{#3}{%
% [#1]{#2}
\added[id=ME,remark={#1}]{#2}%
}{% [#1]{#2}<#3>
\replaced[id=ME, remark={#1}]{#2}{#3}%
}%
}%
}%
}
\begin{document}
\begin{tabular}{ll}
\verb|\ME<deleted>|
& \ME<deleted> \\
\verb|\ME{added}|
& \ME{added} \\
\verb|\ME{added}<deleted>|
& \ME{added}<deleted>\\
\verb|\ME[comment]|
& \ME[comment]\\
\verb|\ME[comment]<deleted>|
& \ME[comment]<deleted> \\
\verb|\ME[comment]{added}|
& \ME[comment]{added}\\
\verb|\ME[comment]{added}<deleted>|
& \ME[comment]{added}<deleted>\\
\end{tabular}
\end{document}
輸出:
答案2
這實際上使用了三個可選參數:
\ME[operation driver]<operation argument>[operation comment]
其中任何一個都可以省略,在這種情況下什麼也不會發生。
\documentclass{article}
\usepackage{changes}
\usepackage{xstring}
\usepackage{xparse}
\definechangesauthor[name={MyName},color=blue]{ME}
\DeclareDocumentCommand \MEOrig{ o m }{%
\IfNoValueTF{#1}{
\deleted[id=ME]{#2}}{
\replaced[id=ME]{#1}{#2}
}
}
\DeclareDocumentCommand{\ME}{oD<>{}o}{%
\IfNoValueTF{#1}{%
\IfValueTF{#3}{%
\deleted[id=ME,remark={#3}]{#2}%
}{%
\deleted[id=ME]{#2}%
}%
}{%
\IfStrEq{#1}{added}{%
\IfValueTF{#2}{%
\IfValueTF{#3}{%
\added[id=ME,remark={#3}]{#2}%
}{%
\added[id=ME]{#2}%
}%
}{%
\IfValueTF{#3}{%
\added[id=ME,remark={#3}]{}%
}{%
\added[id=ME]{}%
}%
}%
}{%
\IfStrEq{#1}{replacing}{%
\IfValueTF{#3}{%
\replaced[id=ME,remark={#3}]{replacing}{#2}%
}{%
\replaced[id=ME]{replacing}{#2}%
}%
}{%
% Do nothing in here
}%
}% End of IfStrEq{#1}{added}
}% End of IfNoValueTF{#1}
}
\begin{document}
\added[id=ME,remark={added}]{added}
\deleted[id=ME,remark={deleted}]{deleted}
\replaced[id=ME,remark={replaced}]{replacing}{replaced}
\ME<aaa> % ok
\ME[aaa]<bbb> % ok
\ME[aaa] % ok
\ME<remark>[aaa]
\end{document}