
我有一個 shell 腳本,它本質上是一個帶有一些日誌記錄的單行程式碼,我試圖從 init 腳本運行它。我正在使用daemon
其中的函數/etc/init.d/functions
來運行它,因為 Redhat 似乎不可start-stop-daemon
用。當我呼叫初始化腳本時(/etc/init.d/script start
) 時,它停留在前台,而不是完成並讓進程保持運行。我讓這個腳本守護程式的正確方法是什麼?
要運行的腳本:
# conf file where variables are defined
. /etc/script.conf
echo "Starting..." | logger -i
echo "Monitoring $LOG_LOCATION." | logger -i
echo "Sending to $MONITOR_HOST:$MONITOR_PORT." | logger -i
tail -n 1 -F $LOG_LOCATION |
grep WARN --line-buffered |
/usr/bin/nc -vv $MONITOR_HOST $MONITOR_PORT 2>&1 |
logger -i
初始化腳本:
#!/bin/bash
# Source Defaults
. /etc/default/script
# Source init functions
. /etc/init.d/functions
prog=/usr/local/bin/script.sh
[ -f /etc/script.conf ] || exit 1
RETVAL=0
start()
{
# Quit if disabled
if ! $ENABLED; then
echo "Service Disabled in /etc/default/script"
exit 1
fi
echo "Starting $prog"
daemon $prog
RETVAL=$?
return $RETVAL
}
stop ()
{
echo -n $"Stopping $prog: "
killproc $prog
RETVAL=$?
return $RETVAL
}
reload()
{
echo "Reload command is not implemented for this service."
return $RETVAL
}
restart()
{
stop
start
}
condrestart()
{
echo "Not Implemented."
}
# See how we were called.
case "$1" in
start)
start
;;
stop)
stop
;;
status)
status $prog
;;
restart)
restart
;;
reload)
reload
;;
condrestart)
condrestart
;;
*)
echo $"Usage: $0 {start|stop|status|restart|condrestart|reload}"
RETVAL=1
esac
使用 bash -vx 執行最後約 20 行:
+ case "$1" in
+ start
+ true
+ echo 'Starting /usr/local/bin/script.sh'
Starting /usr/local/bin/script.sh
+ daemon /usr/local/bin/script.sh
+ local gotbase= force=
+ local base= user= nice= bg= pid=
+ nicelevel=0
+ '[' /usr/local/bin/script.sh '!=' /usr/local/bin/script.sh ']'
+ '[' -z '' ']'
+ base=script.sh
+ '[' -f /var/run/script.sh.pid ']'
+ '[' -n '' -a -z '' ']'
+ ulimit -S -c 0
+ '[' -n '' ']'
+ '[' color = verbose -a -z '' ']'
+ '[' -z '' ']'
+ initlog -q -c /usr/local/bin/script.sh
答案1
我在以下位置找到了一個腳本http://www.linuxforums.org/forum/programming-scripting/190279-daemon-etc-init-d-functions-does-not-return-launching-process.html#post897522我可以對其進行修改以滿足我的需要。它手動追蹤 PID 並使用pidof
.我最終不得不修改它來使用,pgrep
因為pidof
無法看到我的腳本的 PID。修改後,效果很好。 *注意,pgrep 似乎僅在完整腳本名稱長度低於 15 個字元時才有效
這就是我最終得到的結果:
#!/bin/bash
#
#
#
# Start on runlevels 3, 4 and 5. Start late, kill early.
# chkconfig: 345 95 05
#
#
#!/bin/bash
# absolute path to executable binary
progpath='/usr/local/bin/script.sh'
# arguments to script
opts=''
# binary program name
prog=$(basename $progpath)
# pid file
pidfile="/var/run/${prog}.pid"
# make sure full path to executable binary is found
! [ -x $progpath ] && echo "$progpath: executable not found" && exit 1
eval_cmd() {
local rc=$1
if [ $rc -eq 0 ]; then
echo '[ OK ]'
else
echo '[FAILED]'
fi
return $rc
}
start() {
# see if running
local pids=$(pgrep $prog)
if [ -n "$pids" ]; then
echo "$prog (pid $pids) is already running"
return 0
fi
printf "%-50s%s" "Starting $prog: " ''
$progpath $opts &
# save pid to file if you want
echo $! > $pidfile
# check again if running
pgrep $prog >/dev/null 2>&1
eval_cmd $?
}
stop() {
# see if running
local pids=$(pgrep $prog)
if [ -z "$pids" ]; then
echo "$prog not running"
return 0
fi
printf "%-50s%s" "Stopping $prog: " ''
rm -f $pidfile
kill -9 $pids
eval_cmd $?
}
status() {
# see if running
local pids=$(pgrep $prog)
if [ -n "$pids" ]; then
echo "$prog (pid $pids) is running"
else
echo "$prog is stopped"
fi
}
case $1 in
start)
start
;;
stop)
stop
;;
status)
status
;;
restart)
stop
sleep 1
start
;;
*)
echo "Usage: $0 {start|stop|status|restart}"
exit 1
esac
exit $?
答案2
我不了解 Redhat,但daemon $prog &
對我來說看起來很奇怪。如果已經有一個用於守護程序的函數,為什麼有必要(並且有用)將此函數本身放在後台?因此嘗試不使用&
.