
我正在使用提供的程式碼這個答案(其本身是基於這) 來抑制 中某些行的行號lstlisting
。這可行,但是在我使用它之後,間距lstinline
變得混亂:
這似乎是因為|\Reactivatenumber{12}|
。這是為什麼?
微量元素:
\documentclass{article}
\usepackage{listings}
\lstset{numbers=left,escapeinside=||, basicstyle=\ttfamily\footnotesize}
\let\origthelstnumber\thelstnumber
\makeatletter
\newcommand*\Suppressnumber{%
\lst@AddToHook{OnNewLine}{%
\let\thelstnumber\relax%
\advance\c@lstnumber-\@ne\relax%
}%
}
\newcommand*\Reactivatenumber[1]{%
\setcounter{lstnumber}{\numexpr#1-1\relax}
\lst@AddToHook{OnNewLine}{%
\let\thelstnumber\origthelstnumber%
\refstepcounter{lstnumber}
}%
}
\makeatother
\begin{document}
This looks fine: \lstinline!some-words-with-minus! more text\dots
\begin{lstlisting}[firstnumber=1]
var myFunc = function() {|\Suppressnumber|
//my function does many great things
//and it's only 10 lines long!|\Reactivatenumber{12}|
}
\end{lstlisting}
This looks awful: \lstinline!some-words-with-minus! some more text
\end{document}
答案1
好的找到了:我需要新增一個%
after \refstepcounter{lstnumber}
。
完整片段:
\let\origthelstnumber\thelstnumber
\makeatletter
\newcommand*\Suppressnumber{%
\lst@AddToHook{OnNewLine}{%
\let\thelstnumber\relax%
\advance\c@lstnumber-\@ne\relax%
}%
}
\newcommand*\Reactivatenumber[1]{%
\setcounter{lstnumber}{\numexpr#1-1\relax}
\lst@AddToHook{OnNewLine}{%
\let\thelstnumber\origthelstnumber%
\refstepcounter{lstnumber}%
}%
}
\makeatother