如何借助“Circuitikz”繪製電路？

Question

我怎麼能用 繪製這個電路CircuiTikz？我發現了很多類似的電路，但這是我第一次使用這個封裝。

我正在使用 Beamer，我想先顯示一個沒有 R 的框架，然後顯示一個 R 與 C 平行的框架。

這是我找到並部分修改的程式碼：

\begin{circuitikz}
\draw (6,2) node[op amp] (opamp2) {}
(4,2.5) to [ground]  (opamp2.-) 
(4.8,1) node [ground] {}to [short] (opamp2.+)
(opamp2.-) -- +(0,1.5) to[C] +(2.3,1.5) -|
(opamp2.out) to [short,-o] (8,2)node[right]{};
\end{circuitikz}

Answer 1

大約一年前（也許更多）我對類似問題提供了以下解釋：

%%%% circuitikz-explanation
    \documentclass[margin=3mm]{standalone}
\usepackage{circuitikz}
    \usetikzlibrary{calc}

\begin{document}
    \begin{circuitikz}[every pin/.append style={align=left, text=blue}]
    \scriptsize
%---------------------------------------------------------------%
% circuit part
  \draw
  (0, 0) node[op amp] (opamp) {\textcolor{blue}{OA}}
  (opamp.-) to[R] (-3, 0.5)
  (opamp.-) to[short,*-] ++(0,1.5) coordinate (leftC)
  to[C] (leftC -| opamp.out)
  to[short,-*] (opamp.out);
%---------------------------------------------------------------%
% explanation part

\node[pin=above left: \textcolor{red}{opamp.-}: coordinates of\\
                      OA's inverting (negative)\\
                      input] at (opamp.-) {};
\node[pin=above left: \textcolor{red}{++(0,1.5)} -- vertical offset \\
                      OA's inverting imput named     \\
                      "opamp.-" determine position   \\
                      of the coordinate (leftC)
                      ] at ($(opamp.-)+(0,1.5)$) {};
\node[pin=above right: \textcolor{red}{leftC $-|$ opamp.out}:\\
                      determine the coordinate of\\
                      intersection of lines:\\
                      horizontal from C and \\
                      vertical from OA output\\
                      (see dashed red lines)] at (leftC -| opamp.out) {};
    \draw[dashed, red]  (leftC) -- + (31mm,0)
                        (opamp.out) -- + (0,31mm);
\node[pin=below right:\textcolor{red}{opamp} is name of     \\
                      coordinates {(0,0)}. They\\
                      determine the position\\
                      of OA] at (0,0) {};
\node[pin=below left:OA's non inverting input\\
                      (not used)] at (opamp.+) {};
\node[pin=above right:\textcolor{red}{opamp.out} is name of     \\
                      OA's output coordinates] at (opamp.out) {};
    \end{circuitikz}
\end{document}

程式碼與您想要的程式碼僅相差兩個元素。如果您在聽完此解釋後卡在繪圖中，請在顯示您卡住的位置中提出新問題。在繪製circuitikz包文件時會有很大的幫助。

附錄（已編輯）： 讓我分兩步驟製作圖像：在第一個步驟中重複上面的圖像，然後在第二個步驟中添加電阻：

\documentclass[margin=3mm]{standalone}
\usepackage{circuitikz}

\begin{document}
    \begin{circuitikz}[every pin/.append style={align=left, text=blue}]
  \draw
  (0, 0) node[op amp] (opamp) {}
  (opamp.-) to[short,-o] ++(-1, 0)
  (opamp.-) to[short,*-] ++(0,1.5) coordinate (leftC)
            to[C]           (leftC -| opamp.out)
            to[short,-*]    (opamp.out)
            to[short,-o] ++ (0.5,0)
  (leftC)   to[short,*-] ++ (0,1)  coordinate (leftR) 
            to[R]           (leftR -| opamp.out)
            to[short,-*]    (leftC -| opamp.out)
   (opamp.+) -- ++ (0,-0.5) node[ground] {};
    \end{circuitikz}
\end{document}