![如何在數學模式下將註解拆分為多行](https://rvso.com/image/370287/%E5%A6%82%E4%BD%95%E5%9C%A8%E6%95%B8%E5%AD%B8%E6%A8%A1%E5%BC%8F%E4%B8%8B%E5%B0%87%E8%A8%BB%E8%A7%A3%E6%8B%86%E5%88%86%E7%82%BA%E5%A4%9A%E8%A1%8C.png)
在證明中,我想拆分左側的方程,並使用迷你頁在右側顯示圖片。然而,對於左側的其中一個方程,註釋太長,對於小型頁面來說太大。如何拆分評論使其跨越兩行?我知道可以用方程式來完成,但我不知道如何做以供評論。下面是我的程式碼和輸出:
\documentclass[a4paper, 11pt]{article}
\usepackage{fullpage}
\usepackage{amsmath,amsthm,amssymb}
\usepackage{mathtools,amsthm}
\begin{document}
\begin{proof}~\\
\begin{minipage}{0.5\textwidth}
\begin{align*}
AB = BD, & AC=CE &\qquad &\textrm{(midpoint of a side)}\\
\angle BAC &= \angle DAE&\qquad &\textrm{(common angle)}\\
\frac {AB}{AD} &= \frac {AC}{AE} = \frac 12\\
\therefore \Delta ABC &\sim \Delta ADE& \qquad &\textrm{(SAS; 1:2)}\\
\angle ABC & = \angle ADE& \qquad &\textrm{(matching $\angle$ 's, $\Delta ABC \sim\Delta ADE$)}\\
\therefore BC &\| DE& \qquad &\textrm{(corresponding $\angle$'s are $=$)}\\
\frac{BC}{DE} &=\frac 12 & \qquad & \textrm{(matching sides in the same ratio,$\Delta ABC \sim\Delta ADE$)}\\
\therefore BC &= \frac 12 DE && \qedhere
\end{align*}
\end{minipage}
\hfill
\begin{minipage}{0.4\textwidth}
\includegraphics[width=0.9\textwidth,keepaspectratio]{proof.PNG}
\end{minipage}
\end{proof}
\end{document}
如上圖所示,我想在垂直線上分割註釋,並將其放置在與其他註釋對齊的下一行。
謝謝你的幫忙!
答案1
這是另一種方法,使用 alignat*
代替align*
,aligned
來獲得最長的註釋,並adjustbox
控製影像的垂直對齊方式。請注意amsmath
,如果加載,則不必加載mathtools
。我還稍微簡化了您的程式碼(無需\qquad
在每一行添加):
\documentclass[a4paper, 11pt]{article}
\usepackage{fullpage}
\usepackage{showframe}
\renewcommand{\ShowFrameLinethickness} {0.3pt}
\usepackage[demo]{adjustbox}
\usepackage{amssymb}
\usepackage{mathtools,amsthm}
\begin{document}
\begin{proof}~\\[-3ex]
\begin{minipage}[t]{0.5\textwidth}
\begin{alignat*}{2}
AB = BD&,\; AC=CE & \quad &\textrm{(midpoint of a side)}\\
\angle BAC &= \angle DAE& &\textrm{(common angle)}\\
\frac {AB}{AD} &= \frac {AC}{AE} = \frac 12 & & \\
\therefore \Delta ABC &\sim \Delta ADE&&\textrm{(SAS; 1:2)}\\
\angle ABC & = \angle ADE& &\textrm{(matching $\angle$ 's, $\Delta ABC \sim\Delta ADE$)}\\
\therefore BC &\| DE& &\textrm{(corresponding $\angle$'s are $=$)}\\
\frac{BC}{DE} &=\frac 12 & & \begin{aligned} & \textrm{(matching sides in the same ratio,}\\%
& \Delta ABC \sim\Delta ADE)\end{aligned}\\
\therefore BC &= \frac 12 DE & & \qedhere
\end{alignat*}
\end{minipage}
\hfill
\begin{minipage}[t]{0.4\textwidth}
\smash{\adjincludegraphics[width=0.9\linewidth,valign = t, raise = -.25\totalheight]{proof.PNG}}
\end{minipage}
\end{proof}
\end{document}
答案2
以下解決方案使用\parbox
指令允許在三個解釋性註解中換行。每個的寬度\parbox
設定為字串的長度(midpoint of a side)
。
\documentclass[a4paper,11pt,draft]{article} % remove 'draft' in real doc.
\usepackage{fullpage}
\usepackage{amssymb,mathtools,amsthm}
\newlength\mylength
\settowidth\mylength{(midpoint of a side)}
\newcommand{\mybox}[1]{\parbox[t]{\mylength}{\raggedright #1}}
\begin{document}
\begin{proof}~\newline
\begin{minipage}{0.55\textwidth}
\begin{align*}
AB = BD, & AC=CE &\quad &
\text{(midpoint of a side)}\\
\angle BAC &= \angle DAE &&
\text{(common $\angle$)}\\
\frac {AB}{AD} &= \frac {AC}{AE} = \frac 12\\
\therefore \Delta ABC &\sim \Delta ADE &&
\text{(SAS; 1:2)}\\
\angle ABC & = \angle ADE &&
\mybox{(matching $\angle$\,s,
$\Delta ABC \sim\Delta ADE$)}\\
\therefore BC \,&\|\,DE &&
\mybox{(corresponding $\angle$\,s
are $=$)}\\
\frac{BC}{DE} &=\frac 12 &&
\mybox{(matching sides in the same ratio,
$\Delta ABC \sim\Delta ADE$)}\\
\therefore BC &= \frac 12 DE && \qedhere
\end{align*}
\end{minipage}%
\hfill
\begin{minipage}{0.4\textwidth}
\includegraphics[width=\textwidth,keepaspectratio]{proof.PNG}
\end{minipage}
\end{proof}
\end{document}