☰

如何將 tikz 中的直角三角形定義為節點

tag-icon • tag-icon tikz-styles
如何將 tikz 中的直角三角形定義為節點

為了得到一個等邊三角形，我使用

\tikzstyle{triangle} = [fill=green!20, regular polygon, regular polygon sides=3]

但我正在努力定義直角三角形的 tikz 節點

我想做這樣的事情

\tikzstyle{anytriangle} = [draw, A--B--C--A]

進而

\begin{tikzpicture}[ auto, node distance=4em]

% Gridline
\draw [step=0.5cm,draw=gray] (-4,-4) grid (4,4);

\coordinate (A) at (0,0);
\coordinate (B) at (4,0);
\coordinate (C) at (0,4);

\node [anytriangle] {};

\end{tikzpicture}

但我收到錯誤：未知座標 A

答案1

也許是這樣的（但我必須承認我並不完全理解你想要實現的目標）：

\documentclass[tikz]{standalone}

\begin{document}

\tikzset{triangle/.append style={fill=green!20, regular polygon, regular polygon sides=3},
         anytriangle/.append style={draw, append after command={ \pgfextra{ \draw (A) -- (B) -- (C) -- (A); } }}}

\begin{tikzpicture}[auto, node distance=4em]

% Gridline
\draw [step=0.5cm,draw=gray] (-4,-4) grid (4,4);

\coordinate (A) at (0,0);
\coordinate (B) at (4,0);
\coordinate (C) at (0,4);

\node [anytriangle] {};

\end{tikzpicture}

\end{document}

答案2

您可以使用isosceles triangle帶有 的形狀apex angle=90。

\documentclass[tikz,border=2mm]{standalone} 
\usetikzlibrary{positioning, shapes.geometric}

\begin{document}
\begin{tikzpicture}[
    right angle triangle/.style={
        isosceles triangle,
        isosceles triangle apex angle=90},
    every node/.style={right angle triangle, 
        draw, inner sep=0pt,
        anchor=left corner,
        shape border rotate=90},
    paint/.style={draw=#1!75, fill=#1!20}
    ]


\draw[help lines] grid (5,2);

\foreach \a/\c in {1.5/blue, 1/green, 0.5/red}{
    \node[paint=\c, minimum width=\a cm] at (0,0) {};
    \node[paint=\c, minimum height=\a cm] at (2,0) {};
    }

\begin{scope}[yshift=-3cm,
    every node/.style={
        right angle triangle,
        isosceles triangle stretches=false,
        draw, inner sep=0pt,
        minimum height=1cm,
        anchor=apex}
    ]
\draw[help lines] (0,0) grid (2,2);
\foreach \a/\c in {45/blue, 135/green,225/red,315/orange}
     \node[paint=\c, 
        shape border rotate=\a] at (1,1) {};

\end{scope}
\end{tikzpicture}
\end{document}

在此輸入影像描述

答案3

從你的問題我明白，你在尋找這個：

在此輸入影像描述

我用別針標記了座標A、B和C（你可以看到，那個三角形與它完美匹配。

對於上面的圖像我建議兩種解決方案：

\documentclass[tikz, margin=3mm]{standalone}
\usetikzlibrary{shapes.geometric}

\begin{document}
    \begin{tikzpicture}[
trian/.style = {isosceles triangle,
     isosceles triangle apex angle=90,
     minimum size=4cm/sqrt(2), inner sep=0pt,
     anchor=east,rotate=-135,
     draw, fill=green!20}
                        ]
\coordinate[pin=below:A] (A) at (0,0);
\coordinate[pin=below:B] (B) at (4,0);
\coordinate[pin=C]       (C) at (0,4);
%
\node [trian] {};
    \end{tikzpicture}
\end{document}
  • 帶有小圖片（\pic），它不是節點，但具有相似的特徵（從可能的節點錨點我只定義了三個角為-a，-b和 ˙-c` ）：

\documentclass[tikz, margin=3mm]{standalone}

\begin{document}
    \begin{tikzpicture}[
trian/.pic = {
    \draw [fill=green!20]
        (0,0) coordinate (-a) --
        (4,0) coordinate (-b) --
        (0,4) coordinate (-c) -- cycle;
            }
                        ]
\coordinate[pin=below:A] (A) at (0,0);
\coordinate[pin=below:B] (B) at (4,0);
\coordinate[pin=C]       (C) at (0,4);
%
\pic[above right] at (A) {trian};
    \end{tikzpicture}
\end{document}

在這兩種情況下結果是相同的

相關內容