☰

尋找我的 tikzpic 程式碼的有效替代方案

tag-icon • tag-icon tikz-pic
尋找我的 tikzpic 程式碼的有效替代方案

我有一張包含重複元素的 tikzpicture 。現在我正在單獨定義它們。但我想要一個程式碼來定義一個模板三角形，其尺寸由我控制（就像我在範例中透過 p1,q1 所做的那樣）並使用旋轉來控制方向。

（請注意，此範例僅用於說明目的。我想使用其他形狀來建立更複雜的圖案，並希望避免使用更多庫）

我的程式碼：

\documentclass[tikz]{standalone} 
\usetikzlibrary{positioning,graphicx,calc}

\begin{document}
\begin{tikzpicture}

% Gridline

\coordinate (x1) at (-4,+0);
\coordinate (x2) at (+0,-4);
\coordinate (x3) at (+4,+0);
\coordinate (x4) at (+0,+4);

\coordinate (k) at (+0,+0);
\coordinate (p1) at (+4,+0);  %Triangle variable 
\coordinate (q1) at (+0,+4);  %Triangle variable

%---------------------------------

\coordinate (G1) at ($(x1)+(x2)$);
\coordinate (G2) at ($(x3)+(x4)$);

\draw [step=0.5cm,draw=gray] (G1) grid (G2);
%\draw [fill=yellow,opacity=0.5] ($(x1)+(x4)$)--(G2)--($(x3)+(x2)$)--(G1);

%---------------------------------
\coordinate (a1) at (k);
\coordinate (b1) at (p1);
\coordinate (c1) at (q1);

\coordinate (C1) at ($(k)$);
\coordinate (B1) at ($(C1)+(k)+(c1)$);
\coordinate (A1) at ($(B1)-(b1)$);
\draw [fill=black] (A1)--(B1)--(C1)--cycle;

\coordinate (A2) at ($(C1)$);
\coordinate (B2) at ($(A2)+(k)-(c1)$);
\coordinate (C2) at ($(B2)+(k)+(b1)$);
\draw [fill=red] (A2)--(B2)--(C2)--cycle;

\coordinate (A3) at ($(C1)$);
\coordinate (B3) at ($(A3)+(k)-(b1)$);
\coordinate (C3) at ($(B3)+(k)-(c1)$);
\draw [fill=green] (A3)--(B3)--(C3)--cycle;

\coordinate (A4) at ($(C1)$);
\coordinate (B4) at ($(A4)+(k)+(b1)$);
\coordinate (C4) at ($(B4)+(k)+(c1)$);
\draw [fill=blue] (A4)--(B4)--(C4)--cycle;

%---------------------------------
\draw[white,opacity=1] (current bounding box.south west) rectangle 
        (current bounding box.north east);
\end{tikzpicture}
\end{document}

輸出 在此輸入影像描述

第二個例子

\documentclass[tikz]{standalone} 
\usetikzlibrary{positioning,calc,graphics}

\begin{document}
\begin{tikzpicture}

% Gridline

\coordinate (x1) at (-4,+0);
\coordinate (x2) at (+0,-4);
\coordinate (x3) at (+4,+0);
\coordinate (x4) at (+0,+4);

\coordinate (k) at (+0,+0);
\coordinate (p1) at (+1.75,+0); 
\coordinate (q1) at (+0,+1.75); 
\coordinate (r1) at (+4.5,+0); 
\coordinate (s1) at (+0,+4.5); 

%---------------------------------

\coordinate (G1) at ($(x1)+(x2)$);
\coordinate (G2) at ($(x3)+(x4)$);

\draw [step=0.5cm,draw=none] (G1) grid (G2);
\draw [fill=yellow] ($(x1)+(x4)$)--(G2)--($(x3)+(x2)$)--(G1);

%---------------------------------
\coordinate (a1) at (k);
\coordinate (b1) at (p1);
\coordinate (c1) at (q1);

\coordinate (A1) at ($(x1)+(x4)$);
\coordinate (B1) at ($(A1)+(k)+(b1)$);
\coordinate (C1) at ($(B1)+(k)-(c1)$);
\draw [fill=black] (A1)--(B1)--(C1)--cycle;

\coordinate (b2) at (r1);
\coordinate (c2) at (c1);

\coordinate (A2) at (B1);
\coordinate (B2) at ($(A2)+(k)+(b2)$);
\coordinate (C2) at ($(B2)+(a1)-(c2)$);
\coordinate (D2) at (C1);
\draw [fill=black] (A2)--(B2)--(C2)--(D2)--cycle;

\coordinate (b3) at (b1);
\coordinate (c3) at (c1);

\coordinate (A3) at (B2);
\coordinate (B3) at ($(A3)+(k)+(b3)$);
\coordinate (C3) at ($(B3)+(a1)-(c2)$);
\coordinate (D3) at (C2);
\draw [fill=black] (A3)--(B3)--(C3)--(D3)--cycle;

\coordinate (b4) at (b1);
\coordinate (c4) at (s1);

\coordinate (A4) at (C2);
\coordinate (B4) at ($(A4)+(k)+(b4)$);
\coordinate (C4) at ($(B4)+(k)-(c4)$);
\coordinate (D4) at ($(C4)+(k)-(b4)$);
\draw [fill=black] (A4)--(B4)--(C4)--(D4)--cycle;

\coordinate (A5) at (D4);
\coordinate (B5) at ($(A5)+(k)+(b1)$);
\coordinate (C5) at ($(B5)+(k)-(c1)$);
\draw [fill=black] (A5)--(B5)--(C5)--cycle;

\coordinate (A6) at (C1);
\coordinate (B6) at ($(C1)+(k)-(s1)$);
\coordinate (C6) at (A5);
\draw [fill=black] (A6)--(B6)--(C6)--cycle;

%---------------------------------

\draw[white,opacity=1] (current bounding box.south west) rectangle 
        (current bounding box.north east);

\end{tikzpicture}
\end{document}

輸出 在此輸入影像描述

答案1

也許不是處理這個問題的最佳tikz風格，但即使沒有示例中缺少的庫也可以工作。

\documentclass[tikz]{standalone} 

\newcommand{\tri}[1]{%
    \draw[#1] (0,0) -- (4,0) -- (4,4) -- cycle;
}

\begin{document}
\begin{tikzpicture}

\tri{fill=black}
\tri{fill=red,rotate=90}
\tri{fill=green,rotate=180}
\tri{fill=blue,rotate=270}

\end{tikzpicture}
\end{document}

答案2

也許你可以考慮使用pics。您可以使用它們來定義複雜的 tikz 圖形並重複使用它。可以使用參數定義它們，甚至可以在最終繪製它們時更改某些屬性。

以下程式碼顯示了您的圖形的兩個範例。mytriangle定義一個以一個頂點為原點的正方三角形，有三個參數：填滿顏色和兩側長度。第二個範例定義了「複雜」影像。

\documentclass[tikz, border=2mm]{standalone} 
\usetikzlibrary{positioning}

\tikzset{
    pics/mytriangle/.style n args={3}{
        code={
            \fill[#1] (0,0)--++(0,#2)--++(#3,0)--cycle;
        }
    },
    myfigure/.pic={
        \fill[black] (0,0) rectangle ++(-1,-1);
        \fill[blue] (-1,0) rectangle ++(-3,-1);
        \fill[green] (-4,0)-- ++(-1,0)--++(1,-1)--cycle;
        \fill[blue] (0,-1) rectangle ++(-1,-3);
        \fill[green] (0,-4)-- ++(-1,0)--++(1,-1)--cycle;
        \fill[red] (-4,-1)-- ++(0,-3)--++(3,0)--cycle;
    }
}

\begin{document}
\begin{tikzpicture}
\foreach \a/\c in {0/red,90/green,180/blue,270/black}
    \pic[rotate=\a] at (0,0) {mytriangle={\c}{2}{2}};

\begin{scope}[xshift=4cm]
\foreach \a/\c in {0/red,90/green,180/blue,270/black}
    \pic[rotate=\a] at (0,0) {mytriangle={\c}{1}{1.8}};
\end{scope}

\begin{scope}[xshift=8cm]
\foreach \a/\c in {0/red,90/green,180/blue,270/black}
    \pic[rotate=\a] at (0,0) {mytriangle={\c}{1.5}{1}};
\end{scope}

\end{tikzpicture}

\begin{tikzpicture}
\foreach \a in {30,120,210,300}
    \pic[rotate=\a] at (\a:-1cm) {myfigure};
\end{tikzpicture}
\end{document}

在此輸入影像描述

在此輸入影像描述

答案3

\documentclass[tikz]{standalone} 
\usetikzlibrary{positioning,calc}

\begin{document}
\begin{tikzpicture}


\coordinate (O) at (0,0);
\foreach \X/\Col in{1/red,2/green,3/black,4/blue}
{
\coordinate (x\X) at ({-90*\X}:4);
\draw[fill=\Col] (x\X) -- +({-90*(\X-1)}:4) -- (O) -- cycle;
}

%Gridline
\coordinate (G1) at ($(x1)+(x2)$);
\coordinate (G2) at ($(x3)+(x4)$);
\draw [step=0.5cm,draw=gray] (G1) grid (G2);
\draw[white,opacity=1] (current bounding box.south west) rectangle 
        (current bounding box.north east);
\end{tikzpicture}
\end{document}

相關內容