
我有無理座標的點,因為我混合了極座標和直角座標。我想指定一個座標作為一個事物的 x 值和另一個事物的 y 值。
在這個具體範例中,我希望左側的兩條線具有相同的左端點。
\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}
\coordinate (left) at (155:2);
\coordinate (top) at (65:2);
\coordinate (bottom) at (245:2);
\coordinate (right) at (335:2);
\coordinate (leftEdge) at ($ (left) + (-2,0) $);
\coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
\path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
\path[draw=blue] (left) -- (leftEdge);
\path[draw=black] (bottom) -- (bottomEdge);
\path[draw=red] (bottom) -- ++(-2,0);
\end{tikzpicture}
\end{document}
我認為有一種方法可以用類似的方法來做到這一點(leftEdge.x,bottom.y)
,但我沒有成功地讓它發揮作用。
如何讓紅色邊緣與藍色邊緣一樣遠?
答案1
在您的範例中,您所需要做的就是說\path[draw=red] (bottom) -- (bottom-|leftEdge);
.這個很棒的答案為您提供了對該語法的非常有效的討論。
\documentclass[tikz]{standalone}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}
\coordinate (left) at (155:2);
\coordinate (top) at (65:2);
\coordinate (bottom) at (245:2);
\coordinate (right) at (335:2);
\coordinate (leftEdge) at ($ (left) + (-2,0) $);
\coordinate (bottomEdge) at ($ (bottom) + (0,-2) $);
\path[draw=black] (left) -- (top) -- (right) -- (bottom) -- cycle;
\path[draw=blue] (left) -- (leftEdge);
\path[draw=black] (bottom) -- (bottomEdge);
\path[draw=red] (bottom) -- (bottom-|leftEdge);
\end{tikzpicture}
\end{document}